NCERT Solutions for class 10 Maths Chapter 13 exercise 13.5, 13.4, 13.3, 13.2 & 13.1 (प्रश्नावली 13.1, 13.2, 13.3, 13.4 & प्रश्नावली 13.5) of Surface areas and volumes for UP Board 2018 onward and CBSE in Hindi and English medium free in PDF form to download. Download NCERT Books for class 10 all subjects, Course A and Course B in PDF form. Previous year CBSE Exam question, important questions for practice and test series based on different difficulty levels will be uploaded. To download NCERT solutions of other subjects, click here.
NCERT Solutions for class 10 Maths Chapter 13
Class 10 Maths – Surface Areas and Volumes Solutions
- Exercise 13.1
- Exercise 13.2
- Exercise 13.3
- Exercise 13.4
- Exercise 13.5
- NCERT Books in Hindi & English Medium
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Previous Years Questions
One mark questions
- Volume and surface area of a solid hemisphere are numerically equal. What is the diameter of hemisphere? [CBSE 2017]
Three marks questions
- A metallic solid sphere of radius 10.5 cm is melted and recast into smaller solid cones, each of radius 3.5 cm and height 3 cm. How many cones will be made? [CBSE 2017]
Four marks questions
- In a hospital used water is collected in a cylindrical tank of diameter 2 m and height 5 m. After recycling, this water is used to irrigate a park of hospital whose length is 25 m and breadth is 20 m. If the tank is filled completely then what will be the height of standing water used for irrigation the park. Write your views on recycling of water. [CBSE 2017]
- The height of a cone is 30 cm. From its topside a small cone is cut by a plane parallel to its base. If volume of smaller cone is 1/27 of the given cone, then at what height it is cut from its base? [CBSE 2017]
- The height of a cone is 10 cm. The cone is divided into two parts using a plane parallel to its base at the middle of its height. Find the ratio of the volumes of the two parts. [CBSE 2017]
Objective of Surface areas and volumes
To identify situations where there is a need of finding surface area and where there is a need of finding volume of a solid figure and to find the surface areas & volumes of cuboids, cubes, cylinders, cones spheres and hemispheres, using their respective formulae. To solve some problems related to daily life situations involving surface areas and volumes of above solid figures.
In this chapter, we will deal with problems such as finding the area of sheet to covers a solid body, area of an object which is combination of two objects, finding the number of one object, required for creating another different object, finding the cost of ploughing a given field at a given rate, finding the cost of constructing a water tank with a particular capacity, finding area & volume of frustum (Frustum is a Latin word meaning ‘piece cut off’ and its plural form is ‘Frusta’) and the conversion of one solid into another solid on the basis of volume and so on.
For solving above type of problems, we need to find the perimeters and areas of simple closed plane figures (figure which lie in a plane) and surface areas and volumes of solid figures (figures which do not lie wholly in a plane). You are already familiar with the concepts of perimeters, areas, surface areas and volumes. In this chapter, we will study these in details.
Archimedes of Syracuse, Sicily, is remembered as the greatest Greek mathematician of the ancient era. He contributed significantly in geometry regarding the areas of plane figures and the areas and volumes of solid figures. He proved that the volume of a sphere is equal to two-third the volume of a circumscribed cylinder.