NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2 Areas Related to Circles PDF in Hindi Medium and English Medium or View in Video Format for English and Hindi medium students. All the NCERT Solutions and CBSE Offline Apps have been updated for CBSE exams 2019-20.

Class 10: | Maths – गणित |

Chapter 12: | Areas Related to Circles (Exercise 12.2) |

## NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

### Class 10 Maths Chapter 12 Exercise 12.2 Sols in English

NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2 Areas Related to Circles in English medium free for all DOWNLOAD or STUDY ONLINE. Click here to jump Class 10 Maths Chapter 12 for other exercises or for PDF whether to download or online study. CLICK HERE for Hindi Medium or View in Video Format Solutions.

### 10 Maths Chapter 12 Exercise 12.2 Sols in Video

NCERT Solutions for class 10 Maths Exercise 12.2 in video format with complete description.

### Class 10 Maths Chapter 12 Exercise 12.2 Sols in Hindi

NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2 वृत्तों से संबंधित क्षेत्रफल in Hindi medium for all the students of different boards (CBSE, MP Board, UP Board, Bihar Board, NIOS, Uttarakhand and others), whose study material is related to NCERT Books. Click here to move Class 10 Maths Chapter 12 for other exercises whether download or online study. Go back to English Medium or View in Video Format Solutions.

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#### About 10 Maths Exercise 12.2

In Exercise 12.2, the questions are based on area of sectors as well as area of segments. Quadrant is a sector with central angle 90. If it is mention that the area of segment is to find, then we have to find area of minor segment. In Question 3, first we have to find angle formed in 5 minutes by minute hand and then apply the formula of area of sector. The exercise 12.2 is quite easy to understand and solve.

##### Area of Segment

To obtain the area of segment, first of all find the area of sector and then area of triangle formed on the chord of sector. Subtracting the area of triangle from area of sector, we will obtain the area of minor segment. If we subtract this area from the area of circle, the area of major segment can be obtained.

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