NCERT Solutions for Class 8 Maths Ganita Prakash Part 2 Chapter 1 Fractions in Disguise – Exercises Question Answers for Session 2026-27. Every percentage is a fraction in disguise: a fraction with 100 as its denominator.

NCERT Class 8 Maths Ganita Prakash Part 2 Chapter 1 Solutions

Class 8 Maths Ganita Prakash Part 2 Chapter 1, builds on this idea, showing how to move between fractions, decimals and percentages, find a percentage of a quantity, make sense of values above 100% and calculate percentage increase or decrease. It then applies these skills to profit and loss, discounts, GST, simple and compound interest with depreciation. Below, you will find step-by-step NCERT solutions to all the Figure it Out questions, with every calculation shown clearly, so you can check your homework and revise before exams.
Get here the Solutions and Answers of Figure it Out at Page 3.

Page 3 – Figure it Out

1. Express the following fractions as percentages.

(i) 3/5
(ii) 7/14
(iii) 9/20
(iv) 72/150
(v) 1/3
(vi) 5/11
Answer:
To express a fraction as a percentage, we multiply it by 100 and put the % sign.

(i) 3/5
Required percentage = (3/5 ร— 100)%
= (3 ร— 20)%
= 60%
โˆด 3/5 = 60%.

(ii) 7/14
On simplifying, we get,
7/14 = 1/2
Required percentage = (1/2 ร— 100)%
= (1 ร— 50)%
= 50%
โˆด 7/14 = 50%.

(iii) 9/20
Required percentage = (9/20 ร— 100)%
= (9 ร— 5)%
= 45%
โˆด 9/20 = 45%.

(iv) 72/150
On simplifying, we get,
72/150 = 12/25
Required percentage = (12/25 ร— 100)%
= (12 ร— 4)%
= 48%
โˆด 72/150 = 48%.

(v) 1/3
Required percentage = (1/3 ร— 100)%
= (100/3)%
= 33โ…“%
โˆด 1/3 = 33โ…“%.

(vi) 5/11
Required percentage = (5/11 ร— 100)%
= (500/11)%
On dividing 500 by 11, we get quotient 45 and remainder 5.
โˆด Required percentage = (45 + 5/11)%
= 45 5/11%
Hence, 5/11 = 45 5/11%.

2. Nandini has 25 marbles, of which 15 are white. What percentage of her marbles are white?

(i) 10%
(ii) 15%
(iii) 25%
(iv) 60%
(v) 40%
(vi) None of these
Answer:
Total number of marbles = 25
Number of white marbles = 15
Percentage of white marbles = (Number of white marbles / Total number of marbles ร— 100)%
= (15/25 ร— 100)%
= (15 ร— 4)%
= 60%
Hence, 60% of Nandiniโ€™s marbles are white.
The correct option is (iv) 60%.

3. In a school, 15 of the 80 students come to school by walking. What percentage of the students come by walking?

Answer:
Total number of students = 80
Number of students who come by walking = 15
Percentage of students who come by walking
= (Number of students who come by walking / Total number of students ร— 100)%
= (15/80 ร— 100)%
= (1500/80)%
= 18.75%
Hence, 18.75% of the students come to school by walking.

4. A group of friends is participating in a long-distance run. The positions of each of them after 15 minutes are shown in the following picture. Match (among the given options) what percentage of the race each of them has approximately completed.

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 3 - Figure it Out

Answer:
From the positions shown in the picture, we get the following approximate matches among the given options:
A is between one-fourth and one-half of the race. The closest given option is 38%.
B is a little beyond halfway. The closest given option is 55%.
C is about three-fourths of the way through the race. The closest given option is 72%.
D is very close to the finish. The closest given option is 93%.
Hence, the matches are:
A โ†’ 38%
B โ†’ 55%
C โ†’ 72%
D โ†’ 93%

5. Pairs of quantities are shown below. Identify and write appropriate symbols โ€˜>โ€™, โ€˜<โ€™, โ€˜=โ€™ in the blanks. Try to do it without calculations.

(i) 50% ____ 5%
(ii) 5/10 ____ 50%
(iii) 3/11 ____ 61%
(iv) 30% ____ 1/3
Answer:
(i) 50% > 5%
Fifty out of a hundred is more than five out of a hundred.
โˆด 50% > 5%.

(ii) 5/10 = 50%
Both 5/10 and 50% represent one-half of a whole.
โˆด 5/10 = 50%.

(iii) 3/11 < 61%
3/11 is less than one-half, whereas 61% is greater than one-half.
โˆด 3/11 < 61%.

(iv) 30% < 1/3
From Question 1, we know that 1/3 = 33โ…“%, which is greater than 30%.
โˆด 30% < 1/3.

Get here the Solutions and Answers of Figure it Out at Page 12.

Page 12 – Figure it Out

Estimate first before making any computations to solve the following questions. Try different methods including mental computations.

1. Find the missing numbers. The first problem has been worked out.

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 12 - Figure it Out Question 1

Answer:
(i) The bar has 5 equal parts.
Each part represents 100% รท 5 = 20%.
The whole bar represents 75.
Value of 4 parts = (4/5) ร— 75 = 60.

(ii) The marked length on the right is a little more than half the bar, so its value should be a little more than 45.
The bar has 10 equal parts.
Each part represents 100% รท 10 = 10%.
The whole bar represents 90.
Value of 1 part = 90 รท 10 = 9.
Value of 6 parts = 6 ร— 9 = 54.
โˆด The missing numbers are 10% and 54.

(iii) The marked length on the right is between half and the whole bar, so its value should be between 70 and 140.
The bar has 4 equal parts.
Each part represents 100% รท 4 = 25%.
The whole bar represents 140.
Value of 1 part = 140 รท 4 = 35.
Value of 3 parts = 3 ร— 35 = 105.
โˆด The missing numbers are 25% and 105.

2. Find the value of the following and also draw their bar models.

(i) 25% of 160
(ii) 16% of 250
(iii) 62% of 360
(iv) 140% of 40
(v) 1% of 1 hour
(vi) 7% of 10 kg
Answer:
(i) 25% of 160
25% is one-fourth, so the answer should be 40.
25% of 160 = (25/100) ร— 160
= 160 รท 4
= 40.

(ii) 16% of 250
15% of 250 is 37.5, so 16% should be a little more, about 40.
10% of 250 = 25.
5% of 250 = 12.5.
1% of 250 = 2.5.
โˆด 16% of 250 = 25 + 12.5 + 2.5
= 40.

(iii) 62% of 360
60% of 360 is 216, so 62% should be a little more, about 220.
62% of 360 = (62/100) ร— 360
= 223.2.

(iv) 140% of 40
140% is more than 100% and less than 150%, so the answer should be between 40 and 60.
100% of 40 = 40.
40% of 40 = (40/100) ร— 40 = 16.
โˆด 140% of 40 = 40 + 16
= 56.

(v) 1% of 1 hour
1% of an hour should be less than 1 minute.
1 hour = 60 minutes = 3600 seconds.
1% of 1 hour = (1/100) ร— 3600 seconds
= 36 seconds.

(vi) 7% of 10 kg
5% of 10 kg is 0.5 kg and 10% is 1 kg, so the answer should be between 0.5 kg and 1 kg.
7% of 10 kg = (7/100) ร— 10 kg
= 0.7 kg
= 700 g.
The bar models are shown below.

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 12 - Figure it Out Question 2 Answer

3. Surya made 60 ml of deep orange paint, how much red paint did he use if red paint made up 3/4 of the deep orange paint?

Answer:
3/4 is more than 1/2 and less than 1, so the quantity of red paint should be between 30 ml and 60 ml.
Quantity of red paint = (3/4) ร— 60 ml
= 3 ร— 15 ml
= 45 ml.
โˆด Surya used 45 ml of red paint.

4. Pairs of quantities are shown below. Identify and write appropriate symbols โ€˜>โ€™, โ€˜<โ€™, โ€˜=โ€™ in the boxes. Visualising or estimating can help. Compute only if necessary or for verification.

(i) 50% of 510 โ–ก 50% of 515
(ii) 37% of 148 โ–ก 73% of 148
(iii) 29% of 43 โ–ก 92% of 110
(iv) 30% of 40 โ–ก 40% of 50
(v) 45% of 200 โ–ก 10% of 490
(vi) 30% of 80 โ–ก 24% of 64
Answer:
(i) 50% of 510 < 50% of 515.
Half of a smaller number is smaller than half of a larger number.

(ii) 37% of 148 < 73% of 148.
For the same whole, 37% is less than 73%.

(iii) 29% of 43 < 92% of 110.
29% of 43 is less than 43.
92% of 110 is more than half of 110, which is 55.
Therefore, the first quantity is smaller.

(iv) 30% of 40 < 40% of 50.
Both the percentage and the whole are smaller in the first quantity.
For verification:
30% of 40 = 12.
40% of 50 = 20.
Since 12 < 20, the required symbol is <. (v) 45% of 200 > 10% of 490.
40% of 200 is already 80, while 10% of 490 is 49.
Therefore, 45% of 200 is greater than 10% of 490.

(vi) 30% of 80 > 24% of 64.
Both the percentage and the whole are larger in the first quantity.
For verification:
30% of 80 = 24.
24% of 64 = 15.36.
Since 24 > 15.36, the required symbol is >.

5. Fill in the blanks appropriately:

(i) 30% of k is 70, 60% of k is _____, 90% of k is _____, 120% of k is ______.
(ii) 100% of m is 215, 10% of m is _____, 1% of m is ______, 6% of m is ______.
(iii) 90% of n is 270, 9% of n is ______, 18% of n is _____, 100% of n is ______.
(iv) Make 2 more such questions and challenge your peers.
Answer:
(i) 60%, 90% and 120% are 2, 3 and 4 times 30%, respectively.
60% of k = 2 ร— 70 = 140.
90% of k = 3 ร— 70 = 210.
120% of k = 4 ร— 70 = 280.
โˆด The blanks are 140, 210 and 280.

(ii) 10% is one-tenth of 100%, and 1% is one-hundredth of 100%.
10% of m = 215 รท 10 = 21.5.
1% of m = 215 รท 100 = 2.15.
6% of m = 6 ร— 2.15 = 12.9.
โˆด The blanks are 21.5, 2.15 and 12.9.

(iii) 9% is one-tenth of 90%, and 18% is twice 9%.
9% of n = 270 รท 10 = 27.
18% of n = 2 ร— 27 = 54.
1% of n = 27 รท 9 = 3.
100% of n = 100 ร— 3 = 300.
โˆด The blanks are 27, 54 and 300.

(iv) Two similar questions are:
(a) 20% of p is 50, 40% of p is _____, 60% of p is _____, 100% of p is _____.
40% of p = 2 ร— 50 = 100.
60% of p = 3 ร— 50 = 150.
100% of p = 5 ร— 50 = 250.
โˆด The blanks are 100, 150 and 250.
(b) 100% of q is 360, 10% of q is _____, 5% of q is _____, 15% of q is _____.
10% of q = 360 รท 10 = 36.
5% of q = 36 รท 2 = 18.
15% of q = 36 + 18 = 54.
โˆด The blanks are 36, 18 and 54.

6. Fill in the blanks:

(i) 3 is ____ % of 300.
(ii) _____ is 40% of 4.
(iii) 40 is 80% of _____.
Answer:
(i) 3 is a very small part of 300, so the required percentage should be small.
Required percentage = (3/300 ร— 100)%
= 1%.
โˆด 3 is 1% of 300.

(ii) 40% is between one-fourth and one-half, so 40% of 4 should be between 1 and 2.
40% of 4 = (40/100) ร— 4
= 1.6.
โˆด 1.6 is 40% of 4.

(iii) Since 80% is less than 100%, the whole should be greater than 40.
80% of the number = 40.
20% of the number = 40 รท 4 = 10.
100% of the number = 5 ร— 10 = 50.
โˆด 40 is 80% of 50.

7. Is 10% of a day longer than 1% of a week? Create such questions and challenge your peers.

Answer:
A week has 7 days, so 1% of a week is the same as 7% of a day.
Since 10% > 7%, 10% of a day should be longer.
1 day = 24 hours.
1 week = 7 ร— 24 = 168 hours.
10% of a day = (10/100) ร— 24 hours
= 2.4 hours
= 144 minutes.
1% of a week = (1/100) ร— 168 hours
= 1.68 hours
= 100.8 minutes.
Since 144 minutes > 100.8 minutes, 10% of a day is longer than 1% of a week.
Two similar questions are:

(a) Is 25% of an hour longer than 10% of 2 hours?
25% of an hour = (25/100) ร— 60 minutes = 15 minutes.
10% of 2 hours = (10/100) ร— 120 minutes = 12 minutes.
Since 15 minutes > 12 minutes, 25% of an hour is longer.

(b) Is 20% of a day longer than 5% of 4 days?
20% of a day = (20/100) ร— 24 hours = 4.8 hours.
5% of 4 days = (5/100) ร— 96 hours = 4.8 hours.
Both are equal. Therefore, 20% of a day is not longer than 5% of 4 days.

8. Mariamโ€™s farm has a peculiar bull. One day she gave the bull 2 units of fodder and the bull ate 1 unit. The next day, she gave the bull 3 units of fodder and the bull ate 2 units. The day after, she gave the bull 4 units and the bull ate 3 units. This continued, and on the 99th day she gave the bull 100 units and the bull ate 99 units. Represent these quantities as percentages. This task can be distributed among the class. What do you observe?

Answer:
The bull eats half of the fodder on the first day. After that, it eats more than half and the percentage should get closer to 100%.
Percentage eaten = (Fodder eaten รท Fodder offered) ร— 100%.
Day 1: Percentage eaten = (1/2 ร— 100)% = 50%.
Day 2: Percentage eaten = (2/3 ร— 100)% = 66โ…”%.
Day 3: Percentage eaten = (3/4 ร— 100)% = 75%.
Day 4: Percentage eaten = (4/5 ร— 100)% = 80%.
On day n, n + 1 units are offered and n units are eaten.
โˆด Percentage eaten on day n = (n/(n + 1) ร— 100)%.

The daily percentages are shown below. Values are rounded to two decimal places wherever needed.
Day| Eaten Day | Eaten Day | Eaten
1 | 50.00% 34 | 97.14% 67 | 98.53%
2 | 66.67% 35 | 97.22% 68 | 98.55%
3 | 75.00% 36 | 97.30% 69 | 98.57%
4 | 80.00% 37 | 97.37% 70 | 98.59%
5 | 83.33% 38 | 97.44% 71 | 98.61%
6 | 85.71% 39 | 97.50% 72 | 98.63%
7 | 87.50% 40 | 97.56% 73 | 98.65%
8 | 88.89% 41 | 97.62% 74 | 98.67%
9 | 90.00% 42 | 97.67% 75 | 98.68%
10 | 90.91% 43 | 97.73% 76 | 98.70%
11 | 91.67% 44 | 97.78% 77 | 98.72%
12 | 92.31% 45 | 97.83% 78 | 98.73%
13 | 92.86% 46 | 97.87% 79 | 98.75%
14 | 93.33% 47 | 97.92% 80 | 98.77%
15 | 93.75% 48 | 97.96% 81 | 98.78%
16 | 94.12% 49 | 98.00% 82 | 98.80%
17 | 94.44% 50 | 98.04% 83 | 98.81%
18 | 94.74% 51 | 98.08% 84 | 98.82%
19 | 95.00% 52 | 98.11% 85 | 98.84%
20 | 95.24% 53 | 98.15% 86 | 98.85%
21 | 95.45% 54 | 98.18% 87 | 98.86%
22 | 95.65% 55 | 98.21% 88 | 98.88%
23 | 95.83% 56 | 98.25% 89 | 98.89%
24 | 96.00% 57 | 98.28% 90 | 98.90%
25 | 96.15% 58 | 98.31% 91 | 98.91%
26 | 96.30% 59 | 98.33% 92 | 98.92%
27 | 96.43% 60 | 98.36% 93 | 98.94%
28 | 96.55% 61 | 98.39% 94 | 98.95%
29 | 96.67% 62 | 98.41% 95 | 98.96%
30 | 96.77% 63 | 98.44% 96 | 98.97%
31 | 96.88% 64 | 98.46% 97 | 98.98%
32 | 96.97% 65 | 98.48% 98 | 98.99%
33 | 97.06% 66 | 98.51% 99 | 99%

On the 99th day:
Percentage eaten = (99/100 ร— 100)% = 99%.
We observe that:
โ€ข The percentage of fodder eaten increases each day.
โ€ข It gets closer to 100%, but stays below 100%.
โ€ข The bull leaves 1 unit every day.
โ€ข This 1 unit becomes a smaller percentage of the increasing amount offered.

9. Workers in a coffee plantation take 18 days to pick coffee berries in 20% of the plantation. How many days will they take to complete the picking work for the entire plantation, assuming the rate of work stays the same? Why is this assumption necessary?

Answer:
20% is one-fifth of the plantation, so the whole plantation should take 5 times as long, about 90 days.
Time taken for 20% of the plantation = 18 days.
Time taken for 100% of the plantation = (100 รท 20) ร— 18 days
= 5 ร— 18 days
= 90 days.
โˆด They will take 90 days in all to complete the work.
After the first 18 days, they will need 90 โˆ’ 18 = 72 more days.
The same rate is necessary because we are assuming that equal portions of the plantation take equal amounts of time. If the workers pick faster or slower, the total time will change.

10. The badminton coach has planned the training sessions such that the ratio of warm up : play : cool down is 10% : 80% : 10%. If he wants to conduct a training of 90 minutes. How long should each activity be done?

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 12 - Figure it Out Question 10

Answer:
Most of the time should be spent playing. Warm up and cool down should take equal amounts of time, each close to 10 minutes.
Warm up time = (10/100) ร— 90 minutes
= 9 minutes.
Play time = (80/100) ร— 90 minutes
= 72 minutes.
Cool down time = (10/100) ร— 90 minutes
= 9 minutes.

Check: 9 + 72 + 9 = 90 minutes.
โˆด Warm up: 9 minutes; play: 72 minutes; cool down: 9 minutes.

11. An estimated 90% of the worldโ€™s population lives in the Northern Hemisphere. Find the (approximate) number of people living in the Northern Hemisphere based on this yearโ€™s worldwide population.

Answer:
Taking the approximate world population as 8.2 billion (2025 estimate), 90% should be a little less than 8.2 billion, between 7 billion and 8 billion.
Population living in the Northern Hemisphere
= (90/100) ร— 8.2 billion
= 7.38 billion
= 738 crore.
โˆด Using the 2025 estimate, approximately 7.38 billion people or 738 crore people, live in the Northern Hemisphere.
For any other year, the approximate number is 0.9 ร— that yearโ€™s world population.

12. A recipe for the dish, halwa, for 4 people has the following ingredients in the given proportions – Rava: 40%, Sugar: 40%, and Ghee: 20%.

(i) If you want to make halwa for 8 people, what is the proportion of each of the above ingredients?
(ii) If the total weight of the ingredients is 2 kg, how much rava, sugar and ghee are present?
Answer:
(i) For twice as many people, we need twice the quantity of every ingredient. Since all the quantities are doubled, their proportions remain the same.
โˆด Rava = 40%, sugar = 40% and ghee = 20%.
Their ratio is 40 : 40 : 20 = 2 : 2 : 1.

(ii) Rava and sugar should have equal weights, each less than 1 kg. Ghee should weigh half as much as either one.
Weight of rava = (40/100) ร— 2 kg
= 0.8 kg
= 800 g.
Weight of sugar = (40/100) ร— 2 kg
= 0.8 kg
= 800 g.
Weight of ghee = (20/100) ร— 2 kg
= 0.4 kg
= 400 g.

Check: 800 g + 800 g + 400 g = 2000 g = 2 kg.
โˆด Rava = 800 g, sugar = 800 g and ghee = 400 g.

Get here the Solutions and Answers of Figure it Out at Page 19.

Page 19 – Figure it Out

1. If a shopkeeper buys a geometry box for โ‚น75 and sells it for โ‚น110, what is his profit margin with respect to the cost?

Answer:
Cost price = โ‚น75
Selling price = โ‚น110
Profit = Selling price โˆ’ Cost price
= โ‚น110 โˆ’ โ‚น75
= โ‚น35
Profit percentage = (Profit รท Cost price) ร— 100%
= (35/75 ร— 100)%
= (140/3)%
= 46โ…”%
โˆด His profit margin with respect to the cost is 46โ…”%.

2. I am a carpenter and I make chairs. The cost of materials for a chair is โ‚น475 and I want to have a profit margin of 50%. At what price should I sell a chair?

Answer:
Cost price of a chair = โ‚น475
Required profit = 50% of โ‚น475
= โ‚น(50/100 ร— 475)
= โ‚น237.50
Selling price = Cost price + Profit
= โ‚น475 + โ‚น237.50
= โ‚น712.50
โˆด I should sell a chair for โ‚น712.50.

3. The total sales of a company (also called revenue) was โ‚น2.5 crore last year. They had a healthy profit margin of 25%. What was the total expenditure (costs) of the company last year?

Answer:
Total sales = โ‚น2.5 crore
Here, the profit is 25% of the total sales.

Profit = 25% of โ‚น2.5 crore
= โ‚น(25/100 ร— 2.5) crore
= โ‚น0.625 crore

Total expenditure = Total sales โˆ’ Profit
= โ‚น2.5 crore โˆ’ โ‚น0.625 crore
= โ‚น1.875 crore
โˆด The total expenditure was โ‚น1.875 crore, or โ‚น1,87,50,000.

4. A clothing shop offers a 25% discount on all shirts. If the original price of a shirt is โ‚น300, how much will Anwar have to pay to buy this shirt?

Answer:
Original price = โ‚น300

Discount = 25% of โ‚น300
= โ‚น(25/100 ร— 300)
= โ‚น75

Amount to be paid = Original price โˆ’ Discount
= โ‚น300 โˆ’ โ‚น75
= โ‚น225

โˆด Anwar will have to pay โ‚น225.

5. The petrol price in 2015 was โ‚น60 and โ‚น100 in 2025. What is the percentage increase in the price of petrol?

(i) 50%
(ii) 40%
(iii) 60%
(iv) 66.66%
(v) 140%
(vi) 160.66%
Answer:
Increase in price = โ‚น100 โˆ’ โ‚น60 = โ‚น40

Percentage increase = (Increase รท Original price) ร— 100%
= (40/60 ร— 100)%
= (200/3)%
= 66โ…”%

โˆด The increase is 66โ…”% = 66.666โ€ฆ%.
The closest option is (iv), 66.66%.

6. Samson bought a car for โ‚น4,40,000 after getting a 15% discount from the car dealer. What was the original price of the car?

Answer:
After a discount of 15%, Samson paid 100% โˆ’ 15% = 85% of the original price.
85% of the original price = โ‚น4,40,000
1% of the original price = โ‚น(4,40,000 รท 85)
100% of the original price = โ‚น(4,40,000 ร— 100 รท 85)
= โ‚น(88,00,000/17)
โ‰ˆ โ‚น5,17,647.06
โˆด The original price of the car was approximately โ‚น5,17,647.06.

7. 1600 people voted in an election and the winner got 500 votes. What percent of the total votes did the winner get? Can you guess the minimum number of candidates who stood for the election?

Answer:
Percentage of votes received by the winner = (500/1600 ร— 100)%
= 31.25%

The winner got the most votes, so no other candidate could have received more than 500 votes.
If there were only 3 candidates, their total votes could not be more than 3 ร— 500 = 1500.
But 1600 votes were cast. So, at least 4 candidates must have stood for the election.

For example, the votes could be 500, 400, 400 and 300.
Their sum is 1600 and the candidate with 500 votes wins.
โˆด The winner got 31.25% of the votes and the minimum number of candidates is 4.

8. The price of 1 kg of rice was โ‚น38 in 2024. It is โ‚น42 in 2025. What is the rate of inflation? (Inflation is the percentage increase in prices.)

Answer:
Increase in price = โ‚น42 โˆ’ โ‚น38 = โ‚น4

Rate of inflation = (Increase รท Original price) ร— 100%
= (4/38 ร— 100)%
= (200/19)%
โ‰ˆ 10.53%
โˆด The rate of inflation is approximately 10.53%.

9. A number increased by 20% becomes 90. What is the number?

Answer:
After an increase of 20%, the new number is 120% of the original number.

120% of the original number = 90
Original number = 90 ร— 100/120
= 75
โˆด The number is 75.

10. A milkman sold two buffaloes for โ‚น80,000 each. On one of them, he made a profit of 5% and on the other a loss of 10%. Find his overall profit or loss.

Answer:
For the first buffalo, the selling price is 105% of its cost price.
Cost price of the first buffalo = โ‚น(80,000 ร— 100/105)
= โ‚น(16,00,000/21)

For the second buffalo, the selling price is 90% of its cost price.
Cost price of the second buffalo = โ‚น(80,000 ร— 100/90)
= โ‚น(8,00,000/9)

Total cost price = โ‚น(16,00,000/21 + 8,00,000/9)
= โ‚น(48,00,000/63 + 56,00,000/63)
= โ‚น(1,04,00,000/63)
โ‰ˆ โ‚น1,65,079.37
Total selling price = โ‚น80,000 + โ‚น80,000
= โ‚น1,60,000
Since the total cost price is greater than the total selling price, there is a loss.

Loss = โ‚น(1,04,00,000/63 โˆ’ 1,60,000)
= โ‚น(3,20,000/63)
โ‰ˆ โ‚น5,079.37

Loss percentage = (Loss รท Total cost price) ร— 100%
= [(3,20,000/63) รท (1,04,00,000/63) ร— 100]%
= (40/13)%
โ‰ˆ 3.08%
โˆด His overall loss is approximately โ‚น5,079.37, or 3.08%.

11. The population of elephants in a national park increased by 5% in the last decade. If the population of the elephants last decade is p, the population now is

(i) p ร— 0.5
(ii) p ร— 0.05
(iii) p ร— 1.5
(iv) p ร— 1.05
(v) p + 1.50
Answer:
Increase in population = 5% of p = 0.05p
Present population = p + 0.05p = 1.05p

โˆด The correct option is (iv) p ร— 1.05.

12. Which of the following statement(s) mean the same as – โ€œThe demand for cameras has fallen by 85% in the last decadeโ€?

(i) The demand now is 85% of the demand a decade ago.
(ii) The demand a decade ago was 85% of the demand now.
(iii) The demand now is 15% of the demand a decade ago.
(iv) The demand a decade ago was 15% of the demand now.
(v) The demand a decade ago was 185% of the demand now.
(vi) The demand now is 185% of the demand a decade ago.
Answer:
Let the demand a decade ago be 100 units.
A fall of 85% means a decrease of 85 units.
Demand now = 100 โˆ’ 85 = 15 units.

โˆด The demand now is 15% of the demand a decade ago.
The correct option is (iii).

Get here the Solutions and Answers of Figure it Out at Page 22.

Page 22 – Figure it Out

1. Bank of Yahapur offers an interest of 10% p.a. Compare how much one gets if they deposit โ‚น20,000 for a period of 2 years with compounding and without compounding annually.

Answer:
Without compounding:
Interest for 1 year = 10% of โ‚น20,000
= โ‚น(10/100 ร— 20,000)
= โ‚น2,000
Interest for 2 years = โ‚น2,000 ร— 2 = โ‚น4,000
Total amount received = โ‚น20,000 + โ‚น4,000 = โ‚น24,000

With annual compounding:
Interest for the first year = 10% of โ‚น20,000 = โ‚น2,000
Amount after the first year = โ‚น20,000 + โ‚น2,000 = โ‚น22,000

Interest for the second year = 10% of โ‚น22,000 = โ‚น2,200
Amount after the second year = โ‚น22,000 + โ‚น2,200 = โ‚น24,200
Difference = โ‚น24,200 โˆ’ โ‚น24,000 = โ‚น200
โˆด One gets โ‚น24,000 without compounding and โ‚น24,200 with annual compounding. Compounding gives โ‚น200 more.

2. Bank of Wahapur offers an interest of 5% p.a. Compare how much one gets if one deposits โ‚น20,000 for a period of 4 years with compounding and without compounding annually.

Answer:
Without compounding:
Interest for 1 year = 5% of โ‚น20,000 = โ‚น1,000
Interest for 4 years = โ‚น1,000 ร— 4 = โ‚น4,000
Total amount received = โ‚น20,000 + โ‚น4,000 = โ‚น24,000

With annual compounding:
Year 1:
Interest = 5% of โ‚น20,000 = โ‚น1,000
Amount = โ‚น20,000 + โ‚น1,000 = โ‚น21,000

Year 2:
Interest = 5% of โ‚น21,000 = โ‚น1,050
Amount = โ‚น21,000 + โ‚น1,050 = โ‚น22,050

Year 3:
Interest = 5% of โ‚น22,050 = โ‚น1,102.50
Amount = โ‚น22,050 + โ‚น1,102.50 = โ‚น23,152.50

Year 4:
Interest = 5% of โ‚น23,152.50 = โ‚น1,157.625
Amount = โ‚น23,152.50 + โ‚น1,157.625 = โ‚น24,310.125

Rounding the final amount to the nearest paise, we get โ‚น24,310.13.
Extra amount from compounding = โ‚น24,310.125 โˆ’ โ‚น24,000
= โ‚น310.125
โ‰ˆ โ‚น310.13
โˆด One gets โ‚น24,000 without compounding and approximately โ‚น24,310.13 with annual compounding. Compounding gives approximately โ‚น310.13 more.

3. Do you observe anything interesting in the solutions of the two questions above? Share and discuss.

Answer:
Without compounding, both deposits give the same total interest of โ‚น4,000 and the same total amount of โ‚น24,000.
This is because 10% ร— 2 = 20% and 5% ร— 4 = 20%. In both cases, the total interest is 20% of โ‚น20,000.

With annual compounding:
Amount from Bank of Yahapur after 2 years = โ‚น24,200
Amount from Bank of Wahapur after 4 years = โ‚น24,310.125

Difference = โ‚น24,310.125 โˆ’ โ‚น24,200
= โ‚น110.125
โ‰ˆ โ‚น110.13
So, Bank of Wahapur gives approximately โ‚น110.13 more over its 4-year period, even though its annual interest rate is lower.

With compounding, each year’s interest is added to the deposit and also earns interest in the following years. In these two cases, the longer period of 4 years gives a greater final amount.

Get here the Solutions and Answers of Figure it Out at Page 24.

Page 24 – Figure it Out

4. Jasmine invests amount โ€˜pโ€™ for 4 years at an interest of 6% p.a. Which of the following expression(s) describe the total amount she will get after 4 years when compounding is not done?

(i) p ร— 6 ร— 4
(ii) p ร— 0.6 ร— 4
(iii) p ร— (0.6/100) ร— 4
(iv) p ร— (0.06/100) ร— 4
(v) p ร— 1.6 ร— 4
(vi) p ร— 1.06 ร— 4
(vii) p + (p ร— 0.06 ร— 4)
Answer:
Interest for 1 year = 6% of p
= p ร— 6/100
= p ร— 0.06

Without compounding, the interest is the same each year.
Interest for 4 years = p ร— 0.06 ร— 4

Total amount = Principal + Interest
= p + (p ร— 0.06 ร— 4)
= 1.24p
โˆด The correct option is (vii).

5. The post office offers an interest of 7% p.a. How much interest would one get if one invests โ‚น50,000 for 3 years without compounding? How much more would one get if it was compounded?

Answer:
Without compounding:
Interest for 1 year = 7% of โ‚น50,000 = โ‚น3,500
Interest for 3 years = โ‚น3,500 ร— 3 = โ‚น10,500

With annual compounding:
Year 1:
Interest = 7% of โ‚น50,000 = โ‚น3,500
Amount = โ‚น50,000 + โ‚น3,500 = โ‚น53,500

Year 2:
Interest = 7% of โ‚น53,500 = โ‚น3,745
Amount = โ‚น53,500 + โ‚น3,745 = โ‚น57,245

Year 3:
Interest = 7% of โ‚น57,245 = โ‚น4,007.15
Amount = โ‚น57,245 + โ‚น4,007.15 = โ‚น61,252.15

Compound interest for 3 years = โ‚น61,252.15 โˆ’ โ‚น50,000
= โ‚น11,252.15
Extra interest = โ‚น11,252.15 โˆ’ โ‚น10,500
= โ‚น752.15
โˆด The interest without compounding is โ‚น10,500. Annual compounding gives โ‚น752.15 more.

6. Giridhar borrows a loan of โ‚น12,500 at 12% per annum for 3 years without compounding and Raghava borrows the same amount for the same time period at 10% per annum, compounded annually. Who pays more interest and by how much?

Answer:
Giridhar’s loan:
Interest for 1 year = 12% of โ‚น12,500
= โ‚น(12/100 ร— 12,500)
= โ‚น1,500

Interest for 3 years = โ‚น1,500 ร— 3 = โ‚น4,500
Raghava’s loan:
Amount after the first year = โ‚น12,500 ร— 1.10 = โ‚น13,750
Amount after the second year = โ‚น13,750 ร— 1.10 = โ‚น15,125
Amount after the third year = โ‚น15,125 ร— 1.10 = โ‚น16,637.50

Interest for 3 years = โ‚น16,637.50 โˆ’ โ‚น12,500
= โ‚น4,137.50
Difference in interest = โ‚น4,500 โˆ’ โ‚น4,137.50
= โ‚น362.50
โˆด Giridhar pays โ‚น362.50 more interest than Raghava.

7. Consider an amount โ‚น1000. If this grows at 10% p.a., how long will it take to double when compounding is done vs. when compounding is not done? Is compounding an example of exponential growth and not-compounding an example of linear growth?

Answer:
Double of โ‚น1000 = โ‚น2000
So, the required increase is โ‚น2000 โˆ’ โ‚น1000 = โ‚น1000.

Without compounding:
Interest each year = 10% of โ‚น1000 = โ‚น100
Time required = โ‚น1000 รท โ‚น100 per year = 10 years

With annual compounding:
Each year, the amount becomes 110% of the previous year’s amount. So, we multiply by 1.1 each year.

After 1 year: โ‚น1000 ร— 1.1 = โ‚น1100
After 2 years: โ‚น1100 ร— 1.1 = โ‚น1210
After 3 years: โ‚น1210 ร— 1.1 = โ‚น1331
After 4 years: โ‚น1331 ร— 1.1 = โ‚น1464.1
After 5 years: โ‚น1464.1 ร— 1.1 = โ‚น1610.51
After 6 years: โ‚น1610.51 ร— 1.1 = โ‚น1771.561
After 7 years: โ‚น1771.561 ร— 1.1 = โ‚น1948.7171
After 8 years: โ‚น1948.7171 ร— 1.1 = โ‚น2143.58881
The amount is less than โ‚น2000 after 7 years and more than โ‚น2000 after 8 years.

โˆด With annual compounding, it first reaches or exceeds double at the end of 8 years. Without compounding, it doubles in 10 years.
Yes, compounding is an example of exponential growth because the amount is multiplied by the same factor, 1.1, each year. Without compounding, it is linear growth because the same amount, โ‚น100, is added each year.

8. The population of a city is rising by about 3% every year. If the current population is 1.5 crore, what is the expected population after 3 years?

Answer:
Current population = 1.5 crore = 1,50,00,000
Each year, the population becomes 103% of the previous year’s population.
Multiplying factor = 103/100 = 1.03

Population after 1 year = 1,50,00,000 ร— 1.03 = 1,54,50,000
Population after 2 years = 1,54,50,000 ร— 1.03 = 1,59,13,500
Population after 3 years = 1,59,13,500 ร— 1.03 = 1,63,90,905
โˆด The expected population after 3 years is about 1,63,90,905, or 1.6390905 crore.

9. In a laboratory, the number of bacteria in a certain experiment increases at the rate of 2.5% per hour. Find the number of bacteria at the end of 2 hours if the initial count is 5,06,000.

Answer:
Initial number of bacteria = 5,06,000
Each hour, the number becomes 102.5% of the previous count.
Multiplying factor = 102.5/100 = 1.025

Number after 1 hour = 5,06,000 ร— 1.025
= 5,18,650

Number after 2 hours = 5,18,650 ร— 1.025
= 5,31,616.25

As per calculation, it is 5,31,616.25. Since bacteria are counted in whole numbers, the expected count is approximately 5,31,616 bacteria.

Get here the Solutions and Answers of Figure it Out at Page 28.

Page 28 – Figure it Out

1. The population of Bengaluru in 2025 is about 250% of its population in 2000. If the population in 2000 was 50 lakhs, what is the population in 2025?

Answer:
Population in 2025 = 250% of 50 lakhs
= (250/100) ร— 50 lakhs
= 125 lakhs
โˆด The population in 2025 is about 125 lakhs or 1 crore 25 lakhs.

2. The population of the world in 2025 is about 8.2 billion. The populations of some countries in 2025 are given. Match them with their approximate percentage share of the worldwide population.

[Hint: Writing these numbers in the standard form and estimating can help].

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 28 - Figure it Out - Question 2

Answer:
World population = 8.2 billion = 8,200 million
India’s population = 1.46 billion = 1,460 million

Percentage share = (Country’s population รท World population) ร— 100%
Germany’s share = (83/8,200 ร— 100)%
โ‰ˆ 1.01%
โ‰ˆ 1%

India’s share = (1,460/8,200 ร— 100)%
โ‰ˆ 17.80%
โ‰ˆ 18%

Bangladesh’s share = (175/8,200 ร— 100)%
โ‰ˆ 2.13%
โ‰ˆ 2%

USA’s share = (347/8,200 ร— 100)%
โ‰ˆ 4.23%
โ‰ˆ 4%

โˆด The matches are:
Germany โ†’ 1%
India โ†’ 18%
Bangladesh โ†’ 2%
USA โ†’ 4%

The option 4% is missing from the choices, while 2% appears twice.

3. The price of a mobile phone is โ‚น8,250. A GST of 18% is added to the price. Which of the following gives the final price of the phone including the GST?

(i) 8250 + 18
(ii) 8250 + 1800
(iii) 8250 + 18/100
(iv) 8250 ร— 18
(v) 8250 ร— 1.18
(vi) 8250 + 8250 ร— 0.18
(vii) 1.8 ร— 8250
Answer:
GST = 18% of โ‚น8,250
= โ‚น(8,250 ร— 18/100)
= โ‚น1,485
Final price = โ‚น8,250 + โ‚น1,485
= โ‚น9,735

We can also write the final price as:
8250 + 8250 ร— 0.18
= 8250 ร— (1 + 0.18)
= 8250 ร— 1.18
โˆด Options (v) and (vi) are correct. The final price is โ‚น9,735.

4. The monthly percentage change in population (compared to the previous month) of mice in a lab is given: Month 1 change was +5%, Month 2 change was โˆ’2%, and Month 3 change was โˆ’3%. Which of the following statement(s) are true? The initial population is p.

(i) The population after three months was p ร— 0.05 ร— 0.02 ร— 0.03.
(ii) The population after three months was p ร— 1.05 ร— 0.98 ร— 0.97.
(iii) The population after three months was p + 0.05 โˆ’ 0.02 โˆ’ 0.03.
(iv) The population after three months was p.
(v) The population after three months was more than p.
(vi) The population after three months was less than p.
Answer:
Population after Month 1 = p ร— 105/100 = p ร— 1.05

Population after Month 2 = p ร— 1.05 ร— 98/100
= p ร— 1.05 ร— 0.98

Population after Month 3 = p ร— 1.05 ร— 0.98 ร— 97/100
= p ร— 1.05 ร— 0.98 ร— 0.97
= 0.99813p

Since 0.99813 is less than 1, the final population is less than p.
โˆด Statements (ii) and (vi) are true.

5. A shopkeeper initially set the price of a product with a 35% profit margin. Due to poor sales, he decided to offer a 30% discount on the selling price. Will he make a profit or a loss? Give reasons for your answer.

Answer:
Let the cost price be โ‚น100.
Price before discount = โ‚น100 + 35% of โ‚น100
= โ‚น100 + โ‚น35
= โ‚น135

Discount = 30% of โ‚น135
= โ‚น(30/100 ร— 135)
= โ‚น40.50

Final selling price = โ‚น135 โˆ’ โ‚น40.50
= โ‚น94.50
Since the selling price is less than the cost price, there is a loss.

Loss = โ‚น100 โˆ’ โ‚น94.50 = โ‚น5.50
Loss percentage = (5.50/100 ร— 100)% = 5.5%
โˆด The shopkeeper makes a loss of 5.5%.

6. What percentage of area is occupied by the region marked โ€˜Eโ€™ in the figure?

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 28 - Figure it Out - Question 6

Answer:
The whole figure is a square. Its lower-left quarter is divided into two equal triangles, D and E.
Fraction of the whole area occupied by E = 1/2 ร— 1/4
= 1/8

Required percentage = (1/8 ร— 100)%
= 12.5%
โˆด Region E occupies 12.5% of the total area.

7. What is 5% of 40? What is 40% of 5?

What is 25% of 12? What is 12% of 25?
What is 15% of 60? What is 60% of 15?
What do you notice?
Can you make a general statement and justify it using algebra, comparing x% of y and y% of x?
Answer:
5% of 40 = 5/100 ร— 40 = 2
40% of 5 = 40/100 ร— 5 = 2

25% of 12 = 25/100 ร— 12 = 3
12% of 25 = 12/100 ร— 25 = 3

15% of 60 = 15/100 ร— 60 = 9
60% of 15 = 60/100 ร— 15 = 9
We notice that the answers in each pair are equal.
In general, x% of y = y% of x.

This is because:
x% of y = x/100 ร— y = xy/100
y% of x = y/100 ร— x = yx/100 = xy/100
โˆด x% of y and y% of x are always equal.

8. A school is organising an excursion for its students. 40% of them are Grade 8 students and the rest are Grade 9 students. Among these Grade 8 students, 60% are girls.

[Hint: Drawing a rough diagram can help].
(i) What percentage of the students going to the excursion are Grade 8 girls?
(ii) If the total number of students going to the excursion is 160, how many of them are Grade 8 girls?
Answer:

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 28 - Figure it Out - Question 8 Answer

(i) Grade 8 girls are 60% of the 40% who are Grade 8 students.
Percentage of all students who are Grade 8 girls = (60/100 ร— 40)%
= 24%
โˆด 24% of the students going to the excursion are Grade 8 girls.

(ii) Number of Grade 8 students = 40% of 160
= 40/100 ร— 160
= 64

Number of Grade 8 girls = 60% of 64
= 60/100 ร— 64
= 38.4

A number of students must be a whole number. Since we get 38.4, the figures in this question do not give a possible exact number of Grade 8 girls.

9. A shopkeeper sells pencils at a price such that the selling price of 3 pencils is equal to the cost of 5 pencils. Does he make a profit or a loss? What is his profit or loss percentage?

Answer:
Let the cost price of one pencil be โ‚น1.

Cost price of 3 pencils = โ‚น3
Cost price of 5 pencils = โ‚น5
Selling price of 3 pencils = Cost price of 5 pencils = โ‚น5
Since the selling price is greater than the cost price, there is a profit.
Profit on 3 pencils = โ‚น5 โˆ’ โ‚น3 = โ‚น2

Profit percentage = (Profit รท Cost price) ร— 100%
= (2/3 ร— 100)%
= (200/3)%
= 66โ…”%
โˆด The shopkeeper makes a profit of 66โ…”%.

10. The bus fares were increased by 3% last year and by 4% this year. What is the overall percentage price increase in the last 2 years?

Answer:
Let the original fare be โ‚น100.
Fare after last year’s increase = โ‚น100 ร— 103/100
= โ‚น103

Fare after this year’s increase = โ‚น103 ร— 104/100
= โ‚น107.12

Total increase = โ‚น107.12 โˆ’ โ‚น100
= โ‚น7.12
Overall percentage increase = (7.12/100 ร— 100)%
= 7.12%
โˆด The overall increase in bus fares is 7.12%.

11. If the length of a rectangle is increased by 10% and the area is unchanged, by what percentage (exactly) does the breadth decrease by?

Answer:
Let the original length be l and the original breadth be b.
Original area = l ร— b
New length = l ร— 110/100 = 11l/10

Since the area is unchanged,
New breadth = Original area รท New length
= (l ร— b) รท (11l/10)
= 10b/11

Decrease in breadth = b โˆ’ 10b/11
= b/11
Percentage decrease = [(b/11) รท b ร— 100]%
= (100/11)%
= 9 1/11%
โˆด The breadth decreases by exactly 9 1/11%.

12. The percentage of ingredients in a 65 g chips packet is shown in the picture. Find out the weight each ingredient makes up in this packet.

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 28 - Figure it Out - Question 12

Answer:
Weight of potato = 70% of 65 g
= 70/100 ร— 65 g
= 45.5 g

Weight of vegetable oil = 24% of 65 g
= 24/100 ร— 65 g
= 15.6 g

Weight of salt = 3% of 65 g
= 3/100 ร— 65 g
= 1.95 g

Weight of spices = 3% of 65 g
= 3/100 ร— 65 g
= 1.95 g
โˆด The packet contains approximately 45.5 g of potato, 15.6 g of vegetable oil, 1.95 g of salt and 1.95 g of spices.

13. Three shops sell the same items at the same price. The shops offer deals as follows:

Shop A: โ€œBuy 1 and get 1 freeโ€
Shop B: โ€œBuy 2 and get 1 freeโ€
Shop C: โ€œBuy 3 and get 1 freeโ€
Answer the following:
(i) If the price of one item is โ‚น100, what is the effective price per item in each shop? Arrange the shops from cheapest to costliest.
(ii) For each shop, calculate the percentage discount on the items. [Hint: Compare the free items to the total items you receive.]
(iii) Suppose you need 4 items. Which shop would you choose? Why?
Answer:
(i) Shop A:
We pay โ‚น100 and receive 2 items.
Effective price per item = โ‚น100 รท 2 = โ‚น50
Shop B:
We pay โ‚น200 and receive 3 items.
Effective price per item = โ‚น200 รท 3 = โ‚น66โ…” (approximately โ‚น66.67)
Shop C:
We pay โ‚น300 and receive 4 items.
Effective price per item = โ‚น300 รท 4 = โ‚น75
โˆด From cheapest to costliest: Shop A, Shop B, Shop C.

(ii) Discount percentage = (Number of free items รท Total number of items received) ร— 100%
Shop A: (1/2 ร— 100)% = 50%
Shop B: (1/3 ร— 100)% = 33โ…“%
Shop C: (1/4 ร— 100)% = 25%
โˆด The discounts are 50% at Shop A, 33โ…“% at Shop B and 25% at Shop C.

(iii) At Shop A, we can use the offer twice: pay for 2 items and get 2 free.
Cost of 4 items = โ‚น200
At Shop B, we pay โ‚น200 for 3 items under the offer and โ‚น100 for one more item.
Cost of 4 items = โ‚น300
At Shop C, we pay for 3 items and get 1 free.
Cost of 4 items = โ‚น300
โˆด I would choose Shop A because 4 items cost only โ‚น200, which is โ‚น100 less than at either of the other shops.

14. In a room of 100 people, 99% are left-handed. How many left-handed people have to leave the room to bring that percentage down to 98%?

Answer:
Number of left-handed people = 99% of 100 = 99
Number of people who are not left-handed = 100 โˆ’ 99 = 1
Only left-handed people leave, so this 1 person remains.

When 98% are left-handed, the remaining 2% are not left-handed.
So, 2% of the remaining people = 1
Total number of people remaining = 1 ร— 100/2 = 50
Number of left-handed people who leave = 100 โˆ’ 50 = 50
โˆด 50 left-handed people have to leave the room.

15. Look at the following graph.

Class 8 Maths Ganita Prakash Part 2 Chapter 1 Page 28 - Figure it Out - Question 15

Based on the graph, which of the following statement(s) are valid?
(i) People in their twenties are the most computer-literate among all age groups.
(ii) Women lag behind in the ability to use computers across age groups.
(iii) There are more people in their twenties than teenagers.
(iv) More than a quarter of people in their thirties can use computers.
(v) Less than 1 in 10 aged 60 and above can use computers.
(vi) Half of the people in their twenties can use computers.
Answer:
(i) Valid. The percentages for both women and men are highest in their twenties: 26% and 37%, respectively.

(ii) Valid. In every age group, the bar for women is shorter than the bar for men.

(iii) Not valid. The graph shows percentages of people who can use computers. It does not show the total number of people in each age group.

(iv) Not valid. A quarter is 25%. Among people in their thirties, 14% of women and 25% of men can use computers. So the overall percentage cannot be more than 25%.

(v) Valid. One in ten means 10%. Among seniors, 2% of women and 4% of men can use computers. Both are less than 10%.

(vi) Not valid. Half means 50%. Among people in their twenties, 26% of women and 37% of men can use computers. So the overall percentage is less than 50%. We cannot add these two percentages because they are percentages of different groups.

โˆด Statements (i), (ii) and (v) are valid.

Final Tips to Master Percentages in Class 8

Percentages are everywhere, from sale tags and GST bills to bank interest and exam scores, so this chapter will serve you well beyond your Maths test. Try each question on your own first, estimate the answer before calculating, and then use these Fractions in Disguise Class 8 solutions to check your method, not just the final number. Give extra time to the Tricky Percentages section, especially successive discounts and a 50% profit margin followed by a 50% discount, because the obvious answer turns out to be wrong. When you are ready, move on to Chapter 2, The Baudhayana-Pythagoras Theorem, or browse the other chapters in our NCERT Solutions for Class 8 Maths.

Content Reviewed: October 24, 2026
Content Reviewer

Kalpana Mishra

Kalpana Mishra, Senior Content Writer at Tiwari Academy, holds an M.Sc. in Mathematics from the University of Allahabad and a B.Ed. She has been teaching Mathematics since 2020.