NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.1 Surface Areas and Volumes (mensuration) in Hindi Medium as well as English Medium for all boards (CBSE, MP Board, UP Board, Bihar Board, Uttarakhand) who are using NCERT Books as a Textbook for exams. NCERT Solutions are have been updated as per the latest CBSE Syllabus 2018-2019.

## NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.1

### Class 10 Maths Chapter 13 Exercise 13.1 Sols in English

NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.1 Surface Areas and Volumes in English Medium free to use online or download as PDF to use offline. Click here to go back to Class 10 Maths Chapter 13 all exercises or go for Hindi Medium Solutions, if you want to see the solutions in Hindi.

### Class 10 Maths Chapter 13 Exercise 13.1 Sols in Hindi

NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.1 Surface Areas and Volumes in Hindi Medium free to use online. Click here to go back to Class 10 Maths Chapter 13 all exercises or go for English Medium solutions, if you want to change the medium of solutions as English.

Go back to top of Hindi Medium Solutions or English Medium solutions.

#### About 10 Maths Exercise 13.1

In Exercise 13.1 Questions are based on Surface areas related to Cubes, Cuboids, Cones, Cylinders, etc. The solid figures are the combination of two or more figures. The surface area of the solid figures depends on the part which are visible. Exercise 13.1 is based on the Chapter 13 of class 9 Maths. All the questions in this exercise are direct applications of Mensuration. To find the surface area of joined figures, you should first need to draw a rough sketch to identify the portion which are visible and to decide which are is to be calculated.

If it is given to find Total Surface Area (TSA) of a solid, we must recognize, the visible part of the solid to calculate the TSA. Do not apply directly the formula of TSA in case of solid figure (combination of two or more figure).

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Hello Sir,

Your solutions are very helpful but while going through the solution I found one minute error Kindly see to it.In some Ques like in Q4 and Q 5 the base area of hemisphere is also taken as 2πr but it should be πr.

very useful thanks a lot