NCERT Solutions for Class 11 Maths Chapter 3 Exercise 3.5 Supplementary Exercise of Trigonometric Functions in Hindi Medium for the students using NCERT Books in Hindi and English Medium for those who are using Textbooks in English. Solutions are in updated form based on latest CBSE Syllabus 2018-19 for all the boards (CBSE, UP Board, MP Board, Bihar, Gujrat and others) who are using NCERT Books.

Table of Contents

## NCERT Solutions for Class 11 Maths Chapter 3 Exercise 3.5

### Class 11 Maths Chapter 3 Exercise 3.5 Sols in English

NCERT Solutions for Class 11 Maths Chapter 3 Exercise 3.5 Supplementary Exercise of Trigonometric Functions in English Medium is given below. It is an important one as per examination point of view. After doing all the main exercises, students must do this as it is based on sine and cosine rule which is important for further classes. Click here to see the Hindi Medium solutions or go to NCERT Solutions for Class 11 Maths Chapter 3 to see the solutions of other exercises.

### Class 11 Maths Chapter 3 Exercise 3.5 Sols in Hindi

NCERT Solutions for Class 11 Maths Chapter 3 Exercise 3.5 Supplementary Exercise in Hindi Medium is given below. All the questions of this exercise are based on sine and cosine formulae. Click here to see English Medium sols go to NCERT Solutions for Class 11 Maths Chapter 3 to see the solutions of other exercises.

#### About 11 Maths Exercise 3.5 Supplementary

In Chapter 3 Exercise 3.5, mainly the sine formula and cosine formula are introduced. The questions are given on the basis of these formula only. Some of the problems required both the formulae simultaneously.

Sine Formula: In any triangle, the sides of triangle are proportional to the sine of angles opposite to the sides.

i.e. (sin A)/a = (sin B)/b = (sin C)/c = k, where k is a constant.

- Cosine formula: The cosine of an angle A of any triangle ABC, whose sides are a (opposite to BC), b (opposite to AC) and c (opposite to AB) is given by cos A = [b² + c² – a²]/2bc.
- साइन सूत्र: किसी भी त्रिभुज में, भुजाएँ सम्मुख कोणों के साइनों के समानुपाती होती हैं।

(sin A)/a = (sin B)/b = (sin C)/c = k

कोसाइन सूत्र: किसी त्रिभुज ABC, जिसके कोण A, B और C हैं तथा a, b और c क्रमशः कोणों की सम्मुख भुजाएँ हैं। cos A = [b² + c² – a²]/2bc

Thank you very much sir.

I had some doubts in this exercise and was looking for this

appreciated

this is very best