NCERT Solutions for Class 5 Maths Mela Chapter 1 We the Travellers I (New Edition) for Session 2025–26. Maths Mela chapter 1 gives a well-structured answers based on the latest syllabus. This chapter helps students understand large numbers, place value, number patterns, rounding off and units of distance through fun, travel-based contexts. The solutions include clear explanations, activities and step-by-step reasoning to build strong number sense. Ideal for revision and classroom learning, these answers follow the updated NCERT format.
Class 5 Maths Mela Chapter 1 Solutions
Class 5 Maths Mela Chapter 1 MCQ
Class 5 Math Magic Chapter 1 Solutions
Class 5 Maths all Chapters Solutions

We the Travellers I Class 5 Maths Mela Chapter 1 Solutions

Page 5

Let Us Do

1. Fill in the blanks by continuing the pattern in each of the following sequences. Discuss the patterns in class.

Class 5 Maths Mela Chapter 1 Question 1

Answer:

Class 5 Maths Mela Chapter 1 Answer 1

2. Fill in the blanks appropriately. Use commas as required.

Class 5 Maths Mela Chapter 1 Question 2

Answer:

Class 5 Maths Mela Chapter 1 Answer 2

3. Arrange the numbers below in increasing order. You can use the number line below, if required.

Class 5 Maths Mela Chapter 1 Question 3

See Solution18926, 34407, 34740, 40347, 40473, 47340, 73404, 74430

Class 5 Maths Mela Chapter 1 Answer 3

4. A student said 9,990 is greater than 49,014 because 9 is greater than 4. Is the student correct? Why or why not?
Use the number line below to find the position of the numbers. Fill in the blanks.

Class 5 Maths Mela Chapter 1 Question 4

See SolutionOn a number line, numbers increase as we move to the right. So, a number with more digits is always greater than a number with fewer digits.
9,990 has 4 digits
49,014 has 5 digits
So, 49,014 is much farther to the right on the number line than 9,990.
Even though 9 is greater than 4 in the first digit, we must compare the entire number, not just the first digit.

Class 5 Maths Mela Chapter 1 Answer 4

5. Digit swap
(a) In the number 1,478, interchanging the digits 7 and 4 gives 1,748. Now, interchange any two digits in the number 1,478 to make a number that is larger than 5,500.
See Solution(a) Original number: 1,478
Interchanged digits: 7 and 4 → 1,748 (Already done)
Now, try to find a number greater than 5,500 by swapping any two digits:
• Swap 1 and 8 → 8,471 (greater than 5,500)
• Swap 1 and 7 → 7,418 (greater than 5,500)
• Swap 1 and 4 → 4,178 (less than 5,500)
So, the Possible numbers greater than 5,500 are 8,471, and 7,418.

(b) Interchange two digits of 10,593 to make a number
i) Between 11,000 and 15,000.
ii) More than 35,000.
See Solution(b) Original number: 10,593
i) Between 11,000 and 15,000:
Try by swapping:
Swap 0 and 5 → 15,093
Swap 1 and 3 → 30,591
Swap 1 and 5 → 50,193
Swap 0 and 3 → 13,590 (Between 11,000 and 15,000)
So, the number between 11,000 and 15,000 is 13,590.
ii) More than 35,000:
Try by swapping:
Swap 1 and 5 → 50,193 (more than 35,000)
Swap 1 and 9 → 90,513 (more than 35,000)
Swap 0 and 9 → 19,503 (less than 35,000)
So, the numbers more than 35,000 are 50,193 and 90,513.

(c) Interchange two digits of 48,247 to make a number
i) As small as possible.
ii) As big as possible.
See Solution(c) Original number: 48,247
i) As small as possible:
We want smallest number → put smallest digits in the highest places.
Try by swapping:
Swap 4 and 2 → 28,447
Swap 4 and 7 → 78,247
Swap 4 and 8 → 84,247
Swap 8 and 2 → 42,847
So, the smallest number is 28,447.
ii) As big as possible:
We want largest number → put largest digits in the highest places.
Try by swapping:
Swap 4 and 2 → 28,447
Swap 4 and 7 → 78,247
Swap 4 and 8 → 84,247
Swap 8 and 2 → 42,847
So, the largest number is 84,247.

Class 5 Maths Mela Chapter 1 Question Answers

Page 8

Let Us Think

1. Vijay rounded off a number to the nearest hundred. Suma rounded off the same number to the nearest thousand. Both got the same result. Circle the numbers they might have used.

Class 5 Maths Mela Chapter 1 Question 5

See SolutionLet’s check each number one by one:
• 7126
Nearest hundred = 7100
Nearest thousand = 7000
Not same
• 7835
Nearest hundred = 7800
Nearest thousand = 8000
Not same
• 7030
Nearest hundred = 7000
Nearest thousand = 7000
Same
• 6999
Nearest hundred = 7000
Nearest thousand = 7000
Same
So, they might used 7030 or 6999.

Class 5 Maths Mela Chapter 1 Answer 5

2. Think and write two numbers that have the same –
(a) Nearest ten.
See Solution(a) Nearest Ten: 38 and 42
Both round off to 40 (nearest ten)

(b) Nearest hundred.
See Solution(b) Nearest Hundred: 248 and 198
Both round off to 200 (nearest hundred)

(c) Nearest thousand.
See Solution(c) Nearest Thousand: 3,426 and 3,499
Both round off to 3,000 (nearest thousand)

3. Think and write the numbers that have the same –
(a) Nearest ten and nearest hundred.
See Solution(a) Same Nearest Ten and Nearest Hundred: 195 and 204
Both round to 200 (nearest ten)
Both also round to 200 (nearest hundred)

(b) Nearest hundred and nearest thousand.
See Solution(b) Same Nearest Hundred and Nearest Thousand: 949 and 915
Both round to 1,000 (nearest thousand)
Both also round to 1,000 (nearest hundred)

(c) Nearest ten, hundred and thousand.
See Solution(c) Same Nearest Ten, Hundred and Thousand: 1,000 and 1,004
Both round to 1,000 for nearest ten, hundred and thousand.

Page 10

Let Us Do

1. A cyclist can cover 15 km in one hour. How much distance will she cover in 4 hours, if she maintains the same speed?
See SolutionA cyclist goes 15 kilometres in 1 hour.
So, in 4 hours, she will go 15 × 4
= 60 kilometres

2. A school has 461 girls and 439 boys. How many vehicles are needed for all of them to go on a trip using the following modes of travel?
The numbers in the bracket indicates the number of people that can travel in one vehicle.
(a) Bicycle ( 2)
(b) Autorickshaw ( 3)
(c) Car ( 4)
(d) Big car ( 6)
(e) Tempo traveller (10)
(f) Boat ( 20)
(g) Minibus ( 25)
(h) Aeroplane (180)
See SolutionNumber of Girls = 461
Number of Boys = 439
Total number of students = 461 + 439 = 900
Now we divide 900 by the number of people each vehicle can carry to find how many vehicles are needed. If there’s any remainder, we add 1 extra vehicle.
(a) Bicycle (2 people)
So, 900 ÷ 2 = 450 bicycles
(b) Autorickshaw (3 people)
So, 900 ÷ 3 = 300 autorickshaws
(c) Car (4 people)
So, 900 ÷ 4 = 225 cars
(d) Big car (6 people)
So, 900 ÷ 6 = 150 big cars
(e) Tempo traveller (10 people)
So, 900 ÷ 10 = 90 tempo travellers
(f) Boat (20 people)
So, 900 ÷ 20 = 45 boats
(g) Minibus (25 people)
So, 900 ÷ 25 = 36 minibuses
(h) Aeroplane (180 people)
So, 900 ÷ 180 = 5 aeroplanes

Grade 5th Maths Mela Chapter 1 Answer Explanation

Page 13

Let Us Do

1. Write 5 numbers between the numbers 23,568 and 24,234.
________, _______, ________, ________ and _______
See SolutionThe 5 numbers between 23,568 and 24,234:
23600, 23750, 23890, 24000 and 24123

2. Write 5 numbers that are more than 38,125 but less than 38,600.
________, ________, ________, ________ and ________
See SolutionThe 5 numbers that are more than 38,125 but less than 38,600:
38200, 38310, 38420, 38500 and 38590

3. Ravi’s car has been driven for 56,987 km till now. Sheetal’s car has been driven 67,543 km. Whose car has been driven more? ____________.
See SolutionComparing the distances:
Distance traveled by Ravi’s car = 56,987 km
Distance traveled by Sheetal’s car = 67,543 km
Since 67,543 > 56,987,
So, Sheetal’s car has been driven more.
Now, 67,543 − 56,987 = 10,556
So, Sheetal’s car has been driven 10,556 more than Ravi.

4. The following are the prices of different electric bikes. Arrange the prices in ascending (increasing) order.
₹90000, ₹89999, ₹94983, ₹49900, ₹93743, ₹39999
See SolutionPrices of different electric bikes in increasing order:
₹39999, ₹49900, ₹89999, ₹90000, ₹93743, ₹94983

5. The following table shows the population of some towns. Arrange them in a descending (decreasing) order.

Class 5 Maths Mela Chapter 1 Question 6

See SolutionDescending order: 66540, 65232, 56380, 53231, 51336, 45858
Descending order: Town 6, Town 1, Town 3, Town 2, Town 4, Town 5

Class 5 Maths Mela Chapter 1 Question 6 and 7

6. Find numbers between 42,750 and 53,500 such that the ones, tens and hundreds digits are all 0?____________.
See SolutionNumbers between 42750 and 53500, whose ones, tens and hundreds digits are all 0:
43000, 44000, 45000, 46000, 47000, 48000, 49000, 50000, 51000, 52000 and 53000.

7. Write the following numbers in the expanded form. One has been done for you.
(a) 783 = 700 + 80 + 3
(b) 8,062 = ____________.
(c) 9,980 = ____________.
(d) 10,304 = ____________.
(e) 23,004 = ____________.
(f) 70,405 = ____________.
See SolutionExpanded form:
(a) 783 = 700 + 80 + 3 (Already done)
(b) 8,062 = 8000 + 60 + 2
(c) 9,980 = 9000 + 900 + 80
(d) 10,304 = 10000 + 300 + 4
(e) 23,004 = 20000 + 3000 + 4
(f) 70,405 = 70000 + 400 + 5

Grade 5 Maths Mela Chapter 1 All Questions

8. Fill in the blanks with the correct answer. Share your thoughts in class.
(a) 983 = 90 Tens + 83 Ones
(b) 68 = ___ Tens + 18 Ones
(c) 607 = 4 Hundreds + ___ Ones
(d) 5,621 = 4 Thousand + ___ Hundreds + 2 Tens + ___ Ones
(e) 7,069 = ___ Thousand + 20 Hundreds + ___ Ones
(f) 37,608 = ___ Ten Thousand + 17 Thousand + ___ Hundreds + 8 Ones
(g) 43,001 = 3 Ten Thousand + ____ Thousand + ____ Hundreds + 1 Ones
See Solution(a) 983 = 90 Tens + 83 Ones
(b) 68 = 5 Tens + 18 Ones
(c) 607 = 4 Hundreds + 201 Ones
(d) 5,621 = 4 Thousand + 16 Hundreds + 2 Tens + 1 Ones
(e) 7,069 = 5 Thousand + 20 Hundreds + 69 Ones
(f) 37,608 = 2 Ten Thousand + 17 Thousand + 6 Hundreds + 8 Ones
(g) 43,001 = 3 Ten Thousand + 10 Thousand + 30 Hundreds + 1 Ones

9. Fill in the blanks with the correct answers.
(a) How many notes of ₹10 are there in ₹7,934? 793
(b) How many notes of ₹100 are there in ₹7,934? _______
(c) How many thousands are there in 7,934? _______
(d) How many ₹500 notes are there in ₹7,934? _______
(e) How many notes of ₹10 are there in ₹65,342? _______
(f) How many notes of ₹100 are there in ₹65,342? _______
(g) How many thousands are there in 65,342? _______
(h) How many ₹500 notes are there in ₹65,342? _______
See Solution(a) ₹7,934 ÷ ₹10 = 793 notes of ₹10 (Already given)
(b) ₹7,934 ÷ ₹100 = 79 notes of ₹100
(100 × 79 = ₹7,900)
(c) ₹7,934 has 7 thousands
(1,000 × 7 = ₹7,000)
(d) ₹7,934 ÷ ₹500 = 15 notes
(500 × 15 = ₹7,500)
(e) ₹65,342 ÷ ₹10 = 6,534 notes of ₹10
(f) ₹65,342 ÷ ₹100 = 653 notes of ₹100
(g) ₹65,342 has 65 thousands
(1,000 × 65 = ₹65,000)
(h) ₹65,342 ÷ ₹500 = 130 notes of ₹500
(500 × 130 = ₹65,000)

Is Class 5 Maths Mela Chapter 1 easy?

Yes, Chapter 1 is quite easy and fun to learn. It uses real-life travel situations to explain big numbers, distances and place values. With number lines, charts and puzzles, the concepts become simple to understand.

How to solve Class 5 Maths Mela Chapter 1 in one day?

To complete the chapter in one day:
• Read the story and examples carefully.
• Solve the place value table and number patterns.
• Practice rounding off and comparison questions.
• Try the puzzles and activities at the end.

Which topic of Class 5 Maths Mela Chapter 1 is most important?

The most important topic is reading and writing large numbers using the Indian place value system, especially up to ten-thousands, along with rounding off and distance estimation.

What are the key points of Class 5 Maths Chapter 1 for Exams?

• Place value (Ones to Ten-thousands)
• Reading and writing numbers with commas
• Expanded and short forms
• Number comparison and ordering
• Rounding off to nearest tens, hundreds, and thousands
• Simple distance and travel-related calculations
These are frequently asked in exams.

Content Reviewed: August 8, 2025
Content Reviewer

Mayank Tiwari

I have completed my M. Tech. in Computer Science and Engineering, Specialization in Artificial Intelligence in Delhi. Since, then I am working for Tiwari Academy as quality manager in Tech and Content formation.