# NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.5

NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.5 Number Systems download in Hindi Medium and English Medium free to download in PDF form for session 2021-22 updated according to new CBSE Curriculum.

NCERT Solutions 2021-2022 are available to View in Video Format or use it online only. NCERT Solutions for 9 Maths are given on one page to download. These solutions are further updated according to CBSE Syllabus 2021-22 academic session. Download (Exercise 1.5 ) in PDF format to use it offline.## NCERT Solutions for Class 9 Maths Chapter 1 Exercise 1.5

Class: 9 | Maths – Number Systems |

Chapter 1: | Exercise 1.5 |

### 9th Maths Chapter 1 Exercise 1.5 Sols

Here the solutions are given to use online, if you want to download these solutions in English Medium PDF format follow the link given at the top of the page. Go back to Class 9 Maths Chapter 1 Solutions main page to see other exercises. All the solutions are updated for new academic session 2021-2022 on the basis of latest NCERT Books 2021-22.

#### Class 9 Maths Chapter 1 Exercise 1.5 Solution in Videos

#### Class 9 Maths Chapter 1 Exercise 1.5 Solution

#### 9th Maths Exercise 1.5 Solutions in Hindi & English

NCERT Solutions of Maths in Hindi Medium as well as English Medium are updated for new academic session 2021-22 and free to download in PDF. These solutions are prepared on the basis of new NCERT Books 2021-22 for CBSE and UP Board Students. Go back to Class 9 Maths Chapter 1 main page solutions to see other exercises.

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###### Important Questions on 9th Maths Exercise 1.5

1. Check whether the following number is rational or irrational number. √5×√125

2. Add √225 + 2√27 and -5√5 – √3.

3. Rationalize the denominator: 1/[√3 + √5 + √7].

4. If a = [√7 – √6]/[√7 + √6] and b = [√7 + √6]/[√7 – √6], then find the value of a² + b² + ab.

5. nimnalikhit ko saral keejie: √45 – 3√20 + √45.

6. nimnalikhit ke har ka parimeyeekaran keejie: √40/√3.

7. nimnalikhit mein a aur b ke maan gyaat keejie keejie: [5 + 2√3]/[7 + 4√3] = a – 6√3.

8. nimnalikhit ke har ka parimeyeekaran keejie aur phir √2 = 1.414, √3 = 1.732 aur √5 = 2.236 lete hue, teen dashamalav sthaanon tak [√10 – √5]/ √3 ka maan gyaat keejie.

9. yadi √2 = 1.414 hai to √8 + √50 + √72 + √98 ka maan gyaat keejie.

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