To make a conical tent of height 8 m and base radius 6 m, first calculate the slant height using Pythagoras’ theorem: l = √[8² + 6²] = √[64 + 36] = √[100] = 10 m. The curved surface area is 3.14 × 6 × 10 = 188.4 m². For a 3 m wide tarpaulin, the length needed is 188.4/3 ≈ 62.8 m. Adding 20 cm for margins, the total length required is approximately 63 m.

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## Introduction to Tent Construction

Constructing a conical tent requires a thorough understanding of geometry and material estimation. In this scenario, we are tasked with determining the length of tarpaulin needed to create a conical tent with specific dimensions. The tent’s height is 8 meters, and the radius of its base is 6 meters. Additionally, we must account for extra material for stitching margins and wastage, which is a common consideration in practical applications.

### Calculating the Slant Height

The first step in our calculation is to determine the slant height of the tent. The slant height is the distance from the top of the tent (vertex) to the edge of the base, measured along the surface of the tent. This can be calculated using Pythagoras’ theorem, which states that in a right-angled triangle, the square of the hypotenuse (slant height) is equal to the sum of the squares of the other two sides (height and radius).

#### Applying Pythagoras’ Theorem

For our conical tent, the height (h) is 8 meters, and the radius (r) is 6 meters. Using Pythagoras’ theorem, the slant height (l) is calculated as l = √[h² + r²]. Substituting the given values, we find l = √[8² + 6²] = √[64 + 36] = √[100] = 10 meters.

#### Determining the Curved Surface Area

The next step is to calculate the curved surface area of the tent, which is essential for determining the amount of tarpaulin required. The curved surface area of a cone is given by the formula πrl. With a radius of 6 meters and a slant height of 10 meters, the curved surface area is 3.14 × 6 × 10 = 188.4 square meters.

##### Calculating the Required Tarpaulin Length

Given that the tarpaulin is 3 meters wide, the length of tarpaulin needed can be calculated by dividing the total curved surface area by the width of the tarpaulin. Therefore, the length required is 188.4/3 ≈ 62.8 meters. However, we must also consider additional material for stitching margins and wastage.

###### Final Calculation and Practical Considerations

Taking into account an extra 20 cm for margins and wastage, the total length of tarpaulin required is approximately 63 meters. This calculation is crucial for efficient use of materials and cost estimation in the construction of the tent. It demonstrates the practical application of geometric principles in real-world scenarios, emphasizing the importance of accuracy in measurements and allowances for additional material in manufacturing processes.

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Questions of 9th Maths Exercise 11.1 in Detail

 Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area. Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m. Curved surface area of a cone is 308 cm² and its slant height is 14 cm. Find (i) radius of the base and (ii) total surface area of the cone. A conical tent is 10 m high and the radius of its base is 24 m. Find (i) slant height of the tent. (ii) Cost of the canvas required to make the tent, if the cost of 1 m² canvas is ₹70. What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (Use π = 3.14). The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of white-washing its curved surface at the rate of ₹210 per 100 m². A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps. A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is ₹12 per m², what will be the cost of painting all these cones?

Last Edited: January 2, 2024