NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 Differential Calculus free to use online or Download in Hindi Medium for CBSE, Uttarakhand, Bihar, MP Board & UP Board using NCERT Books in Hindi and English Medium for those students who are using NCERT Books in English.




NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6

12 Maths Chapter 5 Exercise 5.6 Solutions in English

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 in English Medium. In this exercise, we have to learn about differentiation of parametric equation (When two variables are expressed in the terms of third variable, the third variable is called parameter). Click here to get the solutions of other exercises of Class 12 Mathematics Chapter 5, If you need Solutions in Hindi, CLICK HERE for Hindi Medium Solutions.

12 Maths Chapter 5 Exercise 5.6 Differential Calculus




12 Maths Chapter 5 Exercise 5.6 Differential Calculus in English medium

12 Maths Chapter 5 Exercise 5.6 Differential Calculus in PDF for 2018-2019



12 Maths Chapter 5 Exercise 5.6 Differential Calculus updated for CBSE & UP Board students

12 Maths Chapter 5 Exercise 5.6 Solutions के हल हिंदी में

कक्षा १२ के पाठ ५ प्रशनावली ५.६ के हल में हम फलनों के प्राचलिक रूपों के अवकलज ज्ञात करना सीखते हैं। इन प्रश्नों में दो चर राशिओं x और y में एक तीसरी चर राशि की सहायता से संबंध बनाया जाता है। यह तीसरी राशि ही प्राचल कहलाती है। Click here to get the solutions of other exercises of Class 12 Mathematics Chapter 5, Go back to English Medium Solutions.

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 in Hindi medium



NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 Updated for 2018-19

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 Questions 1, 2, 3, 4, 5, 6, 7, 8, 9, 10



12 Maths Exercise 5.6 in Hindi for CBSE and UP Board 2019

Go Back to Top of English Medium Solutions & Hindi Medium Solutions.



About 12 Maths Exercise 5.6

12 Maths Exercise 5.6 is based on parametric equation. Variables x and y are connected with the help of the third variable called parameter. In this exercise the symbols t and θ are used as parameters. In order to get the expression for dy/dx, we have to find dy/dt and dx/dt and then divide them to get dy/dx. The questions asked in examination is mostly of second degree like d²y/dx² using parameter. In this case find the expression for dy/dx, and then find d²y/dx² keeping in mind the second derivative is with respect to x not t, so we must multiply with dt/dx (as per the chain rule). For example: d²y/dx² = [dy/dx]/[dx/dt]. [dt/dx]


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