# NCERT Solutions for Class 12 Maths Chapter 5

NCERT Solutions for class 12 Maths chapter 5 Continuity and Differentiability all exercises (ex. 5.1, 5.2, 5.3, 5.4, 5.5, 5.6, 5.7, 5.8 and miscellaneous exercise) English Medium and Hindi Medium. All the NCERT sols are updated for academic session 2020-21 for all boards who are following NCERT Books for their course. CBSE Solutions are in the format of PDF file and Video. Videos related to Class 12 Mathematics chapter 5 all exercises are given below in Hindi and English Medium. UP Board Students also using the same NCERT textbooks as CBSE Students. So, these solutions are useful for those also in solving their doubts.

Download UP Board Solutions for Class 12 Maths Chapter 5 in Hindi and English Medium. NCERT Solutions and corresponding Offline Apps are also available to free download. All the contents on this website are free to use.## NCERT Solutions for class 12 Maths chapter 5

Class: 12 | Maths (English and Hindi Medium) |

Chapter 5: | Continuity and Differentiability |

### 12th Maths Chapter 5 Solutions

NCERT Solutions for class 12 Maths chapter 5 Continuity and Differentiability all exercises with miscellaneous exercises in Hindi and English Medium free to download. Download NCERT Books for class 12 all subjects for 2020-21 based on latest CBSE Syllabus. Join the discussion forum to ask the doubts related to NIOS and CBSE Board.

### Class 12 Maths Chapter 5 Solutions in English Medium

- Class 12 Maths Exercise 5.1 Solutions
- Class 12 Maths Exercise 5.2 Solutions
- Class 12 Maths Exercise 5.3 Solutions
- Class 12 Maths Exercise 5.4 Solutions
- Class 12 Maths Exercise 5.5 Solutions
- Class 12 Maths Exercise 5.6 Solutions
- Class 12 Maths Exercise 5.7 Solutions
- Class 12 Maths Exercise 5.8 Solutions
- Class 12 Maths Miscellaneous Exercise 5

### Class 12 Maths Chapter 5 Solutions in Hindi Medium

- Class 12 Maths Exercise 5.1 Solutions in Hindi
- Class 12 Maths Exercise 5.2 Solutions in Hindi
- Class 12 Maths Exercise 5.3 Solutions in Hindi
- Class 12 Maths Exercise 5.4 Solutions in Hindi
- Class 12 Maths Exercise 5.5 Solutions in Hindi
- Class 12 Maths Exercise 5.6 Solutions in Hindi
- Class 12 Maths Exercise 5.7 Solutions in Hindi
- Class 12 Maths Exercise 5.8 Solutions in Hindi
- Class 12 Maths Miscellaneous Exercise 5 Solutions in Hindi
- Class 12 Maths Solutions Main Page

### Class 12 Maths Chapter 5 Solutions in PDF

- Download Class 12 Maths Exercise 5.1 in PDF
- Download Class 12 Maths Exercise 5.2 in PDF
- Download Class 12 Maths Exercise 5.3 in PDF
- Download Class 12 Maths Exercise 5.4 in PDF
- Download Class 12 Maths Exercise 5.5 in PDF
- Download Class 12 Maths Exercise 5.6 in PDF
- Download Class 12 Maths Exercise 5.7 in PDF
- Download Class 12 Maths Exercise 5.8 in PDF
- Download Class 12 Maths Miscellaneous Exercise 5
- Class 12 Maths NCERT Book Chapter 5
- Class 12 Maths NCERT Book Answers
- Class 12 Maths Revision Book Chapter 5
- Class 12 Maths Revision Book Answers
- Download Class 12 Maths Assignment 1
- Download Class 12 Maths Assignment 2
- Download Class 12 Maths Assignment 2 Answers
- Download Class 12 Maths Assignment 3
- Download Class 12 Maths Assignment 4

#### Class 12 Maths Exercise 5.1 Solutions in Videos

#### Class 12 Maths Exercise 5.2 Solutions in Videos

#### Class 12 Maths Exercise 5.3 Solutions in Videos

#### Important Terms related to Chapter 5

- The main points of the chapter are continuous functions, algebra of continuous functions, differentiation and continuity, chain rule, rules for derivative of inverse functions, derivative of implicit function, parametric and logarithmic functions. Second order derivatives, mean value theorems (LMV) and Rolle’s Theorem.
- Calculus (differentiability) deals with related variables and constants. In differential calculus we investigate the way in which ‘one quantity varies when the other related quantity is made to vary’. We find the rate of change (in Application of derivatives) one variable quantity relative to another variable. The relation between a function and its derivative is same as between displacement of a particle and its velocity.
- The derivative of f(x) at x = a is represented by the slope (gradient) of the tangent to the curve y = f(x) at the point P[a, f(a)].

##### ROLLE’S THEOREM

Let f be a real function defined in the closed interval [a, b] such that

(i) f is continuous in the closed interval [ a, b ]

(ii) f is differentiable in the open interval ( a, b )

(iii) f (a) = f (b)

Then f'(c) = 0, where c lies in (a, b).

###### MEAN VALUE THEOREM

Let f be a real valued function defined on the closed interval [a, b] such that

(a) f is continuous on [a, b], and

(b) f is differentiable in (a, b)

Then there exists a point c in the open interval (a, b) such that f ‘(c) = [f (b) – f (a)]/[b – a]

### Important Questions on 12th Maths Chapter 5

Differentiating both sides with respect to x, we get

d/dx (2x) + d/dx (3y) = d/dx sinx

⇒ 2+3 dy/dx = cosx

⇒ dy/dx = (cosx-2)/3

इसलिए,

dy/dx = cos〖(x^2+5).d/dx〗 (x^2+5)

= cos(x^2+5).2x

dy/dx = d/dx (x^2+3x+2)

=2x+3

⇒(d^2 y)/(dx^2 )

= d/dx (2x+3)=2

dy/dx=d/dx (3 cos〖(logx )+4 sin〖(logx)〗 〗 )

=-3 sin〖(logx ).1/x+4 cos〖(logx ).〗 〗 1/x

⇒x dy/dx=-3 sin〖(logx )+4 cos(logx ) 〗

⇒x (d^2 y)/(dx^2 )+dy/dx.d/dx x

=d/dx [-3 sin〖(logx )+4 cos(logx ) 〗 ]

=-3 cos〖(logx ).1/x-4 sin(logx ) 〗.1/x

=-1/x [3 cos〖(logx )+4 sin(logx ) 〗 ]=-1/x.y

⇒x (d^2 y)/(dx^2 )+dy/dx=-1/x y

⇒x^2 (d^2 y)/(dx^2 )+x dy/dx=-y

⇒x^2 (d^2 y)/(dx^2 )+x dy/dx+y=0

⇒x^2 y_2+xy_1+y=0

(i) फलन f एक बहुपद है। अतः, यह संवृत अंतराल [-4,2] में संतत है।

(ii) f'(x)=2x+2

अतः, फलन f विवृत अंतराल (-4,2) में अवकलनीय है।

(iii) f(-4)=(-4)^2+2(-4)-8=16-8-8=0

तथा f(2)=(2)^2+2(2)-8=4+4-8=0

⇒f(-4)=f(2)

यहाँ, रोले की तीनों परिस्थितियाँ सत्य हैं। इसलिए, विवृत अंतराल (-4,2) में किसी ऐसे c का अस्तित्व है कि f'(c)=0 है।

⇒f^’ (c)=2c+2=0

⇒c=-1∈(-4,2)

अतः, फलन f(x)=x^2+2x-8,x∈[-4,2] के लिए रोले की प्रमेय सत्यापित हो जाती है।

Putting n=1, we have LHS=d/dx (x^1 )=1 and RHS=1x^(1-1)=x^0=1

Hence, P(n) is true for n=1.

Let, P(k):d/dx (x^k )=kx^(k-1) is true.

To prove:

P(k+1):d/dx (x^(k+1) )=(k+1)x^k is also true.

LHS

=d/dx (x^(k+1) )

=d/dx (x^k.x)

=x^k d/dx (x)+x d/dx x^k

=x^k.1+x.kx^(k-1)

=(1+k) x^k

=RHS

Hence, P(n) is true for n=k+1.

Therefore, by the principle of Mathematical Induction P(n) is true for all natural numbers n.