# NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 (Class XII ex. 5.6) Differential Calculus free to use online or Download. 12th Maths solutions are in Hindi Medium and English Medium for CBSE, Uttarakhand, Bihar, MP Board and UP Board students who are using updated NCERT Books for new academic year 2021-2022. UP Board intermediate students are now using NCERT book for their exams, so they also take help from these contents given in PDF. Download UP Board Solutions for class 12 Maths Exercise 5.6 in PDF here without any registration. Videos related to CBSE Solutions are also given in Hindi and English Medium.

All the questions are solved one by one in a separate video in Hindi and English, so that student can solve their doubts using particular video. Visit to discussion forum to ask your questions and give response to questions asked by other users.## NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6

### Class 12 Maths Exercise 5.6 Solutions in Hindi and English Medium

Class: 12 | Maths (English and Hindi Medium) |

Chapter 5: | Exercise 5.6 |

### 12th Maths Exercise 5.6 Solutions

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 in English and Hindi Medium are given below based on latest NCERT Books 2021-22. In this exercise, we have to learn about differentiation of parametric equation (When two variables are expressed in the terms of third variable, the third variable is called parameter).

#### Class 12 Maths Exercise 5.6 Question 1, 2, 3, 4 Solution in Videos

#### Class 12 Maths Exercise 5.6 Question 5, 6, 7 Solution in Videos

#### Class 12 Maths Exercise 5.6 Question 8, 9 Solution in Videos

#### Class 12 Maths Exercise 5.6 Question 10, 11 Solution in Videos

#### Class 12 Maths Exercise 5.6 Question 1 to 6 in Hindi Videos

#### Class 12 Maths Exercise 5.6 Question 7, 8, 9 in Hindi Videos

#### Class 12 Maths Exercise 5.6 Question 10, 11 in Hindi Videos

##### About 12 Maths Exercise 5.6

12 Maths Exercise 5.6 is based on parametric equation. Variables x and y are connected with the help of the third variable called parameter. In this exercise the symbols t and θ are used as parameters. In order to get the expression for dy/dx, we have to find dy/dt and dx/dt and then divide them to get dy/dx. The questions asked in examination is mostly of second degree like d²y/dx² using parameter. In this case find the expression for dy/dx, and then find d²y/dx² keeping in mind the second derivative is with respect to x not t, so we must multiply with dt/dx (as per the chain rule). For example: d²y/dx² = [dy/dx]/[dx/dt]. [dt/dx]

###### Feedback and Suggestions

NCERT Solutions 2021-2022 are now updated for new academic session based on new NCERT Books and following the latest CBSE Syllabus. If there is any error, please inform us, we will try to rectify very soon. You can raise your problem in discussion forum regarding to NIOS or CBSE board.