# NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 (Class XII ex. 5.6) Differential Calculus free to use online or Download. 12th Maths solutions are in Hindi Medium and English Medium for CBSE, Uttarakhand, Bihar, MP Board and UP Board students who are using updated NCERT Books for new academic year 2020-2021. UP Board intermediate students are now using NCERT book for their exams, so they also take help from these contents given in PDF. Download UP Board Solutions for class 12 Maths Exercise 5.6 in PDF here without any registration. Videos related to CBSE Solutions are also given in Hindi and English Medium.

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## NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6

Class: 12 | Maths (English and Hindi Medium) |

Chapter 5: | Exercise 5.6 |

### Class 12 Maths Exercise 5.6 Solutions in Hindi and English Medium

### 12th Maths Exercise 5.6 Solutions

NCERT Solutions for Class 12 Maths Chapter 5 Exercise 5.6 in English and Hindi Medium are given below based on latest NCERT Books 2020-21. In this exercise, we have to learn about differentiation of parametric equation (When two variables are expressed in the terms of third variable, the third variable is called parameter). कक्षा १२ के पाठ ५ प्रशनावली ५.६ के हल में हम फलनों के प्राचलिक रूपों के अवकलज ज्ञात करना सीखते हैं। इन प्रश्नों में दो चर राशिओं x और y में एक तीसरी चर राशि की सहायता से संबंध बनाया जाता है। यह तीसरी राशि ही प्राचल कहलाती है।

#### Class 12 Maths Exercise 5.6 Question 1, 2, 3, 4 Solution in Videos

#### Class 12 Maths Exercise 5.6 Question 5, 6, 7 Solution in Videos

#### Class 12 Maths Exercise 5.6 Question 8, 9 Solution in Videos

#### Class 12 Maths Exercise 5.6 Question 10, 11 Solution in Videos

#### Class 12 Maths Exercise 5.6 Question 1 to 6 in Hindi Videos

#### Class 12 Maths Exercise 5.6 Question 7, 8, 9 in Hindi Videos

#### Class 12 Maths Exercise 5.6 Question 10, 11 in Hindi Videos

##### About 12 Maths Exercise 5.6

12 Maths Exercise 5.6 is based on parametric equation. Variables x and y are connected with the help of the third variable called parameter. In this exercise the symbols t and θ are used as parameters. In order to get the expression for dy/dx, we have to find dy/dt and dx/dt and then divide them to get dy/dx. The questions asked in examination is mostly of second degree like d²y/dx² using parameter. In this case find the expression for dy/dx, and then find d²y/dx² keeping in mind the second derivative is with respect to x not t, so we must multiply with dt/dx (as per the chain rule). For example: d²y/dx² = [dy/dx]/[dx/dt]. [dt/dx]

###### Feedback and Suggestions

NCERT Solutions 2020-2021 are now updated for new academic session based on new NCERT Books and following the latest CBSE Syllabus. If there is any error, please inform us, we will try to rectify very soon. You can raise your problem in discussion forum regarding to NIOS or CBSE board.