NCERT Solutions for Class 11 Maths Chapter 3 Trigonometric Functions

NCERT Solutions for Class 11 Maths Chapter 3 Trigonometric Functions in English and Hindi Medium following the new session 2022-2023.

11th Maths Chapter 3 Solutions in English Medium

11th Maths Chapter 3 Solutions in Hindi Medium

Class 11 Chapter 3 all Exercises Solution

NCERT Solutions for Class 11 Maths Chapter 3

NCERT Solutions for Class 11 Maths Chapter 3 Trigonometric Functions are given below to download in PDF or use online in Hindi and English Medium. Contents are updated for academic session 2022-23 for UP Board, MP Board, CBSE and all other boards who are using the latest books for 11th class available on NCERT (https://ncert.nic.in/) website 2022-23 as their course books.

Class 11 all Subjects App

Class: 11	Maths Solutions
Chapter 3:	Trigonometric Functions
Content:	Exercises and Supplementary
Mode:	Online Text and Videos format
Medium:	English and Hindi Medium

Questions for Practice

Write the value of 2sin 75° sin 15°?
What is the maximum value of 3 – 7 cos 5x?
Express sin 12A + sin 4A as the product of sines and cosines.
Express 2 cos 4x sin 2x as an algebraic sum of sines and cosines
Write the maximum value of cos (cos x).
Write the minimum value of cos (cos x).
Write the radian measure of 22° 30’
Find the length of an arc of a circle of radius 5cm subtending a central angle measuring 15°.

Class 11 Maths Chapter 3 Important Questions for Practice

1. Find the maximum and minimum value of 7 cos x + 24 sin x
2. Evaluate sin(π + x) sin(π – x) cosec² x
3. Find the angle in radians between the hands of a clock at 7 : 20 pm.
4. A horse is tied to a post by a rope. If the horse moves along a circular path, always keeping the rope tight and describes 88 metres when it traces 72° at the centre, find the length of the rope.
5. Draw sin x, sin 2x and sin 3x on same graph and with same scale.

Feedback & Suggestions

Important Questions on 11th Maths Chapter 3

Find the radian measures corresponding to 25°.

We know that 180° = π radians
Therefore, 25° = π/180 × 25 radians
= 5π/36 radians
Hence, 25° = 5π/36 radians.

A wheel makes 360 revolutions in one minute. Through how many radians does it turn in one second?

Number of revolutions in one minute (60 seconds) = 360
Therefore, number of revolutions in 1 seconds = 360/60 = 6
We know that the angle formed in one revolutions = 360° = 2π radians
Therefore, the angle formed in 6 revolutions = 6 × 2π = 12π radians
Hence, it will turn 12π radians in one second.

Find the degree measure of the angle subtended at the centre of a circle of radius 100 cm by an arc of length 22 cm (Use π = 22/7).

Here, radius r=100 cm, length of arc l=22 cm
Hence, using the relation θ =l/r we have
θ = 22/100 radians
= 11/50 radians
We know that π radians =180°
Therefore, 11/50 radians
= 180/π × 11/50 degree
= (180 × 7)/22 × 11/50 degree
= 63/5 degree
= 12 3/5 degree
= 12° + 3/5 × 60 minutes [∵ 1° = 60′]
= 12° + 36 minutes
= 12° + 36’= 12°36′
Hence, the angle formed by are at the centre is 12°36′.

Prove that: sin²π/6 + cos²π/3 – tan²π/4 = -1/2

LHS = sin²π/6 + cos²⁡π/3 – tan²⁡π/4
= (1/2)² + (1/2)² – (1)²
= 1/4 + 1/4 – 1
= 1/2 – 1
= – 1/2
= RHS

Prove that: sin⁡(n+1)x sin⁡(n + 2)x + cos⁡(n+1)x cos⁡(n+2)x = cos⁡x

LHS = sin⁡(n+1)x sin⁡(n+2)x + cos⁡(n+1)x cos⁡(n+2)x
= cos⁡[(n+2)x-(n+1)x] [∵cos⁡A cos⁡B + sin⁡A sin⁡B = cos⁡(A-B)]
= cos⁡[nx + 2x – nx – x]
= cos⁡x
= RHS

Prove that: cos⁡4x = 1 – 8 sin²⁡x cos²⁡x

LHS = cos⁡4x = cos⁡2(2x)
= 1 – 2sin²(⁡2x)
= 1-2(sin⁡2x)² [∵cos⁡2A = 1 – 2sin²⁡A ]
= 1 – 2(2sin⁡x cos x)² [∵sin⁡2A = 2 sin⁡A cos⁡A ]
= 1 – 2(4sin²⁡x cos²⁡x ) = 1 – 8sin²⁡x cos²⁡x
= RHS

Prove that: cos⁡6x = 32 cos⁶x – 48 cos⁴⁡x + 18 cos²⁡x – 1

LHS = cos⁡6x
= cos⁡2(3x)
= 2cos²(⁡2x) – 1 [∵ cos⁡2A = 2 cos²A – 1]
= 2(4 cos³⁡x – 3 cos⁡x )² – 1 [∵ cos⁡3A = 4 cos³A – 3 cos A]
= 2(16 cos⁶⁡x + 9 cos²⁡x – 24 cos⁴⁡x ) -1
= 32 cos⁶x – 48 cos⁴⁡x + 18 cos²⁡x – 1 = RHS

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Which questions of chapter 3 of class 11th Maths can students expect in the school exams?

Students can expect the following questions of chapter 3 of class 11th Maths in the school exams:

Questions 1, 2, and 4 of exercise 3.1.
Questions 1, 3, 4, 7, 8, 9, and 10 of exercise 3.2.
Questions 2, 3, 5, 6, 8, 9, 11, 18, 21, 22, and 23 of exercise 3.3.
Questions 3, 4, 5, 6, 7, 8, and 9 of exercise 3.4.
Questions 1, 2, 4, 6, 7, 8, 9, and 10 of miscellaneous exercise on chapter 3.
Examples 5, 6, 7, 9, 11, 16, 17, 19, 22, 24, 25, 26, 27, 28, and 29.

Does chapter 3 of Class 11 Maths has any miscellaneous exercise?

Yes, chapter 3 (Trigonometric Functions) of grade 11th Maths has a miscellaneous exercise. There are five exercises in chapter 3 of class 11th Maths, and the last exercise is the miscellaneous exercise of chapter 3 of grade 11th Maths.

From which books other than NCERT students can practice extra questions of chapter 3 of class 11th Maths?

There are some books other than NCERT from which students can practice extra questions of chapter 3 of class 11th Maths. The names of these books are Exemplar porblems, R.L. Arora, R.D. Sharma, R.S. Aggarwal. These books are the best books after NCERT and NCERT Exemplar. The languages of these books are students friendly. Students can easily prepare chapter 3 of class 11th Maths from these books. Students can also see the previous year’s question papers.

Is there any chapter which students should revise before starting chapter 3 of 11th NCERT Maths?

Before starting chapter 3 (Trigonometric Functions) of 11th standard Maths, students should revise chapter 8 (Introduction to Trigonometry) of grade 10th Maths. Chapter 8 of class 10th Maths works as a base for chapter 3 of class 11th Maths.