on April 14, 2023, 5:41 AM
NCERT Solutions for Class 6 Maths Chapter 8 Exercise 8.4 in Hindi and English Medium updated for CBSE 2024-25. The solutions of ex. 8.4 class 6 Maths are revised according to new rationalised syllabus and latest NCERT books issued for academic session 2024-25.
6th Maths Exercise 8.4 Solutions in Hindi and English Medium
| Class: 6 | Mathematics |
| Chapter: 8 | Exercise: 8.4 |
| Topic Name: | Decimals |
| Content: | Solutions of all the Questions |
| Session: | CBSE 2024-25 |
| Medium: | Hindi and English Medium |
Class 6 Maths Chapter 8 Exercise 8.4 Solution
Class VI Mathematics Ex. 8.4 of NCERT Chapter 8 Decimals in Hindi and English Medium free to use online or download in PDF file format for CBSE Board. All the solutions are free to use without any per-registration. In class 6 Maths exercise 8.4, we will learn to add or subtract the like terms based on word problem and application based questions. Explanation videos are also helpful to understand the solutions.
CBSE Solutions App for Class 6
Addition of Decimals
To add decimals, we take the following steps:
- 1: Convert the given decimals into like decimals.
- 2: Write the numbers in column form.
- 3: Decimal points should be aligned so that tenths come under tenths, hundredths come under hundredths and so on.
Example:
Add: 28.7, 29, 158.09 and 825.7
First of all, we convert the given decimals into like decimals.
So, the decimals will be 28.70, 29.00, 158.09 and 825.70.
Now, put them in columns and add:
2 8.7 0
+ 2 9.0 0
+ 1 5 8.0 9
+ 8 2 5.7 0
= 1 0 4 1.4 9
Hence, the sum of the given decimals is 1041.49.
Class 6 Maths Exercise 8.4 Extra Question with Answer
Ramesh travelled 15 km 28 m by car, 9 km 814 m by bus and the rest 2 km 25 m by bicycle. How much distance did he travel in all?
We have, Distance travelled by car = 15 km 28 m = 15.028 km
Distance travelled by bus = 9 km 814 m = 9.814 km
Distance travelled by bicycle = 2 km 25 m = 2.025 km
So, Total distance travelled is:
15.028 km
+ 9.814 km
+ 2.025 km
26.867 km
Hence, total distance travelled = 26.867 km
= 26 km 867 m.
Rekha had a one hundred rupee note. She bought her school bag for Rs. 75.25. How much amount did she get back?
Total amount of money = Rs. 100 = Rs. 100.00
Amount spent on school bag = Rs. 75.25
Balance amount of money = Rs. 100.00 – Rs. 75.25
100.00
– 75.25
24.75
= Rs. 24.75
Subtraction of Decimals
To subtract decimals, we take the following steps:
Step-1: Convert the given decimals into like decimals.
Step-2: Write the smaller number under the larger one in column form in such a way that the decimal points of both the numbers are in the same column and the digits of the same place lie in the same column.
Step-3: Subtract as we do in the case of whole numbers.
Step-4: In the difference, put the decimal point directly under the decimal points of the given numbers.
Class 6 Maths Exercise 8.4 Important Questions
What is addition and subtraction of decimals?
To add two decimal numbers, first check if they have the same number of digits to the right of the decimal point. If they don’t, add zeros to the right of one of the numbers until they do. Then, write one number on top of the other, lining up the decimal points vertically.
What is the meaning of borrowing within mixed decimal subtraction?
If the fraction portion of a mixed number, such as 2 5/6, is more than the fraction portion of the mixed number you’re trying to subtract from, such as 3 1/6, you must “borrow” from the whole number of the mixed number you’re trying to subtract from to make its fraction bigger.
Why do you need to align decimal points before adding or subtracting?
In order to keep the numbers in the proper place-value column when adding decimals, align the decimal points. This will keep the numbers aligned; ones to ones, tenths to tenths, hundredths to hundredths, and so on.
How do you subtract mixed numbers?
To subtract mixed numbers, subtract the whole number parts of the mixed numbers and then subtract the fraction parts in the mixed numbers. Finally, combine the whole number answer and the fraction answer to express the answer as a mixed number. Subtract. Simplify the answer and write as a mixed number.
Example:
Subtract 5.946 from 23.93.
Converting the given decimals into like decimals, we have 5.946, 23.930
Now,
23.930
– 5.946
17.984
Hence, difference is 17.984.
What are the new topics to study in exercise 8.4 of 6th NCERT Maths Book?
In exercise 8.4 of 6th standard Maths, students will learn how to subtract decimals. This exercise has three examples (examples 15, 16, 17) and seven questions. In all problems, students have to just subtract one decimal from another decimal.
Does exercise 8.4 of 6th standard Maths take less time to solve?
Yes, exercise 8.4 of 6th standard Maths is short. It has only three examples (examples 15, 16, 17) and seven questions. Students can complete exercise 8.4 maximum in 2 days if they give 1 hour per day to this exercise. This time also depends on student’s and teacher’s efficiency and working speed.
Is exercise 8.4 of 6th standard Maths complex to solve and understand?
No, exercise 8.4 of 6th standard Maths is not at all complex. This exercise is very simple to solve and understand. Also, this exercise is straightforward and not tricky. Students rapidly understand the concept of this exercise.
Which problems of exercise 8.4 of Class 6 Maths can students expect in the school exams?
In exercise 8.4 of grade 6th Maths, there are three examples (examples 15, 16, 17) and seven questions. The problems of exercise 8.4 of grade 6th Maths that students can expect in the school exams are questions 1, 3, 4, 5, 6, 7. Questions 3, 4, 5, 6, 7 are word problems. These questions are important. Students should practice these questions seriously.
