NCERT Solutions for Class 8 Maths Chapter 4 Exercise 4.3 Practical Geometry in Hindi and English Medium updated for CBSE new session. Access updated Tiwari Academy’s free NCERT solutions for Class 8 Maths Chapter 4, Exercise 4.3 on Practical Geometry. Available in both Hindi and English for students following CBSE and state board guidelines. Simplify your geometry learning with our expert resources.

## 8th Maths Exercise 4.3 Solution in Hindi and English Medium

### Class 8 Maths Chapter 4 Exercise 4.3 Solution

Class VIII Maths Ex. 4.3 of chapter 4 Practical Geometry free to download in PDF file format updated for CBSE session 2024-25. In this exercise, we will construct quadrilaterals with two given sides and three given angles. Class 8 NCERT Textbook Maths ex. 4.3 is easy to solve as compared to other exercises of chapter 4 class 8th Maths. Videos with complete explanation and step by step solving are given with the solutions.

Class: 8 | Mathematics |

Chapter: 4 | Exercise: 4.3 |

Topic Name: | Practical Geometry |

Medium: | Hindi and English Medium |

Content: | Online Text and Videso |

### Class 8 Maths Exercise 4.3 Extra Questions for Practice

### How do you write an adjacent side?

Adjacent side is the side next to the angle in question. (The one other than the hypotenuse). For example: Here, the side A is adjacent to the angle x.

### What are adjacent sides and angles?

Two angles are Adjacent when they have a common side and a common vertex (corner point) and don’t overlap. They have a common side (line CB) they have a common vertex (point B).

### Can 2 adjacent angles be complementary?

Two adjacent angles can be complimentary, if they add up to 90∘, i.e. the sum of two angles formed should be 90∘. They are also complementary as the sum of the angles is 90∘, i.e. ∠ABD+∠CBD=30∘+60∘=90∘.

#### When two adjacent sides and three angles are given

Construct a quadrilateral PQRS in which PQ = 4.5 cm, ∠PQR = 120°, QR = 3.8 cm, ∠QRS = 100° and ∠QPS = 60°.

First we draw a rough sketch of quad. PQRS and write down its dimensions, as given.

Steps of construction:

Step 1. Draw PQ = 4.5 cm.

Step 2. Make ∠PQX = 120°.

Step 3. With Q as centre and radius 3.8 cm, draw an arc, cutting QX at R.

Step 4. Make ∠QRY = 100°.

Step 5. Make ∠QPZ = 60°

So that PZ and RY intersect each other at the point S.

Then, PQRS is the required quadrilateral.

**Question**:

Construct a quadrilateral ABCD in which AB = 5.6 cm, BC = 4 cm, ∠A = 50°, ∠B = 105° and ∠D = 80°.

**Solution**:

First we draw a rough sketch of quad. ABCD and write down its dimensions, as given.

Steps of construction:

Step 1. Draw AB = 5.6 cm.

Step 2. Make ∠ABE = 105°

Step 3. With B as centre and radius 4 cm, draw an arc, cutting BE at C.

Step 4. Make ∠BAF = 50° (∠A + ∠B + ∠D = 50° + 105° + 80° = 2350, so, ∠C = 3600 – 2350 = 1250)

Step 5. Make ∠BCD = 125°

So that AF and CG intersect each other at the point D.

Then, ABCD is the required quadrilateral.