# NCERT Solutions for Class 10 Maths Chapter 1 Exercise 1.2

NCERT Solutions for Class 10 Maths Chapter 1 Exercise 1.2 (Ex. 1.2) Vastvik Sankhaen / Real Numbers in Hindi Medium and English Medium PDF format free to download. Solutions are updated for new academic session 2020-21 based on latest NCERT Books. UP Board students also using NCERT Books so they too can use these solutions for their help. Download UP Board Solutions for Class 10 Maths Exercise 1.2 in Hindi Medium. You can view free NCERT Solutions in Hindi Medium and English Medium Video Format also free for UP Board NCERT Books, Uttarakhand following CBSE Curriculum 2020-2021. Download Tiwari Academy Online app in IOS and Android, which contains the NCERT Solutions for the classes 6 to 12 all subjects.

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## NCERT Solutions for class 10 Maths Chapter 1 Exercise 1.2

Class: 10 | Maths (English and Hindi Medium) |

Chapter 1: | Exercise 1.2 |

### 10 Maths Chapter 1 Exercise 1.2 Solutions

NCERT Solutions for class 10 Maths Chapter 1 Exercise 1.2 Real Numbers in English medium as well as Hindi Medium is given below to free download in PDF form for 2020-21. IF YOU WANT TO DOWNLOAD, THE LINK IS ALSO GIVEN or visit NCERT Solutions for Class 10 Maths Chapter 1 to download other exercises.

#### Class 10 Maths Exercise 1.2 Solution in Hindi Medium Video

#### Class 10 Maths Exercise 1.2 Question 1, 2 Solutions in Video

#### Class 10 Maths Exercise 1.2 Question 3, 4, 5, 6 Solutions in Video

#### Class 10 Maths Exercise 1.2 Question 7 Solutions in Video

#### Important Questions on REAL NUMBERS

1. In a seminar, the number of participants in English, Maths and Science are 175, 140 and 105, respectively. Find the minimum number of rooms required if in each room the same number of participants are to be seated and all of them being in the same subject. [Answer: 12]

2. Find the value of m if HCF of 65 and 117 is expressible in the form 65m – 117. [Answer: 2]

3. What can you say about the product of a non-zero rational and irrational number? [Answer: Irrational]

4. In a school there are two sections of class X – section A and section B. There are 48 students in sections A and 54 students in section B. Determine the least number of books required for the library of the school so that the books can be distributed equally among students of section A or section B? [Answer: 216]

5. After how many places the decimal expansion of 13497/1250 will terminate? [Answer: 4]

6. Find the least number which is divisible by all numbers from 1 to 10 (both inclusive). [Answer: 2520]

##### Practice Questions on Real Numbers

- A circular field has a circumference of 360 km. Three cyclists start together and can cycle 48 km, 60 km and 72 km a day, round the field. After how many days will they meet again at the starting point? [Answer: 30 days]
- The numbers 525 and 3000 are divisible by 3, 5, 15, 25 and 75 what is the HCF of 525 and 3000? [Answer: 75]
- Can two numbers have 18 as their HCF and 380 as their LCM? Give reasons. [Answer: No]
- If a = 4q + r then what are the condition for a and q? What are the values that r can take? [Answer: a and q are positive integer 0 ≤ r ≤ 4]
- What is the digit at unit’s place of 9^n? [Answer: Even power = 1, odd power = 9]
- If n is an odd integer then show that n² – 1 is divisible by 8.
- Use Euclid’s division algorithm to find the HCF of 16 and 28. [Answer: 4]

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##### What is fundamental theorem of Arithmetic?

According to fundamental theorem of arithmetic:

Every composite number can be expressed ( factorised) as a product of primes, and this factorisation is unique, apart from the order in which the prime factors occur.

##### 225 can be expressed as (a) 5 x 3^2 (b) 5^2 x 3 (c) 5^2 x 3^2 (d) 5^3 x 3. [CBSE 2020] [Maths Basic]

225 = 3 x 3 x 5 x 5 = 3^2 x 5^2.

Hence, Option (c) is correct.

##### The total number of factors of a prime number is (a) 1 (b) 0 (c) 2 (d) 3. [CBSE 2020] [Maths Standard]

The total number of factors of a prime number is 2. One is 1 and other is itself number.

Hence, Option (c) is correct.

##### The HCF and the LCM of 12, 21, 15 respectively are (a) 3, 140 (b) 12, 120 ((c) 3, 420 (d) 420, 3 [CBSE 2020] [Maths Standard]

12 = 2 x 2 x 3

21 = 3 x 7

15 = 3 x 5

HCF = 3

LCM = 2 x 2 x 3 x 7 x 5 = 420

Hence, Option (c) is correct.