NCERT Solutions for Class 12 Maths Exercise 10.4

Class XII Mathematics chapter 10 ex. 10.4 solutions are updated for CBSE academic session 2024-25. Video solutions are also available in Hindi and English Medium free to use online or download for offline use. PDF solutions and online study material both are available to use free without any login or password.

Get here the solution of class 12 Maths Exercise 10.4, which is based on cross-product of vectors. Solution contains the complete explanation of exercise 10.4 in Hindi and English Medium. Videos related to Hindi and English Medium are given separately.

A vector is the displacement from point A to point B. Now consider a situation in which a girl moves from A to B and then from B to C. The net displacement done by the girl from point A to point C is given by the vector and expressed as vector AC = vector AB + vector AC. This is known as the triangle rule of vector addition. In general, if we have two vectors to add, they are positioned so that the starting point of one coincides with the terminal point of the other.

Let a be a vector and let k be a scalar. So, the scalar denotes the product of the vector, because ka is called multiplication of the vector by the scalar. Note that ka is also a vector, consisting of a vector. The vector has only one direction (or vice versa), depending on whether the value of the vector is positive (or negative). Furthermore, the magnitude of the vector is several times greater than the magnitude of the vector.

P and Q are represented by two points, representing OP and OQ, respectively, with respect to the original O. Subsequently, the line segment joining the points P and Q can be divided by the third point, R says, in two ways: internally and externally. Here, we intend to find the position vector for point R with respect to the origin O.