NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.2 in Hindi and English Medium for new session 2024-25. The questions explanation of ex. 10.2 class 6th Maths are updated and revised according to syllabus change given in new NCERT textbooks for CBSE 2024-25.

## 6th Maths Exercise 10.2 Solutions in Hindi and English Medium

Class: 6 | Mathematics |

Chapter: 10 | Exercise: 10.2 |

Chapter Name: | Mensuration |

Content Type: | PDF and Videos Solutions |

Session: | CBSE 2024-25 |

Medium: | Hindi and English Medium |

### Class 6 Maths Chapter 10 Exercise 10.2 Solution

Class VI Mathematics NCERT book Ex. 10.2 of Mensuration in Hindi and English Medium prepared for CBSE and state board following the latest NCERT (https://ncert.nic.in/) Books. 6th NCERT Textbook solutions are given in PDF format as well as videos. Practice all the question answers according to your convenience whether through text solutions or videos solutions. In class 6 math exercise 10.2 we will learn how to find the area of any figure by counting the squares.

#### Class 6 Maths Chapter 10 Exercise 10.2 Solution in Videos

#### Perimeter of a Square

We know that all the sides of a square are equal.

If we denote the length of each side of the square by s, then its perimeter is given by

P = (s + s + s + s) = 4s.

The perimeter of a square of side s is given by P = 4s.

If the perimeter P of a square is known, then its side s can be found easily.

Perimeter = 4 × side

Thus, side = ¼ × Perimeter

### Class 6 Maths Exercise 10.2 Extra Questions with Answer

### A rectangular field is 45 m long and 32 m wide. Find its perimeter.

Length of the field = 45 m

Breadth of the field = 32 m

So, Perimeter of the field = 2 (length + breadth)

= 2 (45 + 32) m = 2 × 77 m

= 154 m

### Length and breadth of a rectangular field are in the ratio 3 :2. If perimeter of the field is 70 m, then find its length and breadth in metre.

Let the length is 3x and the breadth is 2x.

We know that, P = 2 (l + b)

So, 70 m = 2(3x + 2x)

or, 70 m = 2 × 5x

x = 70/10 = 7 m

so, length = 3x

= 3 × 7 m

= 21 m and breadth = 2x

##### Concept of Area of close surface

The measure of the amount of surface enclosed by a figure is called its area.

##### Comparison of Areas

When the given surfaces are of the same shape, we compare them by placing one over the other.

### Class 6 Maths Exercise 10.2 Important Questions

### Where do we use perimeter and area in real life?

Uses of perimeter and area in daily life

(i) Fencing off an area to plot a crop. Since fences cost money for a given area you would want to minimize the perimeter.

(ii) Planning the construction of a house.

(iii) Building a barn with box stalls for horses.

(iv) Make Wooden furniture.

(v) Building a swimming pool.

### How does perimeter relate to area?

The perimeter is the sum of all the side lengths of a shape. The area is the amount of two dimensional space a shape occupies.

### Find the cost of fencing a square of the side 24 cm at the rate of Rs 4.50 per metre.

Side of the square = 24 cm

So, Perimeter of the square = 4 × side

= 4 × 24 cm = 96 cm

So, cost of fencing the square = Rs. (4.50 × 96)

= Rs. 432.

### To fence a rectangular field, 260 m long wire is required. Find the length of the field if its breadth is 55 m.

Length of wire to fence the field = 260 m

= Perimeter of the field

So, Length of the field = perimeter – breadth

= ( ½ × 260 – 55) m = (130 – 55) m = 75 m

##### Standard Units of Area

The area of a small figure is measured in square millimetres or square centimetres The bigger area is measured in square metres. Some examples given below:

(i) The area of a square of side 1 mm is 1 square millimetre, written as 1 square mm or 1 mm².

(ii) The area of a square of side 1 cm is 1 square centimetre, written as 1 square cm or 1 cm².

(iii) The area of a square of side 1 metre is 1 square metre, written as 1 square m or 1 m².

### What is the basic objective of class 6 Mathematics exercise 10.2?

The basic objective of class 6th Maths exercise 10.2 is to teach students how to find the area (The amount of surface enclosed by a closed figure is called its area) of the given figures by counting the squares.

### How many problems are there in exercise 10.2 of 6th class Maths?

In exercise 10.2 of 6th class Maths, there are 4 problems (three examples (examples 10, 11, and 12) and 1 question having 14 parts). In all problems of this exercise, students have to find out the area of given figures by counting the squares.

### Which parts of question 1 and examples of exercise 10.2 are considered as important?

In exercise 10.2 of 6th class Maths, there is one question having 14 parts. All parts of this question are important and unique. But, parts (g), (l), and (m) has more chance to come in the exams as compared to other parts of question 1 of exercise 10.2 of Maths class 6th. Examples 10 and 11 of this exercise are important.

### How many days are required to complete exercise 10.2 of grade 6th Maths?

If students can give 1 hour per day to exercise 10.2 of grade 6th Maths then they need a maximum of 2 days to complete exercise 10.2 of grade 6th Maths. This time increases or decreases because this time depends on students working speed.