# NCERT Solutions for Class 6 Maths Chapter 10

NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.1, Exercise 10.2 and Exercise 10.3 in English Medium as well as Hindi Medium updated for new academic session 2021-2022 based on new NCERT Books.

Solutions of Prashnavali 10.1, Prashnavali 10.2 and Prashnavali 10.3 in Hindi Medium PDF file format to free download. Download links for NCERT Books 2021-2022 and Offline NCERT Solutions Apps 2021-22 are also available to free download. Solutions of each question with suitable answers and explanation are given on the website. Download NCERT Solution Offline Apps for Class 6 all subjects.## NCERT Solutions for Class 6 Maths Chapter 10

### Class 6 Maths Chapter 10 all Exercises Solution

Class: 6 | Mathematics |

Chapter 10: | Mensuration |

### Download Class 6 Maths Chapter 10 Solutions in PDF Format

Download NCERT Solutions for Class 6 Maths Chapter 10 Mensuration in PDF format updated for new session 2021-22 using the latest NCERT Books 2021-22. For any difficulty, please notify us for help. We are here to help you free of cost.

### Class 6 Maths Chapter 10 Solutions in English Medium

### Class 6 Maths Chapter 10 Solutions in Hindi Medium

#### Class 6 Maths Exercise 10.1 & 10.2 Solutions in Video

#### Class 6 Maths Exercise 10.3 Solutions in Video

#### About Class 6 Maths Chapter 10

In 6 Maths Chapter 10 Mensuration, we will study about the perimeter and area related to various 2-D figures. This chapter is important as per further classes also. We should learn the formulae of perimeter and areas of various figures. Some the the formulae are given below:

Perimeter of a rectangle = 2 × (length + breadth)

Perimeter of a square = 4 × length of its side

Perimeter of an equilateral triangle = 3 × length of a side

Perimeter is the distance covered along the boundary forming a closed figure when you go round the figure once.

Area of a rectangle = length × breadth

Area of a square = side × side

To calculate the area of a figure using a squared paper, the following conventions are adopted:

Ignore portions of the area that are less than half a square.

If more than half a square is in a region. Count it as one square.

If exactly half the square is counted, take its area as 1/2 sq units.

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### Important Questions on Class 6 Maths Chapter 10

##### The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required?

Total length of tape required

= Perimeter of rectangle

= 2 (length + breadth)

= 2 (40 + 10)

= 2 x 50

= 100 cm

= 1 m

Thus, the total length of tape required is 100 cm or 1 m.

##### A table-top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table-top?

Length of table top = 2 m 25 cm = 2.25 m

Breadth of table top = 1 m 50 cm = 1.50 m

Perimeter of table top

= 2 x (length + breadth)

= 2 x (2.25 + 1.50)

= 2 x 3.75

= 7.50 m

Thus, the perimeter of table top is 7.5 m.

##### Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.

Perimeter of triangle = Sum of all three sides

= 10 cm + 14 cm + 15 cm = 39 cm

Thus, the perimeter of triangle is 39 cm.

##### Find the perimeter of a regular hexagon with each side measuring 8 cm.

Perimeter of Hexagon = 6 x length of one side = 6 x 8 m = 48 m

Thus, the perimeter of hexagon is 48 m.

##### Find the cost of fencing a square park of side 250 m at the rate of ₹20 per meter.

Side of square = 250 m

Perimeter of square = 4 x side = 4 x 250 = 1000 m

Since, cost of fencing of per meter = ₹ 20

Therefore, the cost of fencing of 1000 meters = 20 x 1000 = ₹20,000

##### A table-top measures 2 m by 1 m 50 cm. What is its area in square meters?

Length of table = 2 m

Breadth of table = 1 m 50 cm = 1.50 m

Area of table = length x breadth = 2 m x 1.50 m = 3 m²

##### Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?

Side of square bed = 1 m

Area of square bed = side x side = 1 m x 1 m = 1 m²

Area of 5 square beds = 1 x 5 = 5 m²

Now, Length of land = 5 m

Breadth of land = 4 m

Area of land = length x breadth = 5 m x 4 m = 20 m²

Area of remaining part

= Area of land – Area of 5 flower beds = 20 m² – 5 m² = 15 m²