NCERT Solutions for Class 6 Maths Chapter 10
NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Exercise 10.1, Exercise 10.2 and Exercise 10.3 in English Medium as well as Hindi Medium updated for new academic session 2021-2022 based on new NCERT Books.
Solutions of Prashnavali 10.1, Prashnavali 10.2 and Prashnavali 10.3 in Hindi Medium PDF file format to free download. Download links for NCERT Books 2021-2022 and Offline NCERT Solutions Apps 2021-22 are also available to free download. Solutions of each question with suitable answers and explanation are given on the website. Download NCERT Solution Offline Apps for Class 6 all subjects.NCERT Solutions for Class 6 Maths Chapter 10
Class 6 Maths Chapter 10 all Exercises Solution
| Class: 6 | Mathematics |
| Chapter 10: | Mensuration |
NCERT Solutions App for Class 6
Download Class 6 Maths Chapter 10 Solutions in PDF Format
Download NCERT Solutions for Class 6 Maths Chapter 10 Mensuration in PDF format updated for new session 2021-22 using the latest NCERT Books 2021-22. For any difficulty, please notify us for help. We are here to help you free of cost.
Class 6 Maths Chapter 10 Solutions in English Medium
Class 6 Maths Chapter 10 Solutions in Hindi Medium
Class 6 Maths Exercise 10.1 & 10.2 Solutions in Video
Class 6 Maths Exercise 10.3 Solutions in Video
About Class 6 Maths Chapter 10
In 6 Maths Chapter 10 Mensuration, we will study about the perimeter and area related to various 2-D figures. This chapter is important as per further classes also. We should learn the formulae of perimeter and areas of various figures. Some the the formulae are given below:
Perimeter of a rectangle = 2 × (length + breadth)
Perimeter of a square = 4 × length of its side
Perimeter of an equilateral triangle = 3 × length of a side
Perimeter is the distance covered along the boundary forming a closed figure when you go round the figure once.
Area of a rectangle = length × breadth
Area of a square = side × side
To calculate the area of a figure using a squared paper, the following conventions are adopted:
Ignore portions of the area that are less than half a square.
If more than half a square is in a region. Count it as one square.
If exactly half the square is counted, take its area as 1/2 sq units.
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Important Questions on Class 6 Maths Chapter 10
The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required?
Total length of tape required
= Perimeter of rectangle
= 2 (length + breadth)
= 2 (40 + 10)
= 2 x 50
= 100 cm
= 1 m
Thus, the total length of tape required is 100 cm or 1 m.
A table-top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table-top?
Length of table top = 2 m 25 cm = 2.25 m
Breadth of table top = 1 m 50 cm = 1.50 m
Perimeter of table top
= 2 x (length + breadth)
= 2 x (2.25 + 1.50)
= 2 x 3.75
= 7.50 m
Thus, the perimeter of table top is 7.5 m.
Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm.
Perimeter of triangle = Sum of all three sides
= 10 cm + 14 cm + 15 cm = 39 cm
Thus, the perimeter of triangle is 39 cm.
Find the perimeter of a regular hexagon with each side measuring 8 cm.
Perimeter of Hexagon = 6 x length of one side = 6 x 8 m = 48 m
Thus, the perimeter of hexagon is 48 m.
Find the cost of fencing a square park of side 250 m at the rate of ₹20 per meter.
Side of square = 250 m
Perimeter of square = 4 x side = 4 x 250 = 1000 m
Since, cost of fencing of per meter = ₹ 20
Therefore, the cost of fencing of 1000 meters = 20 x 1000 = ₹20,000
A table-top measures 2 m by 1 m 50 cm. What is its area in square meters?
Length of table = 2 m
Breadth of table = 1 m 50 cm = 1.50 m
Area of table = length x breadth = 2 m x 1.50 m = 3 m²
Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?
Side of square bed = 1 m
Area of square bed = side x side = 1 m x 1 m = 1 m²
Area of 5 square beds = 1 x 5 = 5 m²
Now, Length of land = 5 m
Breadth of land = 4 m
Area of land = length x breadth = 5 m x 4 m = 20 m²
Area of remaining part
= Area of land – Area of 5 flower beds = 20 m² – 5 m² = 15 m²
