NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.3 in Hindi and English Medium updated for CBSE new session 2023-24. Students of class 6th Maths can get the revised solutions of ex. 10.3 based on new NCERT textbooks issued for CBSE 2023-24 examination.
|Chapter: 10||Exercise: 10.3|
|Content:||NCERT textbook solutions|
|Medium:||Hindi and English Medium|
Class 6 Maths Chapter 10 Exercise 10.3 Solution
Class VI Mathematics NCERT (https://ncert.nic.in/) textbook Ex. 10.3 of Mensuration in PDF file format free to use online or download. All the contents are updated for academic session 2023-24 CBSE and other state board’s students. NCERT Class 6 math exercise 10.3 explains the way to find area of square and rectangles using formulae. Here some practical questions are also given based on daily life word problems.
Class 6 Maths Chapter 10 Exercise 10.3 Solution in Videos
Area by Counting Squares on a Squared Paper
We can find the area of some regular and irregular figures by using squared paper. To find area some steps are given below:
Step-1: Count the number of complete squares enclosed by the figure.
Step-2: Count the number of those squares in which more than half part is enclosed by the figure and treat them as one complete square.
Step-3: Count the number of those squares in which half part is enclosed by the figure and divide it by 2 to get the number of complete squares.
Step-4: Leave those squares in which less than half part is enclosed by the figure.
Class 6 Maths Exercise 10.3 Extra Questions with Answer
Find the area of a rectangle if its length and breadth are 24 cm and 13 cm respectively.
Here, length = 24 cm and breadth = 13 cm
So, Area of the rectangle = length × breadth
= (24 × 13) sq.cm = 312 sq.cm
What is the area of the floor of a square room of side 8.3 m? Also, find the cost of flooring the room at Rs. 10 per sq. m.
Side of the square = 8.3 m
So, Area of the square = side × side
= (8.3 × 8.3) sq. m
= 68.89 sq. m
So, cost of flooring the room = Rs. (10 × 68.89) = Rs. 688.90.
Area of a Rectangle and a Square
So far, we have learnt how to find the area of any given figure by counting the number of squares enclosed by the figure. This method is time consuming and a bit difficult for calculating the area of given figures. There is an easier method for calculating the areas of rectangles and squares.
We observe that the area of a rectangle (A) = length × breath
or A = l × b
Also, we have: Length = area/breadth
And breadth = area/length
In the case of a square, we know that l = b
Hence, the area of a square (A) = side × side
or A = l × l
Class 6 Maths Exercise 10.3 Important Questions
Does area increase as perimeter increases?
The area increases much faster than the length of the perimeter (you could graph this and discuss linear versus exponential growth). Sides increase by one, perimeters increase by four, and area increases by three, five, seven, then nine!
The area of a rectangle is 90 sq.cm. Find the breadth of the rectangle if its length is 20 cm.
Area of the rectangle = 90 sq.cm.
Length of the rectangle = 20 cm
So, Breadth of the rectangle = Area/length
= 90/20 cm
= 4.5 cm
The perimeter of a rectangular field is 220 m and its breadth (width) is 48 m. Find the area and total cost of cultivating the field at Rs. 3.50 per sq. m.
Perimeter of the field = 220 m Breadth of the field = 48 m
So, Length of the field = ½ x Perimeter – Breadth
= (1/2 × 220 – 48) m
= (110 – 48) m = 62 m
Now, area of the field = length × breadth
= (62 × 48) sq. m
= 2976 sq. m
So, Total cost of cultivating the field = Rs (3.50 × 2976)
= Rs 10416
Perimeter of rectangle = 2 (length + breadth)
Area of rectangle = length x breadth
Perimeter of square = 4 x side
Area of square = side²
Which new topics will students study in exercise 10.3 of class 6th Maths?
In exercise 10.3 of class 6th Maths, students will study how to find:
1. The area of a rectangle (length × breadth)
2. The area of a square (side × side)
Which examples and questions of exercise 10.3 of Maths 6th class can the teacher give in the unit test?
Exercise 10.3 of Maths 6th class has 5 examples (examples 13, 14, 15, 16, and 17) and 12 questions. Example 15 and questions 4, 5, 7, 8, 9, 10, 11, and 12 of exercise 10.3 of Maths 6th class are most important.
How many days are needed to finish exercise 10.3 of Maths 6th class?
A maximum of 3 days are needed to finish exercise 10.3 of Maths 6th class if students give 1-2 hours per day to this exercise. This time is an approximate time. This time depends on the student’s working speed, efficiency, capability, etc.
Which problems of exercise 10.3 of class 6th Maths are simple and which are complicated from a student’s point of view?
Examples 15, 16 and questions 4, 5, 8, 9, 10, 11, and 12 of exercise 10.3 of class 6th Maths are complicated from the student’s point of view, and examples 13, 14, 17 and questions 1, 2, 3, 6, 7 of exercise 10.3 of class 6th Maths are simple from the student’s point of view.