NCERT Solutions for Class 8 Maths Chapter 7 Exercise 7.1 Comparing Quantities in Hindi and English Medium updated for new session 2024-25. The solutions of ex. 7.1 class 8th mathematics are revised according to new syllabus and latest textbooks issued for academic year 2024-25.

## 8th Maths Exercise 7.1 Solution in Hindi and English Medium

Class: 8 | Mathematics |

Chapter: 7 | Exercise: 7.1 |

Chapter Name: | Comparing Quantities |

Content: | PDF and Videos Solutions |

Academic Session: | CBSE 2024-25 |

Medium: | Hindi and English Medium |

### Class 8 Maths Chapter 7 Exercise 7.1 Solution

Class VIII Mathematics NCERT book Ex. 7.1 Comparing Quantities in Hindi and English Medium to download in PDF for 2024-25. All the contents are updated for CBSE and State board academic session 2024-25. Questions are described in simple and easy methods through videos and PDF. All the contents on Tiwari Academy is free to use online or download without any login or password.

#### Percent

By a certain per cent we mean that many hundredths.

We denote x per cent by x%.

x% = x hundredths = x/100

**Express each of the following as a fraction: (i) 36%, (ii) 120%, (iii) 0.8%**

- (i) 36% = 36/100 = 9/25
- (ii) 120% = 120/100 = 6/5
- (iii) 0.8% = 0.8/100 = 8/1000 = 1/125

**Express each of the following fractions as a percentage: (i) 7/25 (ii) 5/8 (iii) 11/6**

We have:

- (i) 7/ 25 = (7/25) x 100% = 28%.
- (ii) 5/8 = 5/8 x 100% = (125/2) %
- (iii) = 11/6 x 100% =550/3 % = 183 %.

**In a class, the girls are 60% of the total number of students and the boys are 18 in number. How many students are there in the class?**

Let the total number of students in the class be x.

Percentage of girls = 60%.

Percentage of boys = 40%.

So, number of boys = 40% of x = x X 40/100 = 2x /5

2x/5 = 18, x = 18 x 5 /2 = 45

Hence, the total number of students in the class is 45.

**The price of sugar goes up by 20%. By how much per cent must a housewife reduce her consumption of sugar so that the expenditure on sugar remains the same?**

Let the consumption of sugar originally be 1 unit and let its cost be 100.

New cost of 1 unit = 120.

Now, 120 yield 1 unit of sugar.

So, Rs. 100 will yield (1/120) x 100 unit = 5/6 units of sugar.

Reduction in consumption = 1- (5/6) = 1/6 units

So, reduction % in consumption = (1/6 x 5/6 x 100) % = 50/3 %

### How to you find the percentage of pure gold in exercise 7.1 of class 8 Maths?

Class 8 Mathematics chapter 7 is based on comparing the quantities. So, we can compare the different quantities and also find the percentage of pure substance present in given object.

22-carat gold contains 22 parts out of 24 parts.

Percentage of pure gold in it

= (22/24) x 100 %

= 91%.

### How do exercise 7.1 of 8th Maths helps to calculate the percentage between two numbers?

First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number – Original Number.

Then, divide the increase by the original number and multiply the answer by 100.

% increase = Increase ÷ Original Number × 100.

### What are the main steps given in exercise 7.1 of class 8 Maths to calculate percentage of a total?

According the class 8 Mathematics exercise 7.1, the steps are given below:

- Determine the whole or total amount of what you want to find a percentage for.
- Divide the number that you wish to determine the percentage for.
- Multiply the value from step two by 100.