NCERT Solutions for Class 8 Maths Chapter 8 Exercise 8.1 in Hindi and English Medium updated for CBSE session 2022-2023.

Class 8 Maths Chapter 8 Exercise 8.1 Solution

Class VIII Mathematics NCERT book Ex. 8.1 Comparing Quantities in Hindi and English Medium to download in PDF for 2022-23. All the contents are updated for CBSE and State board academic session 2022-23. Questions are described in simple and easy methods through videos and PDF. All the contents on Tiwari Academy is free to use online or download without any login or password.

Class: 8Mathematics
Chapter: 8Exercise: 8.1
Chapter Name:Comparing Quantities
Content:PDF and Videos Solutions
Medium:Hindi and English Medium

Hindi Medium App for Class 8

Percent

By a certain per cent we mean that many hundredths.
We denote x per cent by x%.
x% = x hundredths = x/100

Express each of the following as a fraction: (i) 36%, (ii) 120%, (iii) 0.8%

    • (i) 36% = 36/100 = 9/25
    • (ii) 120% = 120/100 = 6/5
    • (iii) 0.8% = 0.8/100 = 8/1000 = 1/125

Express each of the following fractions as a percentage: (i) 7/25 (ii) 5/8 (iii) 11/6
We have:

    • (i) 7/ 25 = (7/25) x 100% = 28%.
    • (ii) 5/8 = 5/8 x 100% = (125/2) %
    • (iii) = 11/6 x 100% =550/3 % = 183 %.

In a class, the girls are 60% of the total number of students and the boys are 18 in number. How many students are there in the class?
Let the total number of students in the class be x.
Percentage of girls = 60%.
Percentage of boys = 40%.
So, number of boys = 40% of x = x X 40/100 = 2x /5
2x/5 = 18, x = 18 x 5 /2 = 45
Hence, the total number of students in the class is 45.

The price of sugar goes up by 20%. By how much per cent must a housewife reduce her consumption of sugar so that the expenditure on sugar remains the same?
Let the consumption of sugar originally be 1 unit and let its cost be 100.
New cost of 1 unit = 120.
Now, 120 yield 1 unit of sugar.
So, Rs. 100 will yield (1/120) x 100 unit = 5/6 units of sugar.
Reduction in consumption = 1- (5/6) = 1/6 units
So, reduction % in consumption = (1/6 x 5/6 x 100) % = 50/3 %

How to you find the percentage of pure gold in exercise 8.1 of class 8 Maths?

Class 8 Mathematics chapter 8 is based on comparing the quantities. So, we can compare the different quantities and also find the percentage of pure substance present in given object.
22-carat gold contains 22 parts out of 24 parts.
Percentage of pure gold in it
= (22/24) x 100 %
= 91%.

How do exercise 8.1 of 8th Maths helps to calculate the percentage between two numbers?

First: work out the difference (increase) between the two numbers you are comparing.
Increase = New Number – Original Number.
Then, divide the increase by the original number and multiply the answer by 100.
% increase = Increase ÷ Original Number × 100.

What are the main steps given in exercise 8.1 of class 8 Maths to calculate percentage of a total?

According the class 8 Mathematics exercise 8.1, the steps are given below:

    1. Determine the whole or total amount of what you want to find a percentage for.
    2. Divide the number that you wish to determine the percentage for.
    3. Multiply the value from step two by 100.
NCERT Solutions for Class 8 Maths Chapter 8 COMPARING QUANTITIES Exercise 8.1 in pdf form
NCERT Solutions for Class 8 Maths Chapter 8 COMPARING QUANTITIES ex. 8.1 in englsh
8 Maths Exercise 8.1 Solutions in hindi medium free
8 Maths Exercise 8.1 Solutions in pdf free guide