# NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.3

NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.3 Lines and Angles in Hindi Medium and English Medium for all board using NCERT and updated for academic session 2020-2021.

In the UP Board and MP Board, students are now using NCERT Textbooks are course book. So, UP Board and MP board students also take the benefits of exercise 6.3 solutions of class 9 Maths. Get here the videos solutions in Hindi and English Medium using the easy language for the explanation.

## Class 9 Maths Chapter 6 Exercise 6.3 Solution in Hindi and English

 Class: 9 Mathematics Chapter: 6 Lines and Angles Exercise: 6.3 NCERT Solutions in text and Videos

### Class 9 Maths Exercise 6.3 Solution in Hindi Medium Video

#### Class 9 Maths Chapter 6 Exercise 6.3 Solution in Videos

Class 9 Maths Exercise 6.3 Question 1 and 2
Class 9 Maths Exercise 6.3 Question 3 and 4
Class 9 Maths Exercise 6.3 Question 5 and 6
Class 9 Maths Chapter 6 Exercise 6.3 Solution
##### Distance between parallel lines

The lengths of the common perpendiculars at different points on these parallel lines is the same. This equal length is called the distance between two parallel lines. You have learnt the definitions of some of the pairs of angles such as complementary angles, supplementary angles, adjacent angles, linear pair of angles, etc.

If a transversal cuts two lines which are parallel, then

1. Any pair of related angles is the same, or
2. Any pair of alternate interior angles is the same, or
3. Any pair of internal angles on the same side of the transversal is complementary, so the lines are parallel.

## Angles Sum Property of a Triangle The sum of the angles of a triangle is 180º. Proof: We are given a triangle PQR and ∠ 1, ∠ 2 and ∠ 3 are the angles of Δ PQR. We need to prove that ∠ 1 + ∠ 2 + ∠ 3 = 180°. Let us draw a line XPY parallel to QR through the opposite vertex P, as shown in Fig. 6.35, so that we can use the properties related to parallel lines. Now, XPY is a line. Therefore, ∠ 4 + ∠ 1 + ∠ 5 = 180° …… (1) But XPY || QR and PQ, PR are transversal. So, ∠ 4 = ∠ 2 and ∠ 5 = ∠ 3 (Pairs of alternate angles) Substituting ∠ 4 and ∠ 5 in (1),

We get ∠ 2 + ∠ 1 + ∠ 3 = 180°
That is,
∠ 1 + ∠ 2 + ∠ 3 = 180°

###### Terms related to Parallel lines and Transversal Lines

If a line which intersects two or more lines at distinct points is called a transversal. Interior angles on the same side of the transversal are also referred to as consecutive interior angles or allied angles or co-interior angles. If a transversal intersects two lines such that a pair of corresponding angles is equal, then the two lines are parallel. If a transversal intersects two lines such that a pair of corresponding angles is equal, then the two lines are parallel to each other.

##### What are the main concepts on which exercise 6.3 of class 9 Maths based?

CBSE Class 9 Maths Exercise 6.3 is based mainly on angle sum property of triangle and exterior angle property.

##### Which example is most important for exercise 6.3 of 9th Maths?

Example 8 given on page number 106 is the most important example not only for exercise 6.3 but for the entire chapter 6 of CBSE Class 9 Maths.

##### Which is the most important question in exercise 6.3 of 9th Maths?

Question 6 Which is the last question of exercise as well as chapter 6, is most important for all exams and school tests. It is easy to understand but difficult to learn.

##### Which section is deleted from chapter 6 due to COVID-19?

There is not any deletion from chapter 6. Every question is important from chapter 6 of class 9 Maths.    