To find the inner surface area of a vessel composed of a hollow hemisphere mounted by a hollow cylinder, we need to calculate the surface areas of both parts separately and then sum them up. The diameter of the hemisphere is given as 14 cm, so its radius r is 7 cm. The total height of the vessel is 13 cm.
The height of the cylindrical part can be found by subtracting the radius of the hemisphere from the total height of the vessel, which is 13cm − 7cm = 6cm.
The inner surface area of the hemisphere is 2πr², and the inner surface area of the cylinder is 2πrh (since we only consider the lateral surface area for the hollow part). Substituting the values, we get 2π × 7² for the hemisphere and 2π × 7 × 6 for the cylinder.
Calculating these, the total inner surface area of the vessel is
308π + 84π = 392π square cm. Thus, the inner surface area of the vessel is 392π cm², which is approximately 1232.16 cm².

A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner SA of the vessel.

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Introduction to Geometric Problem Solving

In the fascinating world of geometry, solving problems often involves dissecting complex shapes into simpler, more manageable components. This approach is particularly useful when dealing with composite shapes, such as a vessel made of a hollow hemisphere mounted on a hollow cylinder. The challenge here is to find the inner surface area of this vessel. This task not only tests our understanding of basic geometric formulas but also our ability to apply these formulas to real-world objects. By breaking down the vessel into its constituent parts – the hemisphere and the cylinder – we can methodically calculate the surface area of each and combine them to find the total inner surface area.

Understanding the Hemisphere Component

The first step in our calculation involves understanding the dimensions of the hemisphere. Given that the diameter of the hemisphere is 14 cm, its radius (r) is half of this, which is 7 cm. The inner surface area of a hemisphere is calculated using the formula
2πr². This formula accounts for the fact that a hemisphere is essentially half of a sphere, and thus, its surface area is half that of a sphere’s outer surface. The calculation of the hemisphere’s surface area is crucial as it represents a significant portion of the vessel’s inner surface.

Calculating the Cylinder’s Dimensions

Next, we turn our attention to the cylindrical part of the vessel. The total height of the vessel is given as 13 cm. To find the height of the cylinder, we subtract the radius of the hemisphere from the total height. Since the radius of the hemisphere is 7 cm, the height of the cylinder is 13cm − 7cm = 6cm. This height is essential for calculating the inner surface area of the cylindrical portion, which, unlike a full cylinder, does not include the top and bottom surfaces.

Computing the Cylinder’s Surface Area
The inner surface area of the cylinder is given by the formula 2πrh, where r is the radius and h is the height of the cylinder. This formula calculates the lateral surface area of the cylinder, which is the area of the curved surface excluding the top and bottom. In our case, the radius is 7 cm, and the height is 6 cm. By substituting these values into the formula, we can determine the inner surface area of the cylindrical part of the vessel.

Total Inner Surface Area of the Vessel

Having calculated the inner surface areas of both the hemisphere and the cylinder, we now combine these to find the total inner surface area of the vessel. This involves simply adding the surface area of the hemisphere and the cylinder. The sum of these areas gives us the total area that the inner surface of the vessel covers. This step is crucial as it brings together the individual calculations into a single, comprehensive answer, reflecting the total inner surface area of the composite vessel.

The Elegance of Geometric Calculation

In conclusion, the process of calculating the inner surface area of a vessel composed of a hollow hemisphere and a hollow cylinder beautifully illustrates the elegance and precision of geometric problem-solving. By breaking down the problem into smaller parts, applying relevant formulas, and combining the results, we arrive at a clear and accurate solution. This exercise not only reinforces our understanding of geometric principles but also demonstrates their practical application in analyzing real-world objects. It is a testament to the power of mathematical reasoning in solving complex problems by methodically working through each step of the process.

Discuss this question in detail or visit to Class 10 Maths Chapter 12 for all questions.
Questions of 10th Maths Exercise 12.1 in Detail

2 cubes each of volume 64 cm³ are joined end to end. Find the surface area of the resulting cuboid.
A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner surface area of the vessel.
A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy.
A cubical block of side 7 cm is surmounted by a hemisphere. What is the greatest diameter the hemisphere can have? Find the surface area of the solid.
A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.
A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is 14 mm and the diameter of the capsule is 5 mm. Find its surface area.
A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of ₹500 per m².
From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm³.
A wooden article was made by scooping out a hemisphere from each end of a solid cylinder. If the height of the cylinder is 10 cm, and its base is of radius 3.5 cm, find the total surface area of the article.