NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.3

NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.3 (Ex. 2.3) Fractions and Decimals in PDF file format free to use online or download to use it offline. All the solutions and videos are based on latest CBSE syllabus for academic session 2020-2021.

In class 7 math exercise 2.3 questions are given to practice the multiplication of fractions. Here we will learn the multiplication of fraction and daily life situation questions.

Class 7 Maths Chapter 2 Exercise 2.3 Solution

Class: 7Mathematics
Chapter: 2Fractions and Decimals
Exercise: 2.3CBSE Book’s Solution

NCERT Book’s Solution App for Class 7

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Class 7 Maths Chapter 2 Exercise 2.3 Solution in Videos

Class 7 Maths Chapter 2 Exercise 2.3 Solution
Class 7 Maths Exercise 2.3 Question 1, 2 Explanation




Class 7 Maths Exercise 2.3 Question 3, 4 Explanation
Class 7 Maths Exercise 2.3 Question 5-8 Explanation

Subtraction of Fractions

Example:
Find the difference: (i) 7/9 – 5/9 (ii) 13/16 – 7/12
We have:
(i) 7/9 – 5/9 = (7 – 5)/9 = 2/9
(ii) 13/16 – 7/12
LCM of 16 and 12 is 48
So, (13 x 3 – 7 x 4)/48 = (39 – 28)/48 = 11/48

Rekha bought 5(3/4) kg potatoes and 3(1/2) kg tomatoes from a vendor. What is the total weight of vegetables bought by her?

Total weight of vegetables bought by Rekha.
23/4 + 7/2 = (23 + 14)/4 = 37/4 kg = 9(1/4)

Multiplication of Fractions

Rule: Product of Fractions = (Product of their Numerators)/ (Product of their Denominators)
Thus, (a/b x c/d) = (a x c)/ (b x d)

Find the product: (i) 5/8 x ¾ (ii) 3/4 x 5/2.

We have:
(i) 5/8 x ¾ = (5 x 3)/ (8 x 4) = 15/32
(ii) 3/4 x 5/2 = (3 x 5)/ (4 x 2) = 15/8

Multiply: (i) 7(5/8) by 3/2 (ii) 9(3/8) by 12

We have:
(i) 7(5/8) by 3/2 = 7(5/8) x 3/2 = 61/8 x 3/2 = (61 x 3)/ (8 x 2) = 183/16
(ii) 9(3/8) by 12 = {(9 x 8 + 3)/ 8} x 12 = 75/8 x 12 = (75 x 12)/ 8 = 225/2 = 112(1/2)

Use of ‘OF’

We define:
a/b of c = c x (a/b)
Example:
(i) 2/5 of 40 (ii) 5/9 of 48
(i) 2/5 of 40 = 40 x (2/5) = 80/5 = 16
(ii) 5/9 of 48 = 48 x (5/9) = (48 x 5)/9 = 240/9 = 80/3 = 26(2/3)

Simplify: (14/25) x (35/51) x (34/49)

We have:
(14/25) x (35/51) x (34/49)
= (14 x 35 x 34)/ (25 x 51 x 49)
After simplifying we get
4/15

Milk is sold at Rs. 16(3/4) per litre. Find the cost of 6(2/5) litres of milk. Cost of 1 litre of milk = Rs. 16(3/4) = Rs. 67/4

Cost of 6(2/5) litres of milk = Rs. (67/4) x (32/5)
= (67 x 32)/ (4 x 5) = 236/5 = Rs. 107(1/5)
Hence, the cost of 6(2/5) litres of milk is Rs. 107(1/5).



How do you multiply fractions with questions?

Steps for Multiplying Fractions:
(i) Multiply the top numbers (the numerators).
(ii) Multiply the bottom numbers (the denominators).
(iii) Simplify the fraction if needed.

Renu spends 4/5 of her income on household expenses. Her monthly income is Rs. 15000 . How much does she save every month?

Total monthly income = Rs. 15000
So, Monthly expenditure = 4/5 of Rs. 15000
= 15000 x (4/5) = 3000 x 4 = Rs. 12000
So, Monthly savings = Rs. (15000 – 12000) = Rs. 3000

What is important to know for multiplying fractions?

To multiply fractions, first we simplify the fractions if they are not in lowest terms. Then we multiply the numerators of the fractions to get the new numerator, and multiply the denominators of the fractions to get the new denominator. Simplify the resulting fraction if possible.

NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.3
NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.3 in pdf
NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.3 in english medium
7 Maths Exercise 2.3 solutions
7 Maths Exercise 2.3
7 Maths Exercise 2.3 solutions in pdf
7 Maths Exercise 2.3 solutions in hindi