# NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.3

NCERT Solutions for Class 7 Maths Chapter 2 Exercise 2.3 (Ex. 2.3) Fractions and Decimals in PDF file format free to use online or download to use it offline. All the solutions and videos are based on latest CBSE syllabus for academic session 2021-2022.

In class 7 math exercise 2.3 questions are given to practice the multiplication of fractions. Here we will learn the multiplication of fraction and daily life situation questions.## Class 7 Maths Chapter 2 Exercise 2.3 Solution

### CBSE NCERT Class 7 Maths Chapter 2 Exercise 2.3 Solution in Hindi and English Medium

Class: 7 | Mathematics |

Chapter: 2 | Fractions and Decimals |

Exercise: 2.3 | CBSE Book’s Solution |

### Class 7 Maths Chapter 2 Exercise 2.3 Solution in Videos

#### Subtraction of Fractions

Example:

Find the difference: (i) 7/9 – 5/9 (ii) 13/16 – 7/12

We have:

(i) 7/9 – 5/9 = (7 – 5)/9 = 2/9

(ii) 13/16 – 7/12

LCM of 16 and 12 is 48

So, (13 x 3 – 7 x 4)/48 = (39 – 28)/48 = 11/48

### Class 7 Maths Exercise 2.3 Practice Questions

##### Rekha bought 5(3/4) kg potatoes and 3(1/2) kg tomatoes from a vendor. What is the total weight of vegetables bought by her?

Total weight of vegetables bought by Rekha.

23/4 + 7/2 = (23 + 14)/4 = 37/4 kg = 9(1/4)

##### Find the product: (i) 5/8 x ¾ (ii) 3/4 x 5/2.

We have:

(i) 5/8 x ¾ = (5 x 3)/ (8 x 4) = 15/32

(ii) 3/4 x 5/2 = (3 x 5)/ (4 x 2) = 15/8

##### Multiply: (i) 7(5/8) by 3/2 (ii) 9(3/8) by 12

We have:

(i) 7(5/8) by 3/2 = 7(5/8) x 3/2 = 61/8 x 3/2 = (61 x 3)/ (8 x 2) = 183/16

(ii) 9(3/8) by 12 = {(9 x 8 + 3)/ 8} x 12 = 75/8 x 12 = (75 x 12)/ 8 = 225/2 = 112(1/2)

#### Multiplication of Fractions

Rule: Product of Fractions = (Product of their Numerators)/ (Product of their Denominators)

Thus, (a/b x c/d) = (a x c)/ (b x d)

##### Use of ‘OF’

We define:

a/b of c = c x (a/b)

Example:

(i) 2/5 of 40 (ii) 5/9 of 48

(i) 2/5 of 40 = 40 x (2/5) = 80/5 = 16

(ii) 5/9 of 48 = 48 x (5/9) = (48 x 5)/9 = 240/9 = 80/3 = 26(2/3)

### Class 7 Maths Exercise 2.3 Extra Questions

##### Simplify: (14/25) x (35/51) x (34/49)

We have:

(14/25) x (35/51) x (34/49)

= (14 x 35 x 34)/ (25 x 51 x 49)

After simplifying we get

4/15

##### Milk is sold at Rs. 16(3/4) per litre. Find the cost of 6(2/5) litres of milk. Cost of 1 litre of milk = Rs. 16(3/4) = Rs. 67/4

Cost of 6(2/5) litres of milk = Rs. (67/4) x (32/5)

= (67 x 32)/ (4 x 5) = 236/5 = Rs. 107(1/5)

Hence, the cost of 6(2/5) litres of milk is Rs. 107(1/5).

### Class 7 Maths Exercise 2.3 Important Questions

##### How do you multiply fractions with questions?

Steps for Multiplying Fractions:

(i) Multiply the top numbers (the numerators).

(ii) Multiply the bottom numbers (the denominators).

(iii) Simplify the fraction if needed.

##### Renu spends 4/5 of her income on household expenses. Her monthly income is Rs. 15000 . How much does she save every month?

Total monthly income = Rs. 15000

So, Monthly expenditure = 4/5 of Rs. 15000

= 15000 x (4/5) = 3000 x 4 = Rs. 12000

So, Monthly savings = Rs. (15000 – 12000) = Rs. 3000

##### What is important to know for multiplying fractions?

To multiply fractions, first we simplify the fractions if they are not in lowest terms. Then we multiply the numerators of the fractions to get the new numerator, and multiply the denominators of the fractions to get the new denominator. Simplify the resulting fraction if possible.