# NCERT Solutions for Class 7 Maths Chapter 2

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.1, Exercise 2.2, Exercise 2.3, Exercise 2.4, Exercise 2.5, Exercise 2.6 and Exercise 2.7 in English Medium and Hindi Medium for 2020-21.

Download Prashnavali 2.1, Prashnavali 2.2, Prashnavali 2.3, Prashnavali 2.4, Prashnavali 2.5, Prashnavali 2.6 and Prashnavali 2.7 in Hindi Medium free in PDF file format. You may use these solutions offline after downloading or study online without download. NCERT Solutions 2020-21 for all other subjects are also available to download in updated form according to new CBSE Books 2020-2021.

## NCERT Solutions for Class 7 Maths Chapter 2

 Class: 7 Subject: Maths – गणित Chapter 2: Fractions and Decimals

### 7 Maths Chapter 2 Solutions

7 Maths Chapter 2 Fractions and Decimals all exercises solutions are given below in Hindi and English Medium. You can download it without any login or password.

• ### 7 Maths Chapter 2 All Exercises in Hindi Medium

#### Class 7 Maths Chapter 2 Exercise 2.1 Solution in Video

Class 7 Maths Exercise 2.1 Question 1 Solution
Class 7 Maths Exercise 2.1 Question 2, 3, 4 Solution
Class 7 Maths Exercise 2.1 Question 5, 6, 7, 8 Solution
Class 7 Maths Chapter 2 Exercise 2.1 Solution

#### Class 7 Maths Chapter 2 Exercise 2.2 Solution in Video

Class 7 Maths Exercise 2.2 Question 1, 2, 3 Solution
Class 7 Maths Exercise 2.2 Question 4, 5, 6 Solution
Class 7 Maths Exercise 2.2 Question 7, 8 Solution
Class 7 Maths Chapter 2 Exercise 2.2 Solution

#### Class 7 Maths Chapter 2 Exercise 2.3 Solution in Video

Class 7 Maths Exercise 2.3 Question 1, 2 Solution
Class 7 Maths Exercise 2.3 Question 3, 4 Solution
Class 7 Maths Exercise 2.3 Question 5, 6, 7, 8 Solution
Class 7 Maths Chapter 2 Exercise 2.3 Solution

#### Class 7 Maths Chapter 2 Exercise 2.4 and 2.5 Solution in Video

Class 7 Maths Exercise 2.4 Question 1, 2 Solution
Class 7 Maths Exercise 2.4 Question 3, 4 Solution
Class 7 Maths Chapter 2 Exercise 2.4 Solution
Class 7 Maths Chapter 2 Exercise 2.5 Solution

Class 7 Maths Exercise 2.5 Question 1, 2 Solution
Class 7 Maths Exercise 2.5 Question 3, 4 Solution
Class 7 Maths Exercise 2.5 Question 5, 6, 7 Solution
Class 7 Maths Exercise 2.5 Question 8, 9 Solution

#### Class 7 Maths Chapter 2 Exercise 2.6 and 2.7 Solution in Video

Class 7 Maths Exercise 2.6 Question 1, 2, 3 Solution
Class 7 Maths Exercise 2.6 Question 4, 5 Solution
Class 7 Maths Chapter 2 Exercise 2.6 Solution
Class 7 Maths Chapter 2 Exercise 2.7 Solution

Class 7 Maths Exercise 2.7 Question 1 Solution
Class 7 Maths Exercise 2.7 Question 2, 3, 4 Solution

#### About NCERT Solutions for Class 7 Maths Chapter 2

In 7 Maths Chapter 2 Fractions and Decimals, we will learn how to convert a number into decimal and decimal into fraction. Normally we represent fraction in the following ways:
1. Proper Fraction: A proper fraction is a fraction that represents a part of a whole. In which the numerator is always smaller than the denominator.
2. Improper Fraction: An improper fraction is a combination of whole and a proper fraction.
Note: When two proper fractions are multiplied, the product is less than each of the fractions. Or, we say the value of the product of two proper fractions is smaller than each of the two fractions. Download Class 7 Maths App in English or कक्षा 7 गणित App in हिंदी मीडियम for offline use.

##### Class 7 Maths Try These

We also go through the multiplication of a number with fractions. To multiply a whole number with a proper or an improper fraction, we multiply the whole number with the numerator of the fraction, keeping the denominator same. But to multiply a mixed fraction to a whole number, first convert the mixed fraction to an improper fraction and then multiply.

Now the NCERT solutions for 2020-21 and answers of class 7 Maths are available in both the mode Online as well as Downloadable form for the convenience of students. The new updates is uploaded frequently based on latest NCERT Books 2020-2021.

### Important Questions on Class 7 Maths Chapter 2

Lipika reads a book for 1 and 3/4 hours everyday. She reads the entire book in 6 days. How many hours in all were required by her to read the book?
Time taken by Lipika to read a book = 1 and 3/4 hours.
She reads entire book in 6 days.
Now, hours taken by her to read the entire book = (1 and 3/4) x 6 = 7/4 x 6 = 21/2
Thus, 10 and 1/2 hours were required by her to read the book.
विद्या और प्रताप पिकनिक पर गए । उनकी माँ ने उन्हें 5 लीटर पानी वाली एक बोतल दी। विद्या ने कुल पानी का 2/5 उपयोग किया। शेष पानी प्रताप ने पिया। विद्या ने कितना पानी पिया?
दिया है:
बोतल में पानी की कुल मात्रा = 5 लीटर
विद्या द्वारा पानी का उपयोग = 5 लीटर का 2/5 = 2/5 x 5 = 2 लीटर
अतः, विद्या ने बोतल से 2 लीटर पानी पिया।
A car runs 16 km using 1 litre of petrol. How much distance will it cover using 2 and 3/4 litres of petrol?
In 1 litre of pertrol, car covers the distance = 16 km
In litres of petrol, car covers the distance = 2 and 3/4 of 16 km = 11/4 x 16 = 44 km
Thus, the car will cover 44 km distance.
Which is greater: 0.5 or 0.05
0.5 > 0.05
ज्ञात कीजिए: 0.2 x 6
0.2 x 6
= 1.2
एक आयत का क्षेत्रफल ज्ञात कीजिए जिसकी लम्बाई 5.7 cm और चौड़ाई 3 cm है।
दिया है: आयत की लम्बाई = 5.7 cm और
आयत की चौड़ाई = 3 cm
इसलिए, आयत का क्षेत्रफल
= लम्बाई x चौड़ाई
= 5.7 x 3
= 17.1 cm^2
अतः, इस आयत का क्षेत्रफल 17.1 cm^2 है।
एक दुपहिया वाहन एक लीटर पैट्रोल में 55.3 km की दूरी तय करता है। 10 लीटर पैट्रोल में वह कितनी दूरी तय करेगा?
एक लीटर में तय की गई दूरी = 55.3 km
10 लीटर में तय की गई दूरी
= 55.3 x 10
= 553.0 km
अतः, 10 लीटर पैट्रोल में वह 553.0 km दूरी तय करेगा।
Shyam bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?
Total weight of fruits bought by Shyam
= 5 kg 300 g + 3 kg 250 g
= 8 kg 550 g
Total weight of fruits bought by Sarala
= 4 kg 800 g + 4 kg 150 g
= 8 kg 950 g

On comparing the quantity of fruits,
8 kg 550 g < 8 kg 950 g Therefore, Sarala bought more fruits.

How much less is 28 km than 42.6 km?
We have to find the difference of 42.6 km and 28 km.
Difference
= 42.6 – 28.0
= 14.6 km
Therefore 14.6 km less is 28 km than 42.6 km.                                            