# NCERT Solutions for Class 7 Maths Chapter 6

NCERT Solutions for Class 7 Maths Chapter 6 Triangle and its Properties Exercise 6.1, Exercise 6.2, Exercise 6.3, Exercise 6.4 and Exercise 6.5 in English Medium which are updated for new academic session 2020-2021.

Download solutions of Prashanavali 6.1, Prashanavali 6.2, Prashanavali 6.3, Prashanavali 6.4 and Prashanavali 6.5 in Hindi Medium also updated for session 2020-21. All the solutions are according to NCERT Books 2020-2021. Videos related to each exercises are also given to understand easily. Download Offline Apps free for offline use.Page Contents

## NCERT Solutions for Class 7 Maths Chapter 6

Class: 7 | Maths (English and Hindi Medium) |

Chapter 6: | Triangle and its Properties |

### 7 Maths Chapter 6 Solutions

7 Maths all five exercises of Chapter 6 Triangle and its Properties solutions with complete description of each and every question are given below. For offline use, you may use Offline Apps for 2020-21.

### 7 Maths Chapter 6 All Exercises in English Medium

### 7 Maths Chapter 6 All Exercises in Hindi Medium

#### Class 7 Maths Chapter 6 Solution in Videos

#### Class 7 Maths Chapter 6 Exercise 6.5 Solution

#### About NCERT Solutions for Class 7 Maths Chapter 6

In 7 Maths Chapter 6 Triangle and its Properties, we will study about the various properties of a triangle. We know that a triangle is a simple closed curve made of three line segments. It has three vertices, three sides and three angles. It can be classified on the basis of sides and angles as follows:

1. Based on Sides: Scalene, Isosceles and Equilateral triangles.

2. Based on Angles: Acute-angled, Obtuse-angled and Right-angled triangles.

Read the following concepts before going through the chapter:

- Median of a triangle is a line segment drawn form vertex to the mid-point of opposite side. So, a triangle can have three medians drawn from three vertices.
- Altitude of a triangle is a perpendicular line drawn from vertex to opposite side. Like median, a triangle can have three altitudes drawn from three vertices.
- An exterior angle of a triangle is equal to the sum of its interior opposite angles.
- Angle sum property of Triangle: The sum of all the three interior angles of a triangle is 180°.

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### Important Questions on Class 7 Maths Chapter 6

Let QR be x cm.

In right angled triangle QPR,

(Hypotenuse)2 = (Base)2 + (Perpendicular)2

[By Pythagoras theorem]

(QR)2 = (PQ)2 + (PR)2

x^2 = 10^2 + 24^2

x^2 = 100 + 576 = 676

x = 26 cm

Thus, the length of QR is 26 cm.

2 + 3 > 5 संभव नहीं है

2 + 5 > 3 संभव है

3 + 5 > 2 संभव है

अतः, त्रिभुज संभव नहीं है।

Let BC be x cm.

In right angled triangle ACB,

(Hypotenuse)2 = (Base)2 + (Perpendicular)2 [By Pythagoras theorem]

(AB)^2 = (AC)^2 + (BC)^2

25^2 = 7^2 + x^2

625 = 49 + x^2

x^2 = 625 – 49 = 576

x = 24 cm

Thus, the length of BC is 24 cm.