NCERT Solutions for Class 7 Maths Chapter 11

Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.1, Exercise 11.2, Exercise 11.3 and Exercise 11.4 with step by step proper answers and solutions are given below. NCERT Solutions 2022-23 are updated for the new session 2022-23 based on new NCERT Books.

In 7 Maths Chapter 11 Perimeter and Area, we have to go through calculation of perimeters of some basic figures like triangular region, square and some other simple figures. Area of parallelogram, area of triangle and area of triangle as a part of a quadrilateral, etc. We must consider the fact that all the congruent triangles are equal in area but the triangles equal in area need not be congruent. As we know that the distance around a circular region is known as its circumference, so the perimeter of a circular region is normally refer as circumference. Important formulae related to areas are given below:
1. Perimeter of a square = 4 × side
2. Perimeter of a rectangle = 2 × (length + breadth)
3. Area of a square = side × side
4. Area of a rectangle = length × breadth
5. Area of a parallelogram = base × height
6. Area of a triangle = ½ (area of the parallelogram generated from it) = ½ × base × height
7. Circumference of a circle = πd, where d is the diameter of a circle
8. Area of a circle = πr², where r is the radius of the circle.
The value of π can be taken 22/7 or 3.14 (approximately). Use any value if the value of π is not mention in the question.

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