# NCERT Solutions for Class 7 Maths Chapter 11

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.1, Exercise 11.2, Exercise 11.3 and Exercise 11.4 in English Medium or Prashnavali 11.1, Prashnavali 11.2

2, Prashnavali 11.3 and Prashnavali 11.4 in Hindi Medium to study online or download in PDF file format. Latest NCERT Books for 2021-2022 and NCERT Solutions Offline Apps for the new academic session 2021-2022 are also available to free download without any registration.

## NCERT Solutions for Class 7 Maths Chapter 11

### Class 7 Maths Chapter 11 all Exercises Solution

 Class: 7 Maths (English and Hindi Medium) Chapter 11: Perimeter and Area

### 7 Maths Chapter 11 Solutions

Class 7 Maths Chapter 11 Perimeter and Area Exercise 11.1, Exercise 11.2, Exercise 11.3 and Exercise 11.4 with step by step proper answers and solutions are given below. NCERT Solutions 2021-22 are updated for the new session 2021-22 based on new NCERT Books.

• ### 7 Maths Chapter 11 All Exercises in Hindi Medium

#### Class 7 Maths Exercise 11.1 and Exercise 11.2 Solution in Video

Class 7 Maths Exercise 11.1 Solution in Video
Class 7 Maths Exercise 11.2 Solution in Video

#### Class 7 Maths Exercise 11.3 and Exercise 11.4 Solution in Video

Class 7 Maths Exercise 11.3 Solution in Video
Class 7 Maths Exercise 11.4 Solution in Video

#### About NCERT Solutions for Class 7 Maths Chapter 11

In 7 Maths Chapter 11 Perimeter and Area, we have to go through calculation of perimeters of some basic figures like triangular region, square and some other simple figures. Area of parallelogram, area of triangle and area of triangle as a part of a quadrilateral, etc. We must consider the fact that all the congruent triangles are equal in area but the triangles equal in area need not be congruent. As we know that the distance around a circular region is known as its circumference, so the perimeter of a circular region is normally refer as circumference. Important formulae related to areas are given below:
1. Perimeter of a square = 4 × side
2. Perimeter of a rectangle = 2 × (length + breadth)
3. Area of a square = side × side
4. Area of a rectangle = length × breadth
5. Area of a parallelogram = base × height
6. Area of a triangle = ½ (area of the parallelogram generated from it) = ½ × base × height
7. Circumference of a circle = πd, where d is the diameter of a circle
8. Area of a circle = πr², where r is the radius of the circle.
The value of π can be taken 22/7 or 3.14 (approximately). Use any value if the value of π is not mention in the question.

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### Important Questions on Class 7 Maths Chapter 11

##### The length and breadth of a rectangular piece of land are 500 m and 300 m respectively. Find its area.

Given: Length of a rectangular piece of land = 500 m and
Breadth of a rectangular piece of land = 300 m
Area of a rectangular piece of land
= Length x Breadth = 500 x 300 = 1,50,000 m²

##### Find the area of a square park whose perimeter is 320 m.

Given: Perimeter of square park = 320 m
4 x side = 320
side = 320/4 = 80 m
Now, Area of square park = side x side = 80 x 80 = 6400 m²
Thus, the area of square park is 6400 m².

##### Find the breadth of a rectangular plot of land, if its area is 440 m² and the length is 22 m. Also find its perimeter.

Area of rectangular park = 440 m²
length x breadth = 440 m²
breadth = 440/22 = 20 m
Now, Perimeter of rectangular park
= 2 (22 + 20) = 2 x 42 = 84 m
Thus, the perimeter of rectangular park is 84 m.

##### The perimeter of a rectangular sheet is 100 cm. If the length is 35 cm, find its breadth. Also find the area.

Perimeter of the rectangular sheet
= 100 cm
2 (length + breadth) = 100 cm
2 (35 + breadth) = 100
Now, Area of rectangular sheet
= 35 x 15 = 525 cm²
Thus, breadth and area of rectangular sheet are 15 cm and 525 cm² respectively.

##### The perimeter of a rectangle is 130 cm. If the breadth of the rectangle is 30 cm, find its length. Also, find the area of the rectangle.

Perimeter of rectangle = 130 cm
2 (length + breadth) = 130 cm
2 (length + 30) = 130
length + 30 = 130/2
length + 30 = 65
length = 65 – 30 = 35 cm
Now area of rectangle
= 35 x 30 = 1050 cm²
Thus, the area of rectangle is 1050 cm².                                  