Home › Forums › Yeshiva / School / College / Education Issues › 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 = ?
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October 4, 2012 1:39 am at 1:39 am #1125368gotbeerParticipant
Using PEMDAS the answer is 4…..here is how: 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 =
You would first do 1 x 0= and get 0.
Then you add the 1’s till the minus sign (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1) which is equal to 10.
Then you add what ever is left after the minus sign and get 6 (1 + 1 + 1 + 1 + 1 + 1).
Then you add the 0 to the 6 and you get 6.
Then you subtract 10 – 6=4……simple math !!!!!!
October 4, 2012 1:42 am at 1:42 am #1125369gotbeerParticipantBTW, I used a regular calculator and got 14. However, if you would use a scientific calculator, then I believe the answer will be 4.
October 4, 2012 5:46 am at 5:46 am #1125370haifagirlParticipantgotbeer: It doesn’t work like that. With no parentheses, you don’t subtract 6, you subtract 1. In PEDMAS you do the division and multiplication from left to right, then the addition and subtraction from left to right. You don’t put in parentheses that weren’t in the original problem.
October 4, 2012 6:18 am at 6:18 am #1125371Now that we’ve had over 50 comments discussing a fifthgrade math question entailing addition, subtraction and multiplication, perhaps we can move up a notch unto division:
Can we extend this for another 50 responses, debating this highly complex equation?
October 4, 2012 3:54 pm at 3:54 pm #1125372yeshivaguy45Participant48,651
October 4, 2012 4:04 pm at 4:04 pm #1125373I’m always amazed at the number of young Einsteins to be found on this board.
October 4, 2012 4:15 pm at 4:15 pm #1125374MeemaYehudisMemberYeshivaguy beat me to it. I agree. 48,651.
October 4, 2012 11:05 pm at 11:05 pm #1125376CuriosityParticipantHow about
? ?(1+4t^2) dt
?
October 4, 2012 11:40 pm at 11:40 pm #1125377Sam2ParticipantCuriosity: Where does a violin fit into a math problem? ðŸ˜›
October 5, 2012 12:54 am at 12:54 am #1125378ursketchingMemberYitB i think it’s time to say the answer. everyone is making a fool out of themselves.
October 5, 2012 4:27 am at 4:27 am #1125379CuriosityParticipantlol Sam2… that’s not a violin! That’s obviously a cello!!!
It’s actually called an indefinite integral.
October 5, 2012 4:45 am at 4:45 am #1125380Sam2ParticipantCuriosity: Not that it looks like a violin. All violins have the same greek letter to the sides of the strings at the bottom. I have no ideas if cellos do as well.
October 5, 2012 4:54 am at 4:54 am #1125381CuriosityParticipantThey do, and I think they’re called “Fholes”, if I remember correctly. But seriously though, major brownie points to whoever can solve the integral and show their work ðŸ™‚
October 5, 2012 6:06 am at 6:06 am #1125382WIYMembercuriosity
I am no big mathematician so I googled the problem and was easily able to get the answer which I wont post.
October 5, 2012 6:13 am at 6:13 am #1125383mattzerinoParticipantThere is a thing called precedence of operations in algebra. In the lack of any type of parenthesis, the order is division, mult, subtraction and addition. First, you mult. Then all the adding stuff. Should come out to 14, on a good day. Is this an advanced Beis Yaakov arithmetic test, or what?
October 5, 2012 6:20 am at 6:20 am #1125384CuriosityParticipantAre you sure you didn’t find the answer to
? 1/(?(1+4t^2)) dt
Or
? dt/(1+4t^2)
instead of
? ?(1+4t^2) dt
? : ) I couldn’t find that particular one on Google, but there are (lengthier) ways of solving it, and programs that calculate antiderivatives for you.
October 5, 2012 6:21 am at 6:21 am #1125385OneOfManyParticipantuhhh…something + C?
October 25, 2012 5:44 am at 5:44 am #1125386thelittlemercaitMember1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 x 0 = ?
Using PEMDAS, I started with 1 x 0. Automatically, that takes away that 1.
Then, all I did was just follow the line. Since I took the last 1 away, the problem looks like this:
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 = ?
I added 14 1’s and subtracted 1 as shown.
My answer is 13.
October 25, 2012 10:49 am at 10:49 am #1125387RG3MemberGo bck to school …whoops I mean college oh I forgot u didn’t go
October 25, 2012 1:10 pm at 1:10 pm #1125388â˜• DaasYochid â˜•ParticipantMy answer is 13.
You changed the question, so you got a different answer. The answer to the OP’s question is still 14.
If the question was “1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 x 0 = ?”, the answer would be 12.
October 25, 2012 5:48 pm at 5:48 pm #1125389OneOfManyParticipantNu, Curiosity – did I get it right? ^_^
July 6, 2013 9:40 pm at 9:40 pm #1125391sassy oneMember? dt/(1+4t^2) = tar[r]^1(t)
first answer ?(1+4t^(2)+2t)/2
July 8, 2013 12:11 am at 12:11 am #1125392wastingtimeMember=0 ppl r so bored
July 8, 2013 12:25 am at 12:25 am #1125393ubiquitinParticipantwastingtime Are you serious?
If so, wow just wow.
July 8, 2013 12:41 am at 12:41 am #1125394SecularFrummyMemberx = y.
Then x^2 = xy.
Subtract the same thing from both sides:
x^2 – y^2 = xy – y^2.
Dividing by (xy), obtain
x + y = y.
Since x = y, we see that
2 y = y.
Thus 2 = 1, since we started with y nonzero.
Subtracting 1 from both sides,
1 = 0.
July 9, 2013 12:33 pm at 12:33 pm #1125395TheMusicManParticipantI believe the correct answer is Swiss cheese.
Or South Dakota.
July 22, 2013 3:56 am at 3:56 am #1125396notoriouspreMemberThe correct answer is 4. 0x1= 0. Then there are 10 ones on the left of the subtraction sign. And 6 on the right side. Finally 10 minus 6 equals 4. Basic order of operations, and looking closely at the equation. You’re very welcome.
July 22, 2013 4:55 am at 4:55 am #1125397oomisParticipantAnything that is multiplied by zero, no matter how many digits it has = zero.
Unless there is a parentheses in there somewhere at the very end, in which case the answer would actually be a real number.
July 22, 2013 10:00 am at 10:00 am #1125398just my hapenceParticipantgotbeer and notoriouspre – BODMAS (or, as you seem to call it in America, PEDMAS) is a list of 4 operations, not 6: 1. Brackets, 2. Other (indices, surds etc), 3. Division AND Multiplication 4. Addition AND Subtraction. When faced with a problem like the one above, do ALL the multiplications and divisions first, from left to right (unless the division is expressed as a fraction in which case deal with the numerator and denominator separately), then ALL of the additions and subtractions from left to right, not all the additions first then all subtractions. So in this case, first do the 1×0 as you said but then you do not add all the 1’s to the left of the subtraction sign and subtract all the 1’s to the right of it from them but rather you add all the 1’s to the left then subtract the 1 immediately to the right of the subtraction sign and then carry on adding all the 1’s.
July 22, 2013 10:33 am at 10:33 am #1125399just my hapenceParticipantoomis – See above. Always do multiplications and divisions BEFORE additions and subtractions. So the only thing being multiplied by 0 here is the very last 1. You can add and subtract all the rest afterwards. Incidentally, 0 is also a real number.
July 22, 2013 1:54 pm at 1:54 pm #1125400whatdoiknow99Membercomputer programs give the answer 14
July 24, 2013 2:13 am at 2:13 am #1125401moishykMemberi got 14
July 24, 2013 7:49 am at 7:49 am #1125402moi aussiMemberZero
May 27, 2014 1:18 am at 1:18 am #1125403PulsingFlowerMemberI am ready to cry after having read through this thread.
May 27, 2014 3:22 am at 3:22 am #1125404oomisParticipantZero. Anything x 0 is always zero.
May 27, 2014 4:00 am at 4:00 am #1125405PulsingFlowerMemberITS THIRD GRADE MATH!!!!!! HAVE YOU HEARD OF PEMDAS??? THIS IS SO PITIFUL!!
May 27, 2014 4:20 am at 4:20 am #1125406DikDukDuckParticipant1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + (1 * 0) = 14
(1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1) * 0 = 0
May 27, 2014 9:55 pm at 9:55 pm #1125407frumnotyeshivishParticipantPulsingFlower I see it as ignorance. The concept isn’t difficult. The issue is that many people have never come across the concept in a way that they remember. This shows a lack of schooling (or an awful memory, which perhaps might be pitiful, but it doesn’t seem that you were thinking along those lines), and lack of any real life experiences that require simple math rules. Many people have no need for such knowledge and live complete lives without it. I don’t see inherent value in knowing simple math rules, thus I have no pity for those who were never exposed to them.
May 28, 2014 2:52 am at 2:52 am #1125408To be or not to beMemberI made the same mistake. my math woes are well documented on this site ( see one of the Lakewood matzav threads where boruch Schwartz absolutely schooled me on some simple math thingy). when I see a math example, my attention gets divided, my misery gets added, and my pleasure gets subtracted. I used to think algorithims are statements attributed to a former vice president and global warming alarmist. its not ignorance, just nerves I get nervous and cant think straight
May 28, 2014 3:38 am at 3:38 am #1125409PulsingFlowerMemberI used to think algorithims are statements attributed to a former vice president and global warming alarmist. its not ignorance, just nerves I get nervous and cant think straight
Actually, that is ignorance.
May 28, 2014 6:47 pm at 6:47 pm #1125410To be or not to beMemberactually that was a bad pun
May 28, 2014 8:23 pm at 8:23 pm #1125411gefenParticipantI got 16
May 28, 2014 8:59 pm at 8:59 pm #1125412âœ¡onegoalâ„¢Participant1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 = ?
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + (1 x 0) = ?
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + (0) = ?
10 – 6 + 0 = ?
10 – 6 + 0 = 4
July 11, 2014 4:20 am at 4:20 am #1125413frumnotyeshivishParticipantBump… For entertainment purposes. Anything times zero is zero, right?
July 11, 2014 6:14 am at 6:14 am #1125414arifreeParticipantYou are all wrong. The answer to everything is 42!
July 11, 2014 8:04 am at 8:04 am #1125415arifreeParticipantOK seriously…
Yes anything times zero is zero. And if you have pq=0 then you know either p is 0 or q is 0 or both.
Another way to think about multiplication is that you are making combinations. If I had 3 colors and 4 shapes then I have 3×4 = 12 combinations of colored shapes.
But if I had 5 shapes and no colors I would have zero combinations of ‘colored shapes’ since…there are no colors.
And that’s the nice thing about multiplication, because you can take say velocity and time, multiply them together, cancel the units and get the distance.
July 11, 2014 11:03 am at 11:03 am #1125416my own kind of jewParticipantThis is hilarious, in a sad sort of way
July 11, 2014 12:47 pm at 12:47 pm #1125417oomisParticipantIt depends on how you perceive the last two numbers listed. ANYTHING you add or subtract and then multiply by 0, will always be 0. Unless the last two numbers were bracketed together as [1+0], which would actually be 1, the 0 becomes the multiplier, thus ending in a solution of…0 in this problem.
July 11, 2014 5:59 pm at 5:59 pm #1125418arifreeParticipantoomis sorry you are wrong. We have to follow the rules. You said
“ANYTHING you add or subtract and then multiply”
No we multiply first and then add!
So 1 + 1 X 0 = 1 because we first evaluated the multiplication of 1 X 0 = 0
So we have 1 + 0 and that’s 1
July 11, 2014 6:35 pm at 6:35 pm #1125419ubiquitinParticipantOomis, the beauty of math is there is no such thing as “depends how you percieve it” there are strict rules as several posters have explained. following PEMDAS the answer is 14 ANY other response is simply wrong.

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