NCERT Solutions for Class 9 Science Chapter 9
NCERT Solutions for Class 9 Science Chapter 9 force and laws of motion updated for 2020-21. Download 9th Science chapter 9 Intext questions given on Page 118, Page 126, Exercises or Additional Exercises in English Medium. MP Board and UP Board students can download here UP Board Solutions in Hindi Medium. Hindi Medium solutions of Class 9 Science chapter 9 बल तथा गति के नियम के पेज 131 के उत्तर, पेज 140 के उत्तर, अभ्यास के प्रश्न उत्तर या अतिरिक्त अभ्यास के प्रश्न उत्तर are also available in PDF download or study online free.
NCERT Solutions 2020-21 for class 9 all subjects and Offline Apps based on these solutions of class 9 (ix) is given in Hindi and English Medium Download free.
NCERT Solutions for Class 9 Science Chapter 9
Class: | 9 |
Subject: | Science – विज्ञान |
Chapter 9: | Force and Laws of Motion |
9th Science Chapter 9 Answers in English & Hindi Medium
NCERT Solutions for Class 9 Science Chapter 9 force and laws of motion all Intext questions given with in the chapter and end exercise given at the end of the chapters are given below. Additional Exercises solutions and Class 9 Science offline apps 2020-21 in Hindi and English Medium are also given to download free.
Class 9 Science Chapter 9 Answers in English Medium
Class 9 Science Chapter 9 Answers in Hindi Medium
Class 9 Science Chapter 9 Answers in PDF Form
- Download 9th Science Page 118 Answers
- Download 9th Science Page 126-127 Answers
- 9th Science Chapter 9 Exercise Question Answers
- 9th Science Chapter 9 Additional Exercise Answers
- 9th Science Chapter 9 Study Material for 2020-21 in English
- 9th Science Chapter 9 Study Material for 2020-21 in Hindi
- Class 9 Science Solutions Main Page
Class 9 Science Chapter 9 Solutions Related Pages
A body of mass 1 kg is kept at rest. A constant force of 6∙0 N starts acting on it. Find the time taken by the body to move through a distance of 12 m.
2 seconds
A truck of mass 2500 kg moving at 15 m/s collides with a car of mass 1000 kg moving at 5 m/s in the opposite direction. With what velocity would the two move together?
9∙3 m/s in the direction of the truck.
A feather of mass 10 g is dropped from a height. It is found to fall down with a constant velocity. What is the net force acting on it?
Zero
A bullet of mass 20 gram moving with a velocity of 300 m/s gets embedded in a freely suspended wooden block of mass 880 gram. What is the velocity acquired by the bock?
6∙67 m/s
A machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. calculate the force required to keep the gun in position.
50 N
A motorcar is moving with a velocity of 108 km/h and it takes 4 second to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcar if the mass along with the passengers is 1000 kg.
-750 N
Questions for Practice on 9th Science Chapter 9
Question 1:
A girl of mass 40 kg jumps with a horizontal velocity of 5 m/s onto a stationery cart with friction-less wheels. The mass of the cart is 3 kg. What is her velocity as the cart starts moving? Assume that there is no external unbalanced force working in the horizontal direction.
Answer 1:
4∙65 m/s
Question 2:
According to the third law o motion, when we pushed on an object, the object pushes back on us with an equal and opposite force. If the object is a massive truck parked along the roadside, it will probably not move. A student justifies this by answering that the two opposite and equal forces cancel each other. Comment on this logic and explain why the truck does not move.
Answer 2:
When we push a massive truck parked along the roadside, it does not move. The justification given by the student that the two forces and equal forces cancel each other is totally wrong. This is because forces of action and reaction never act on one body. There is no question of their cancellation. The truck does not move because the push applied is far less than the force of friction between the truck and the road. We also do not move because the force of reaction acting on us (due to our pushing the truck) is less than force of friction between us and the road.
Question 3:
A constant force acts on an object of mass 5 kg for a duration of 2 s. It increases the object’s velocity from 3 m/s to 7 m/s. Find the magnitude of the applied force. Now if the force were applied for the duration of 5 s, what would be the final velocity of the object.
Answer 3:
10 n ; 13 m/s
Important Questions on 9th Science Chapter 9
(a) पत्थर का जड़त्व अधिक होगा।
(b) एक रेलगाड़ी का जड़त्व अधिक होगा।
(b) पाँच रुपये के एक सिक्के का जड़त्व अधिक होगा।