To prove that the perpendicular at the point of contact to the tangent of a circle passes through the center:
Tangent and Radius Perpendicularity: By definition, a tangent to a circle is a line that touches the circle at exactly one point, and at this point of contact, the tangent is perpendicular to the radius of the circle.
Constructing the Perpendicular: If we draw a perpendicular line to the tangent at the point of contact, this line must align with the radius, as there is only one unique perpendicular at a point on a line.
Radius Leads to Center: Since the radius of a circle extends from the center to any point on the circle, this perpendicular line (which aligns with the radius) must pass through the center of the circle.
Therefore, the perpendicular at the point of contact to the tangent of a circle necessarily passes through the center of the circle. This conclusion is based on the unique perpendicular relationship between a radius and a tangent at the point of contact.

Prove that the perpendicular at the point of contact to the tangent to a circle passes through centre.

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Introduction to Circle Geometry and Tangents

In the realm of geometry, the study of circles and their properties offers a fascinating exploration of shapes and lines. One intriguing aspect of circle geometry is the relationship between a tangent and the circle it touches. A fundamental property in this area is that the line perpendicular to the tangent at the point of contact passes through the circle’s center. This principle is not only fundamental in understanding circle geometry but also forms the basis for various geometric constructions and proofs.

Understanding the Tangent to a Circle

A tangent to a circle is a line that touches the circle at exactly one point, known as the point of tangency. Unlike a secant, which intersects the circle at two points, a tangent only meets the circle at one point and does not cross into the circle’s interior. This unique property of tangents is key to many geometric proofs and is particularly central to the theorem that the perpendicular at the point of contact to the tangent passes through the circle’s center.

The Perpendicularity of the Radius

A crucial property of tangents in relation to circles is that at the point of tangency, the tangent is perpendicular to the radius of the circle. This means that if a radius is drawn from the center of the circle to the point of tangency, it forms a right angle (90 degrees) with the tangent line. This perpendicular relationship is a defining characteristic of tangents to circles and is essential for understanding their geometric properties.

Constructing the Perpendicular to the Tangent
To prove our theorem, we start by constructing a perpendicular line to the tangent at its point of contact with the circle. According to geometric principles, there can only be one unique line perpendicular to another at a given point. In this case, the constructed perpendicular line at the point of tangency must align with the radius of the circle, as it is the only line that satisfies the condition of being perpendicular to the tangent at that point.

The Radius as the Path to the Center

Since the radius of a circle extends from the center to any point on the circle’s circumference, the alignment of the constructed perpendicular with the radius implies that this line must pass through the center of the circle. This is because the radius, by definition, connects the center with the circumference. Therefore, the perpendicular line we have constructed, which coincides with the radius, must also pass through the circle’s center.

Perpendicularity and Circle Geometry

Thus, we conclude that the perpendicular at the point of contact to the tangent of a circle passes through the center of the circle. This conclusion elegantly demonstrates the interplay of basic geometric principles and the coherence of circle geometry. It highlights the unique relationship between a circle, its radius, and a tangent line, showcasing the simplicity and beauty inherent in geometric reasoning. This theorem is a fundamental aspect of circle geometry and is pivotal in various geometric constructions and applications.

Discuss this question in detail or visit to Class 10 Maths Chapter 10 for all questions.
Questions of 10th Maths Exercise 10.2 in Detail

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is (A) 7 cm (B) 12 cm (C) 15 cm (D) 24.5 cm
If TP and TQ are the two tangents to a circle with centre O so that ∠POQ = 110°, then ∠PTQ is equal to (A) 60° (B) 70° (C) 80° (D) 90°
If tangents PA and PB from a point P to a circle with centre O are inclined to each other at angle of 80°, then ∠POA is equal to (A) 50° (B) 60° (C) 70° (D) 80°
Prove that the tangents drawn at the ends of a diameter of a circle are parallel.
Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.
The length of a tangent from a point A at distance 5 cm from the centre of the circle is 4 cm. Find the radius of the circle.
Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.
A quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB + CD = AD + BC.
If XY and X’Y’ are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and X’Y’ at B. Prove that ∠AOB = 90°.
Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre.
Prove that the parallelogram circumscribing a circle is a rhombus.
A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC into which BC is divided by the point of contact D are of lengths 8 cm and 6 cm respectively. Find the sides AB and AC.
Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.