# NCERT Solutions for Class 11 Maths Chapter 3 Supplementary Exercise 3.5

NCERT Solutions for Class 11 Maths Chapter 3 Supplementary Exercise 3.5 of Trigonometric Functions in Hindi and English Medium for the students using NCERT Books 2021-22 are given below for session 2021-22.

English Medium NCERT Solutions 2021-22 are also given for those who are using Textbooks in English Medium. NCERT Solutions and Offline Apps are in updated format based on latest CBSE Syllabus 2021-22 for all the boards (CBSE, UP Board, MP Board, Bihar, Gujrat and others) who are using NCERT Books 2021-2022.## NCERT Solutions for Class 11 Maths Chapter 3 Supplementary Exercise 3.5

Class: 11 | Maths (English and Hindi Medium) |

Chapter 3: | Supplementary Exercise 3.5 |

### Class 11 Maths Chapter 3 Supplementary Exercise 3.5 Sols

NCERT Solutions for Class 11 Maths Chapter 3 Exercise 3.5 Supplementary Exercise of Trigonometric Functions in English & Hindi Medium are given below updated for new academic session 2021-22. It is an important one as per examination point of view.

After doing all the main exercises, students must do this as it is based on sine and cosine rule which is important for further classes. Visit to NCERT Solutions for Class 11 Maths Chapter 3 main page to see the solutions of other exercises. All the questions of this exercise are based on sine and cosine formulae.

#### Class 11 Maths Supplementary Exercise 3.5 Solution in Videos

#### Class 11 Maths Exercise 3.5 Solution in Hindi

What is Cosine formula?

Cosine formula: The cosine of an angle A of any triangle ABC, whose sides are a (opposite to BC), b (opposite to AC) and c (opposite to AB) is given by cos A = [b² + c² – a²]/2bc.

#### About 11 Maths Exercise 3.5 Supplementary

In Chapter 3 Exercise 3.5, mainly the sine formula and cosine formula are introduced. The questions are given on the basis of these formula only. Some of the problems required both the formulae simultaneously.

Sine Formula: In any triangle, the sides of triangle are proportional to the sine of angles opposite to the sides.

i.e. (sin A)/a = (sin B)/b = (sin C)/c = k, where k is a constant.

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