# NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.4

NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.4 Triangles in PDF format free to download in Hindi Medium as well as in English Medium for the students who are following latest NCERT Books 2020-2021.

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## NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.4

Class: 10 | Maths (English and Hindi Medium) |

Chapter 6: | Exercise 6.4 |

### 10 Maths Chapter 6 Exercise 6.4 Solutions

NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.4 Triangles in English medium as well as Hindi Medium free to use online or download in PDF updated for academic session 2020-21 for High School students. Move Class 10 Maths Chapter 6 main page for other exercises to download or online study. Join the Discussion Forum to ask your doubts and response to other’s questions. Vedic Maths is important tools for class 10 students to make calculation easier and faster.

#### Class 10 Maths Chapter 6 Exercise 6.4 Solution in Hindi Medium

#### Class 10 Maths Chapter 6 Exercise 6.4 Solution in Videos

##### What is Area Theorem in class 10?

The ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding sides. [This also known as Area Theorem. In this theorem, the ratio of area is equal to square of corresponding sides but ratio is also equal to the corresponding altitudes, median.]

##### How many theorems are there in chapter 6, which may be asked to prove?

There are four theorems in class 6 which are asked to prove:

1. BPT or Thales Theorem

2. Area Theorem

3. Pythagoras Theorem

4. Converse of Pythagoras Theorem

#### About 10 Maths Exercise 6.4

In Exercise 6.4, mainly we have to solve the questions based on ratio of area of similar triangles with their corresponding sides, perimeters, altitudes, medians, etc. In Exercise 6.3, we have learnt that if triangles are similar then their sides are proportional. Here, we have to relate it from area also.

##### Extra Questions on Similar Triangles

In triangle ABC, If AD is the median, Show that AB² + AC² = 2(AD² + BD²)

In triangle ABC, angle C is a right angle. Points P & Q lies on the sides CA & CB respectively. Prove that AQ² + BP² = AB² + PQ²

If AD and PS are medians of angle ABC and angle PQR respectively where angle ABC ~ angle PQR, Prove that AB/PQ = AD/PS.

In an equilateral angle ABC, AD is perpendicular to BC, Prove that 3AB² = 4AD².

Prove that the sum of the square of the sides of a rhombus is equal to the sum of the squares of its diagonals.