NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.6

NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.6 (Optional Exercise)* Triangles PDF in Hindi Medium as well as in English Medium updated for new academic session 2020-2021 based on latest NCERT Books 2020-21.

NCERT Solutions are available in in Video Format for all the students of CBSE, MP Board, UP Board High School and other boards using CBSE NCERT Solutions and NCERT Books as a course books.

NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.6

Class: 10Maths (English and Hindi Medium)
Chapter 6:Exercise 6.6

10 Maths Chapter 6 Exercise 6.6 Solutions

NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.6 Optional Exercise or Triangles in English Medium downloadable PDF format updated for 2020-21. Questions containing Exercise 6.6 are also asked in examinations as HOTS. Vedic Maths is important tool for mathematical calculations and to make Maths more easier.




Class 10 Maths Exercise 6.6 Solution in Hindi Medium Video

Class 10 Maths Chapter 6 Exercise 6.6 Solution in Videos

Class 10 Maths Exercise 6.6 Question wise Solution
Class 10 Maths Chapter 6 Exercise 6.6 Solution

About 10 Maths Optional Exercise 6.6

In Exercise 6.6 (Optional), the questions are based on contents of almost all exercises of Similar Triangles. These questions are based on Higher Order Thinking Skills (HOTS) but still asked in CBSE Exams. Questions of Exercise 6.5 and Exercise 6.4 are help full in solving these questions.



EXTRA QUESTIONS ON SIMILAR TRIANGLES

1. Two poles of height a metres and b metres are p metres apart. Prove that the height of the point of intersection of the lines joining the top of each pole to the foot of the opposite pole is gives by ab/(a + b) metres.
2. In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC. Prove that 9AD² = 7AB².
3. In a trapezium ABCD, AB || DC and DC = 2AB. If EF is drawn parallel to AB cuts AD in F and BC in E such that BE/BC = ¾. Diagonals DB intersects EF at G. Prove that 7 EF = 10 AB.
4. In triangle PQR, PD is perpendicular to QR such that D lies on QR. If PQ = a, PR = b, QD = c and DR = d and a, b, c, d are positive units. Prove that (a + b) (a – b) = (c + d) (c – d).
5. Prove that the ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.



Download NCERT Books and Offline Apps 2020-21 based on new CBSE Syllabus. Ask your doubts related to NIOS or CBSE Board and share your knowledge with your friends and other users through Discussion Forum.

NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.6 triangles optional exercise
NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.6 in English medium PDF
NCERT Solutions for Class 10 Maths Chapter 6 Exercise 6.6 updated for 2018-19
10 Maths Optional exercise 6.6 Triangles
10 Maths Optional exercise 6.6 Triangles free in PDF for cbse and up board
10 Maths Optional exercise 6.6 Triangles in Hindi Medium
10 Maths chapter 6 Optional Exercise 6.6 solutions in Hindi Medium
10 Maths chapter 6 Optional Exercise 6.6 solutions for CBSE and UP Board high schools
10 Maths chapter 6 Optional Exercise 6.6 solutions updated for 2018-19 ncert
10 Maths chapter 6 Optional Exercise 6.6 solutions full in Hindi medium
10 Maths chapter 6 Optional Exercise 6.6 sols free