NCERT Solutions for Class 10 Science Chapter 6
NCERT Solutions for Class 10 Science Chapter 6 Life Processes all intext question answers given on Page 95 or Page 101 or Page 105 or Page 110 or Page 112 or Exercises in English Medium updated for 2020-2021.NCERT Solutions given on inside the chapter on पेज 105 के उत्तर or पेज 111 के उत्तर or पेज 116 के उत्तर or पेज 122 के उत्तर or पेज 124 के उत्तर or अभ्यास के प्रश्न उत्तर in हिंदी मीडियम free to study online or download in PDF file format. UP Board Solutions and NCERT Solutions 2020-21 or Solutions Apps for class 10 all subjects are also given.
- 1 10th Science Chapter 6 Answers in English Medium
- 2 10th Science Chapter 6 Answers in Hindi Medium
- 3 10th Science Chapter 6 Answers in PDF Form
- 4 Class 10 Science Chapter 6 Solutions Related Pages
- 4.0.1 Some finger like projection are present in the inner wall of small intestine. Write their name. Why are they important?
- 4.0.2 Which is the internal energy reserve in plants? Do the animals have the same energy reserve? Justify your answer.
- 4.0.3 What are nutrients?
- 4.0.4 Explain the structure of stomata. Write functions of guard cells.
- 4.0.5 Write major functions of stomata present in the epidermis.
- 4.0.6 Stomata remains closed during the day in desert plants. How they get carbon dioxide for photosynthesis?
- 4.0.7 Explain parasitic mode of nutrition with two examples.
- 4.0.8 How does nutrition takes place in Paramoecium?
- 4.0.9 What is emulsification?
- 5 Important Questions on 10th Science Chapter 6
NCERT Solutions for Class 10 Science Chapter 6
|Subject:||Science – Biology|
|Chapter 6:||Life Processes|
10th Science Chapter 6 Answers in English & Hindi Medium
NCERT Solutions for 10 Science Chapter 6 question answers which are given inside the book and at the end of chapters are given below. All the solutions are free to use and updated for new academic session 2020-21. NCERT Solutions Offline Apps for class 10 Science in Hindi and English Medium based on latest CBSE Syllabus 2020-21 are available to free download.
10th Science Chapter 6 Answers in English Medium
10th Science Chapter 6 Answers in Hindi Medium
10th Science Chapter 6 Answers in PDF Form
- 10th Science Page 95 Answers in PDF
- 10th Science Page 101 Answers in PDF
- 10th Science Page 105 Answers in PDF
- 10th Science Page 110 Answers in PDF
- 10th Science Page 112 Answers in PDF
- 10th Science Chapter 6 Exercises in PDF
- 10th Science Chapter 6 Study Material in English
- 10th Science Chapter 6 Study Material in Hindi
- 10th Science Notes on Chapter 6
- Class 10 Science Main Page
Some finger like projection are present in the inner wall of small intestine. Write their name. Why are they important?
The fingers-like structure present on the inner surface of the small intestine are called Villi. About five millions of villi are present in the intestines, thus they increase the absorptive surface of the intestine considerably and facilitate quick absorption of the digested food. Each villi contains a network of blood capillaries with a central lacteal vessel (lymph vessel).
Which is the internal energy reserve in plants? Do the animals have the same energy reserve? Justify your answer.
Carbohydrates are utilized for providing energy to the plants and are stored in the form of starch, which serves as the internal energy reserve to be used as and when required by the plant. In animals, carbohydrates are reserved in the form of glycogen, as internal energy reserve. The carbohydrates like starch (in plants) and glycogen (in animals) serve as the internal energy reserve because they are polymer of glucose and their hydrolysis provide glucose molecules to provide energy at the time of need.
What are nutrients?
Nutrients are substances which an organism obtains from its surroundings and uses it either as an energy source or source of material required for growth and maintenance of the body.
Explain the structure of stomata. Write functions of guard cells.
i). The outermost layer of cell i.e., usually the epidermis is not continuous at some place e.g., on the surface of leaves or green herbaceous stems. The epidermis of the young shoot and leaves contains numerous minute pores called stomata. Each stomata opening is surrounded by two semilunar cells known as the guard cells. The term ‘stomata’ (plural – stomata) is applied to the stomatal opening plus the guard cells. The guard cells are living and contains chloroplast. Their inner walls (wall towards opening) are thicker and outer walls thinner.
ii). Function of guard cells: the guard cells regulate the opening and closing of the stomatal pore. The guard cells swell when water flows into them causing the stomatal pore to open. Because inflow of water in guard cells causes the stretching and bulging of outer thin walls in converse shape. This drags thick walls apart leading to opening of the pore. When there is outflow of water from guard cells, the outer thin walls come to their original position resulting in closure of stomatal pore.
Write major functions of stomata present in the epidermis.
Major functions of stomata are:
1. Stomata are essential for exchange of gases between the plants and the atmosphere-Oxygen and carbon dioxide.
2. Normally, plants eliminate excessive water in the form of vapour through stomatal openings. The process is called transpiration.
3. When there is shortage of water, stomatal openings get closed. Thus, reduce water lose. Stomatal opening also close down during night. Thus, stomata regulate water lose from plants i.e., they regulate transpiration.
Stomata remains closed during the day in desert plants. How they get carbon dioxide for photosynthesis?
In desert, temperature is very high so stomata are closed to reduce the loss of water due to transpiration. Therefore, desert plants are adapted to take up carbon dioxide at night when stomata are open. This CO2, taken up in night, prepare an intermediate compound. This intermediate compound is acted upon by the energy absorbed by the chlorophyll during the day to prepare food
Explain parasitic mode of nutrition with two examples.
Parasitic mode of nutrition: Some organisms derive their nutrition from other plants or animals (hosts). This is known as parasitic mode of nutrition and such organisms are called parasites. Some parasites are ectoparasite. They lived outside of the body of the host and derive their nutrition, the host such as cuscuta, leech, blood sucking mosquitoes etc. are ectoparasite. Some parasites live in the body of the host called endoparasites. For example: tapeworm, some fungi, etc.
How does nutrition takes place in Paramoecium?
Paramoecium is unicellular animal which has a definite shape (slipper – like).
Paramoecium takes in food at a specific point (through oral groove to mouth to gullet). Food such as bacteria or very small organisms are moved to the specific spot (ingestion point) by the movement of cilia which are present all over the single-celled body.
From the gullet a food vacuole is formed which starts circulating in the endoplasm. During circulation food is digested by enzymes. The digested food diffuses into the cytoplasm and undigested food is thrown out through the pore.
What is emulsification?
Emulsification means a fine dispersion of one liquid in another. In reference to digestion of food, breakdown of large fat globules in the small intestine by the bile juice from liver into fine smaller fat globules so to increase the efficiency of enzyme action, is called emulsification.
Questions for Practice
“The breathing cycle is rhythemic whereas exchange of gases is a continuous process” Justify the statement. Differentiate between Inhalation and Exhalation.
The blood brings CO2 form the body parts to be released into the alveoli, and the oxygen in the alveolar cavity is taken up in the alveolar blood vessels to be transported to all the cells in the body. This forms the breathing cycle (taking in air and given out air) is rhythmic. But during breathing cycle, when air is taken in and let out. The lungs always contain a residual volume of air. So that there is sufficient time for oxygen to be absorbed and for the carbon dioxide to be released. Thus, there is some gap in between inspiration (taking in air) and expiration (given out air) during breathing cycle but exchange of gases continuous.
What are the basic materials used during photosynthesis? Write chemical equation for photosynthesis.
Materials used in photosynthesis are (a) Carbon Dioxide and (b) Water. Chemical equation of photosynthesis.
Questions from Board Papers
Explain the process of nutrition in amoeba with the help of diagrams.
Engulfing of Food: Amoeba obtains food by phagocytosis (a type of holozoic nutrition). Amoeba engulfs the food by forming pseudopodia.
1. Two pseudopodia start growing from opposite sides of food particle. They completely encircle the food and their lips touch each other.
2. The membranes of both the pseudopodia dissolve at the point of touching and the food is encaptured into the Amoeba (one cell body) in a bag known as food vacuole.
3. Digestion of food: Inside the food vacuole, complex substances of the food are broken down into simpler ones. The digested simple substances diffuse from food vacuole into cytoplasm.
4. The remaining undigested material is moved near the surface of the single-celled body of amoeba and thrown out.
Example of other unicellular organisms are Paramoecium and Euglena. Pseudopodia also help amoeba in locomotion.
a) Where are salivary glands located in human beings?
b) Name the enzyme found in saliva. State the role of saliva in the digestion of food.
Salivary glands secrete their secretion called saliva in the mouth cavity. There are three pairs of salivary glands located in the mouth. Saliva Amylase enzyme.
Role Or Function of saliva:
1. Saliva moisten the food thus help in chewing of food by the teeth.
2. Human saliva contains an enzyme called salivary amylase that converts starch into maltose (a sugar).
3. Saliva also helps in swolling and passage of food chewed food through the food canal which has soft lining.
Important Questions on 10th Science Chapter 6
Kills germs present in the food and makes the food acidic, so that pepsin can digest protein.
Thus, it is necessary for them to separate oxygenated and de-oxygenated blood, so that their circulatory system is more efficient and can maintain their constant body temperature.