NCERT Solutions for Class 8 Maths Chapter 16
NCERT Solutions for Class 8 Maths Chapter 16 PLAYING WITH NUMBERS Exercise 16.1 and Exercise 16.2 in English as well as Hindi Medium in PDF form to free download updated for new academic session 2020-2021.
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- 1 8 Maths Chapter 16 Solutions in English Medium
- 2 8 Maths Chapter 16 Solutions in Hindi Medium
- 2.0.1 If 21y5 is a multiple of 9, where y is a digit, what is the value of y?
- 2.0.2 If 31z5 is a multiple of 9, where z is a digit, what is the value of z?
- 2.0.3 यदि 24x, 3 का एक गुणज है, जहाँ x एक अंक है, x तो का मान क्या है?
- 2.0.4 यदि 31z5, 3 का एक गुणज है, जहाँ z एक अंक है, z तो का मान क्या हो सकता है?
NCERT Solutions for Class 8 Maths Chapter 16
| Class: | 8 |
| Subject: | Maths – गणित |
| Chapter 16: | Playing with Numbers |
Class 8 Maths Chapter 16 Solutions
Class 8 Maths Chapter 16 Playing with Numbers all exercises in English Medium and Hindi Medium are given below to use online or download in PDF form. For any inconvenience regarding website, please call us, we will immediately solve the problem. Offline Apps 2020-21 are in updated format to use offline without internet.
8 Maths Chapter 16 Solutions in English Medium
8 Maths Chapter 16 Solutions in Hindi Medium
Class 8 Maths Exercise 16.1 & 16.2 Solutions in Video
Important Terms about Class 8 Maths Chapter 16
If 21y5 is a multiple of 9, where y is a digit, what is the value of y?
Since 21y5 is a multiple of 9.
Therefore according to the divisibility rule of 9, the sum of all the digits should be a multiple of 9.
So, 2 + 1 + y + 5 = 8 + y
Now 8 + y = 9
Hence, y = 1
If 31z5 is a multiple of 9, where z is a digit, what is the value of z?
Since 31z5 is a multiple of 9.
Therefore according to the divisibility rule of 9, the sum of all the digits should be a multiple of 9.
So, 3 + 1 + z + 5 = 9 + z should be divisible by 9.
If 9 + z = 9, then z = 0.
If 9 + z = 18, then z = 9.
Hence, 0 and 9 are two possible answers.
यदि 24x, 3 का एक गुणज है, जहाँ x एक अंक है, x तो का मान क्या है?
क्योंकि , 24x, 3 का एक गुणज है,
इसलिए, इसके अंकों का योग 3 से विभाज्य होना चाहिए।
अंकों का योग = 2 + 4 + x = 6 + x
यदि, 6 + x = 6 तो x = 0.
यदि, 6 + x = 9 तो x = 3.
यदि, 6 + x = 12 तो x = 6.
यदि, 6 + x = 15 तो x = 9.
अतः, x के चार मान 0, 3, 6 और 9 हो सकते हैं।
यदि 31z5, 3 का एक गुणज है, जहाँ z एक अंक है, z तो का मान क्या हो सकता है?
क्योंकि 31z5, 3 का एक गुणज है,
इसलिए, इसके अंकों का योग 3 से विभाज्य होना चाहिए।
क्योंकि z एक अंक है, इसलिए, इसके अंकों का योग = 3 + 1 + z + 5 = 9 + z
यदि, 9 + z = 9 तो z = 0.
यदि, 9 + z = 12 तो z = 3.
यदि, 9 + z = 15 तो z = 6.
यदि, 9 + z = 18 तो z = 9.
अतः, z के चार मान 0, 3, 6 और 9 हो सकते हैं।
In Chapter 16 Playing with Numbers, we will study about the Numbers in usual form as well as general form or expanded form. This chapter also tells us the divisibility tests of 2, 3, 5, 9 and 11. A number is divisible by 2 or 3 or any other number, that can be determined only by oral calculation not by actual division. In the last exercise, few a questions are given as tricky one on the basis of divisibility test. Divisibility tests are important tools in Vedic Maths also to simplify the questions.
विभाज्यता की जाँच
२ से विभाज्यता की जाँच करते समय हम केवल इकाई के अंक को ही जांचते हैं कि वह २ से विभाज्य है की नहीं। इसी प्रकार यदि किसी संख्या के अंत में शून्य है तो वह १० से विभाज्य होगी और यदि अंत में ५ है तो वह ५ से विभाज्य है। ३ तथा ९ से विभाज्यता की जाँच के लिए, सभी अंकों का योग ज्ञात करना पड़ता है और जाँच करते हैं कि योग ३ अथवा ९ से विभाज्य है कि नहीं।
